a ) | x - 2| = 3
b) -3 | x + 1 | = 9
c) 3 | x - 1 | -5 = 7
d) -12 ( x - 5 ) + 7 ( 3 - x ) = 5
e) ( x - 2 ) . ( x + 15 ) = 0
f) (7 - x ) . ( x + 19 ) = 0
g) ( x - 3 ) (x - 5 ) < 0
h) -6x - (- 7 ) = 25
i) 46 - ( x - 11 ) = -48
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Giải phương trình
e) x4 -4x3-8x2+8x=0
f) 2x2+3xy+y2=0
g) 2x4-x3-9x2+13x-5=0
h) (x+1)(x+3)(x+5)(x+7)+15=0
e: =>x(x^3-4x^2-8x+8)=0
=>x[(x^3+8)-4x(x+2)]=0
=>x(x+2)(x^2-2x+4-4x)=0
=>x(x+2)(x^2-6x+4)=0
=>\(x\in\left\{0;-2;3+\sqrt{5};3-\sqrt{5}\right\}\)
g: =>2x^4+5x^3-6x^3-15x^2+6x^2+15x-2x-5=0
=>(2x+5)(x^3-3x^2+3x-1)=0
=>(2x+5)(x-1)^3=0
=>x=1 hoặc x=-5/2
h: =>(x^2+8x+7)(x^2+8x+15)+15=0
=>(x^2+8x)^2+22(x^2+8x)+120=0
=>(x^2+8x+10)(x^2+8x+12)=0
=>(x^2+8x+10)(x+2)(x+6)=0
=>\(x\in\left\{-2;-6;-4+\sqrt{6};-4-\sqrt{6}\right\}\)
c) \(\left(34-2x\right)\left(2x-6\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}34-2x=0\\2x-6-0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
d) \(\left(2019-x\right)\left(3x-12\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)
e) \(57\left(9x-27\right)=0\)
\(\Rightarrow9x-27=0\)
\(\Rightarrow9\left(x-3\right)=0\)
\(\Rightarrow x-3=0\)
\(\Rightarrow x=3\)
f) \(25+\left(15-x\right)=30\)
\(\Rightarrow25+15-x=30\)
\(\Rightarrow40-x=30\)
\(\Rightarrow x=40-30\)
\(\Rightarrow x=10\)
g) \(43-\left(24-x\right)=20\)
\(\Rightarrow43-24+x=20\)
\(\Rightarrow19+x=20\)
\(\Rightarrow x=20-19\)
\(\Rightarrow x=1\)
h) \(2\left(x-5\right)-17=25\)
\(\Rightarrow2\left(x-5\right)=17+25\)
\(\Rightarrow x-5=21\)
\(\Rightarrow x=21+5\)
\(\Rightarrow x=26\)
i) \(3\left(x+7\right)-15=27\)
\(\Rightarrow3\left(x+7\right)=27+15\)
\(\Rightarrow x+7=14\)
\(\Rightarrow x=14-7\)
\(\Rightarrow x=7\)
j) \(15+4\left(x-2\right)=95\)
\(\Rightarrow4\left(x-2\right)=95-15\)
\(\Rightarrow4\left(x-2\right)=80\)
\(\Rightarrow x-2=20\)
\(\Rightarrow x=20+2\)
\(\Rightarrow x=22\)
k) \(20-\left(x+14\right)=5\)
\(\Rightarrow x+14=20-5\)
\(\Rightarrow x+14=15\)
\(\Rightarrow x=15-14\)
\(\Rightarrow x=1\)
l) \(14+3\left(5-x\right)=27\)
\(\Rightarrow3\left(5-x\right)=27-14\)
\(\Rightarrow3\left(5-x\right)=13\)
\(\Rightarrow5-x=\dfrac{13}{3}\)
\(\Rightarrow x=5-\dfrac{13}{3}\)
\(\Rightarrow x=\dfrac{2}{3}\)
1) \(\left(x-2\right)\left(x+4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)
2) \(\left(x-2\right)\left(x+15\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-2=0\\x+15=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-15\end{matrix}\right.\)
3) \(\left(7-x\right)\left(x+19\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}7-x=0\\x+19=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=7\\x=-19\end{matrix}\right.\)
4) \(-5< x< 1\)
\(\Rightarrow x\in\left\{-1;-3;-2;-1;0\right\}\)
5) \(\left(x-3\right)\left(x-5\right)< 0\)
\(\Rightarrow\left[{}\begin{matrix}x-3>0\\x-5< 0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x>3\\x< 5\end{matrix}\right.\)
\(\Rightarrow3< x< 5\)
6) \(2x^2-3=29\)
\(\Rightarrow2x^2=29+3\)
\(\Rightarrow2x^2=32\)
\(\Rightarrow x^2=\dfrac{32}{2}\)
\(\Rightarrow x^2=16\)
\(\Rightarrow x^2=4^2\)
\(\Rightarrow\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
7) \(-6x-\left(-7\right)=25\)
\(\Rightarrow-6x+7=25\)
\(\Rightarrow-6x=25-7\)
\(\Rightarrow-6x=18\)
\(\Rightarrow x=\dfrac{18}{-6}\)
\(\Rightarrow x=-3\)
8) \(46-\left(x-11\right)=-48\)
\(\Rightarrow x-11=48+46\)
\(\Rightarrow x-11=94\)
\(\Rightarrow x=94+11\)
\(\Rightarrow x=105\)
1: (x-2)(x+4)=0
=>x-2=0 hoặc x+4=0
=>x=2 hoặc x=-4
2: (x-2)(x+15)=0
=>x-2=0 hoặc x+15=0
=>x=2 hoặc x=-15
3: (7-x)(x+19)=0
=>7-x=0 hoặc x+19=0
=>x=7 hoặc x=-19
4: -5<x<1
=>\(x\in\left\{-4;-3;-2;-1;0\right\}\)
5: (x-3)(x-5)<0
=>x-3>0 và x-5<0
=>3<x<5
6: 2x^2-3=29
=>2x^2=32
=>x^2=16
=>x=4 hoặc x=-4
7: -6x-(-7)=25
=>-6x=25-7=18
=>x=-3
8: 46-(x-11)=-48
=>x-11=46+48=94
=>x=94+11=105
a, 3x - 7 = 0
<=> 3x = 7
<=> x = 7/3
b, 8 - 5x = 0
<=> -5x = -8
<=> x = 8/5
c, 3x - 2 = 5x + 8
<=> -2x = 10
<=> x = -5
e) Ta có: \(\left(5x+1\right)\left(x-3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}5x+1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}5x=-1\\x=3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{5}\\x=3\end{matrix}\right.\)
Vậy: \(S=\left\{-\dfrac{1}{5};3\right\}\)
13) –12(x -5) + 7(3 -x) = 5
→ -12x + 60 + 21 - 7x = 5
→ -12x - 7x = 5 - 60 - 21
→ -19x = -76
→ x = -76 : ( - 19 )
→ x = 4
14) (x –2).(x + 4) = 0
→ ( x - 2 ) . ( x + 4 ) = 0 ↔ x - 2 = 0 hoặc x + 4 = 0 ( chọn 1 cách thôi nhé )
→ x = 0 + 2 = 2 hoặc x = 0 - 4 = -4
15) (x –2).( x + 15) = 0 ( làm giống câu trên )
16) (7–x).( x + 19) = 0 ( làm giống câu trên )
17) -5<x<1
→ x ϵ -4 ; -3 ; -2 ; -1 ; 0
18) /x/<3
→ x ϵ -2 ; -1 ; 0 ; 1 ; 2
19) (x –3)(x –5) < 0
→ x - 3 . x - 5 < 0
→ 2x - 15 < 0
→ 2x < 0 + 15 = 15
→ x < 15 : 2 = 7,5
→ x ϵ ....... ( bạn tự ghi nhé )
20) 2x2–3 = 29( đề bài sai )
21) –6x –(–7) = 25
→ -6x + 7 = 25
→ -6x = 25 - 7 = 18
→ x = 18 : ( - 6 ) = -3
22) 46 –( x –11 ) = –48
→ 46 - x + 11 = -48
→ -x = -48 - 11 - 46 = -105
→ x = 105
1) x - 2 = -6
x = -6 + 2
x = -4
2) -5 . x - ( -3 ) =13
-5 . x = 13 + ( -3 )
-5 . x = 10
x = 10 : ( -5 )
x = -2
a)\(=\dfrac{3}{3}+\dfrac{4}{3}=\dfrac{7}{3}\)
b)\(=\dfrac{5}{9}\times\dfrac{3}{2}=\dfrac{15}{18}=\dfrac{5}{6}\)
d)\(=\left(\dfrac{12}{8}-\dfrac{3}{8}\right)\times2=\dfrac{9}{8}\times2=\dfrac{18}{8}=\dfrac{9}{4}\)
c)\(=\dfrac{4}{3}-\dfrac{5}{6}=\dfrac{8}{6}-\dfrac{5}{6}=\dfrac{3}{6}=\dfrac{1}{2}\)
a) 1 + 4/3 = 7/3
b) 5/9 : 2/3 = 5/6
c ) 4/3 -1/3 x 5/2
= 1 x 5/2
= 5/2
d) ( 3/2 - 3/8) : 1/2
= 9/8 : 1/2
= 9/4
e) 15/16 : 3/8 x 3/4
= 5/2 x 3/4
= 15/8
f) 7/19 x 1/3 x 7/19 x 2/3
= 7/19 x (1/3 x 2/3)
= 7/19 x 2/9
= 14/171
g) 3/5 x 8/27 x 25/3
= 3/5 x 25/3 x 8/27
= 5 x 8/27
= 40/27
h) 1/5 + 4/11 + 4/5 + 7/11
= (1/5 + 4/5) + (4/11 + 7/11)
= 1 + 1
= 2
Dễ thế mà không làm được thì bạn nên xem lại nhé,một hai câu thì còn được chứ cả 10 câu thế kia rõ là ỷ lại rồi bạn ạ.Thân!
i) 46 - ( x - 11 ) = -48
=>x-11=94
=>x=105
Vậy x=105
a. +) x-2 =3
x=5
+) x-2=-3
x= 1