Tính
a) 1+1/3+1/9+1/27+1/81=.......................................
=
b)37,52+4,7*2.3-9,8=................................
=
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A = \(1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)
A = \(\frac{81}{81}+\frac{27}{81}+\frac{9}{81}+\frac{3}{81}+\frac{1}{81}\)
A = \(\frac{81+27+9+3+1}{81}\)
A = \(\frac{121}{81}\)
\(1,\)
\(a,1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)
\(=\frac{81}{81}+\frac{27}{81}+\frac{9}{81}+\frac{3}{81}+\frac{1}{81}\)
\(=\frac{81+27+9+3+1}{81}\)
\(=\frac{121}{81}\)
\(=1\frac{40}{81}\)
\(b,37,25+4,7.2,3-9,8\)
\(=37,25+10,81-9,8\)
\(=38,26\)
\(2,\)
\(a,x:4,37=5,6\left(dư1,53\right)\)
\(x=5,6.4,37+1,53\)
\(\Rightarrow x=26,002\)
\(b,13,5.\left(x:5,6\right)=36,45\)
\(\left(x:5,6\right)=36,45:13,5\)
\(x:5,6=2,7\)
\(x=2,7.5,6\)
\(\Rightarrow x=15,12\)
a) Cho: \(A=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)
\(\Rightarrow3A=3+1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}\)
\(\Rightarrow3A-A=3-\frac{1}{81}\)
\(\Rightarrow A=\frac{3-\frac{1}{81}}{2}\)
\(A=\frac{121}{81}\)
b) \(37,52+4,7\times2,3-9,8\)
\(=37,52+10,81-9,8\)
\(=38,53\)
Chúc bn học tốt !!!!!
c)x:25/8-3/4=9/4
x:25/8=9/4+3/4
x:25/8=3
x=3 nhân 25/8
x=75/8
tất cả các bài có người làm rồi li-ke cho mình nha
a: \(log_2\dfrac{1}{16}=log_22^{-4}=-4\)
b: \(log_3243=log_33^5=5\)
c: \(9^{log_37}=7^{log_39}=7^2=49\)
c: \(\left(\dfrac{1}{81}\right)^{log_32}=\left(3^{-4}\right)^{log_32}=2^{log_33^{-4}}=2^{-4}=\dfrac{1}{16}\)
\(log_2\dfrac{1}{16}=-log_22^4=-4\)
\(log_3243=log_33^5=5\)
\(9^{log_37}=3^{2log_37}=3^{log_349}=49\)
\(\left(\dfrac{1}{81}\right)^{log_32}=3^{-4.log_32}=3^{log_32^{-4}}=2^{-4}=\dfrac{1}{16}\)
a: \(\left(\dfrac{3}{4}-81\right)\left(\dfrac{3^2}{5}-81\right)\cdot...\cdot\left(\dfrac{3^{2000}}{2003}-81\right)\)
\(=\left(\dfrac{3^6}{9}-81\right)\left(\dfrac{3}{4}-81\right)\cdot\left(\dfrac{3^2}{5}-81\right)\cdot...\cdot\left(\dfrac{3^{2000}}{2003}-81\right)\)
\(=\left(81-81\right)\left(\dfrac{3}{4}-81\right)\cdot\left(\dfrac{3^2}{5}-81\right)\cdot...\cdot\left(\dfrac{3^{2000}}{2003}-81\right)\)
=0
b: \(\dfrac{69}{157}-\left(2+\left(3+4+5^{-1}\right)^{-1}\right)^{-1}\)
\(=\dfrac{69}{157}-\left(2+\left(3+4+\dfrac{1}{5}\right)^{-1}\right)^{-1}\)
\(=\dfrac{69}{157}-\left(2+1:\dfrac{36}{5}\right)^{-1}\)
\(=\dfrac{69}{157}-\left(2+\dfrac{5}{36}\right)^{-1}\)
\(=\dfrac{69}{157}-\left(\dfrac{77}{36}\right)^{-1}\)
\(=\dfrac{69}{157}-\dfrac{36}{77}=\dfrac{-339}{12089}\)