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tìm x
(x + 1) mũ 3 = 125
2 mũ x + 2 mũ x +3 ( số 3 là số mũ) =576
\(\left(x+1\right)^3=125\)
\(\left(x+1\right)^3=\sqrt[3]{125}\)
\(\left(x+1\right)=5\)
\(x=5-1\)
\(x=4\)
\(2^x+2^{x+3}=576\)
\(2^x\left(1+2^3\right)=576\)
\(2^x=576:9\)
\(2^x=64\)
\(2^x=2^6\)
\(\Rightarrow x=6\)
\(\Rightarrow2^x+2^x.2^3=24^2\)
\(\Rightarrow2^x\left(1+2^3\right)=24^2\)
\(\Rightarrow2^x+3^2=24^2\)
\(\Rightarrow2^x=\left(24:3\right)^2\)
\(\Rightarrow2^x=8^2\)
\(\Rightarrow2^x=\left(2^3\right)^2\)
\(\Rightarrow2^x=2^6\)
\(\left(x+1\right)^3=125\)
\(\left(x+1\right)^3=\sqrt[3]{125}\)
\(\left(x+1\right)=5\)
\(x=5-1\)
\(x=4\)
\(2^x+2^{x+3}=576\)
\(2^x\left(1+2^3\right)=576\)
\(2^x=576:9\)
\(2^x=64\)
\(2^x=2^6\)
\(\Rightarrow x=6\)
\(2^x+2^{x+3}=576\)
\(\Rightarrow2^x+2^x.2^3=24^2\)
\(\Rightarrow2^x\left(1+2^3\right)=24^2\)
\(\Rightarrow2^x+3^2=24^2\)
\(\Rightarrow2^x=\left(24:3\right)^2\)
\(\Rightarrow2^x=8^2\)
\(\Rightarrow2^x=\left(2^3\right)^2\)
\(\Rightarrow2^x=2^6\)
\(\Rightarrow x=6\)