cho \(\frac{y}{x-z}=\frac{x+y}{z}=\frac{x}{y}\) Tính \(\frac{x}{y}\)
cho \(\frac{a+b-c}{c}=\frac{a-b+c}{b}=\frac{-a+b+c}{a}\) tính \(M=\frac{\left(a+b\right).\left(a+c\right).\left(b+c\right)}{a.b.c}\)
Tìm x \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)