Question

[Cô Thu Hà]

a) $24,3.\Big(\dfrac{-11}{25}\Big)+\Big(\dfrac{-11}{25}\Big).75,7$

b) $[(9^2:3^2)+(125:5^2)].\Big(\dfrac{-1}{2}\Big)^2$

c) $\sqrt{16}+\sqrt{100}-\sqrt{36}$

Answer 1

[Kiều Vũ Linh]

a) \(24,3.\left(\dfrac{-11}{5}\right)+\left(\dfrac{-11}{5}\right).75,7\)

\(=\dfrac{-11}{5}.\left(24,3+75,7\right)\)

\(=\dfrac{-11}{5}.100\)

\(=-220\)

b) \(\left[\left(9^2:3^2\right)+\left(125:5^2\right)\right].\left(\dfrac{-1}{2}\right)^2\)

\(=\left[\left(9:3\right)^2+\left(125:25\right)\right].\left(\dfrac{-1}{2}\right)^2\)

\(=\left(3^2+5\right).\dfrac{1}{4}\)

\(=\left(9+5\right).\dfrac{1}{4}\)

\(=14.\dfrac{1}{4}\)

\(=\dfrac{7}{2}\)

c) \(\sqrt{16}+\sqrt{100}-\sqrt{36}\)

\(=4+10-6\)

\(=14-6\)

\(=8\)