Question

[Phạm Hải Phong]

C = 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128

Answer 1

[Nguyễn Thị Thương Hoài]

C= \(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+\dfrac{1}{64}+\dfrac{1}{128}\)

2C = \(1+\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+\dfrac{1}{64}\)

2C-C = \(1-\dfrac{1}{128}\)

C= \(\dfrac{127}{128}\)

Answer 2

[duong quynh nga]

C= $\genfrac{}{}{0ex}{}{1}{2}+\genfrac{}{}{0ex}{}{1}{4}+\genfrac{}{}{0ex}{}{1}{8}+\genfrac{}{}{0ex}{}{1}{16}+\genfrac{}{}{0ex}{}{1}{32}+\genfrac{}{}{0ex}{}{1}{64}+\genfrac{}{}{0ex}{}{1}{128}$

2C = $1+\genfrac{}{}{0ex}{}{1}{2}+\genfrac{}{}{0ex}{}{1}{4}+\genfrac{}{}{0ex}{}{1}{8}+\genfrac{}{}{0ex}{}{1}{16}+\genfrac{}{}{0ex}{}{1}{32}+\genfrac{}{}{0ex}{}{1}{64}$

2C-C = $1-\genfrac{}{}{0ex}{}{1}{128}$

C= $\genfrac{}{}{0ex}{}{127}{128}$