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d) 7/18 . x - 2/3 = 5/18
7/18 . x = 5/18+2/3
= 17/18 : 7/18
= 17/7
e) 4/9 - 7/8 . x = -2/3
7/8 . x = 4/9 - -2/3
= 10/9 : 7/8
= 80/63
f) 1/6 + -5/7 : x = -7/18
-5/7 : x = -7/18 - 1/6
-5/7 : x = -5/9
= -5/7 : -5/9
= 9/7
Sau đó bạn thử lại kết quả nha!
b: \(\dfrac{163}{257}< \dfrac{163}{221}\)
mà 149/257<163/257
nên 149/257<163/257<163/221
c: \(\dfrac{15}{18}=\dfrac{5}{6}=\dfrac{100}{120}\)
\(\dfrac{17}{20}=\dfrac{102}{120}\)
\(\dfrac{21}{24}=\dfrac{105}{120}\)
mà 100<102<105
nên 15/18<17/20<21/24
=>-15/17>-17/20>-21/24
a: 15/18=5/6=100/120
17/20=102/120
21/24=105/120
mà 100<102<105
nên 15/18<17/20<21/24
=>-15/18>-17/20>-21/24
a: \(\dfrac{5}{24}-\dfrac{6}{21}=\dfrac{35}{168}-\dfrac{48}{168}=\dfrac{-13}{168}\)
b: \(-\dfrac{1}{4}+\dfrac{2}{3}+\dfrac{5}{18}=\dfrac{-9}{36}+\dfrac{24}{36}+\dfrac{10}{36}=\dfrac{5}{36}\)
c: \(\dfrac{2}{3}+\dfrac{3}{4}+\dfrac{1}{2}=\dfrac{8}{12}+\dfrac{9}{12}+\dfrac{6}{12}=\dfrac{23}{12}\)
d: \(=\dfrac{3}{4}-\dfrac{2}{5}+\dfrac{1}{3}=\dfrac{45}{60}-\dfrac{24}{60}+\dfrac{20}{60}=\dfrac{41}{60}\)
1/ \(\frac{7}{5}=1\frac{2}{5}\)
\(-\frac{18}{7}=-2\frac{4}{7}\)
2/\(4\frac{1}{7}=\frac{29}{7}\)
\(-2\frac{7}{11}=-\frac{29}{11}\)
Câu 1:
\(\frac{1}{3}+\frac{3}{35}<\frac{x}{210}<\frac{4}{7}+\frac{3}{5}+\frac{1}{3}\)
\(\Rightarrow\frac{44}{105}<\frac{x}{210}<\frac{158}{105}\)
\(\Rightarrow\frac{88}{210}<\frac{x}{210}<\frac{316}{210}\)
\(\Rightarrow x\in\left\{89;90;91;92;...;310;311;312;313;314;315\right\}\)
Câu 3:
\(\frac{5}{3}\)\(+\frac{-14}{3}\)\(<\)\(x\)\(<\)\(\frac{8}{5}+\frac{18}{10}\)
\(\Rightarrow\)\(-9\)\(<\)\(x\)\(<\)\(3,4\)
Mà \(x\in Z\)
\(\Rightarrow x\in\left\{-8;-7;-6;-5;...;1;2;3\right\}\)
Ta co :5/7=5.11/7.11=55/77;18/11=126/77
=> TS ban dau=126-71=55
Vì 55/b=5/7 nên 55.7=b5=385
=>b=385:5=77
Vay a/b=55/77
ta có a/b=5/7
hay a/b=5*c/7*c(c thuộc Z c khác 0)
a+71/b=18/11
hay 5c+71/7c=18/11
suy ra (5c+71)*11=7c*18
55c+781=126c
781=126c-55c
781=71c
c=781/71=11
a/b=5*11/7*11=55/77
wow
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