Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1) \(2^x-15=17\)
\(\Leftrightarrow2^x=32=2^5\)
\(\Rightarrow x=5\)
2) \(\left(7x-11\right)^3=25\cdot5^2+200\)
\(\Leftrightarrow\left(7x-11\right)^3=825\)
\(\Leftrightarrow7x-11=\sqrt[3]{825}\)
\(\Leftrightarrow7x=11+\sqrt[3]{825}\)
\(\Rightarrow x=\frac{11+\sqrt[3]{825}}{7}\)
3) \(\left(x+1\right)^{100}-3\left(x+1\right)^{99}=0\)
\(\Leftrightarrow\left(x+1\right)^{99}\left(x-2\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}\left(x+1\right)^{99}=0\\x-2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-1\\x=2\end{cases}}\)
4) \(4x+5\left(x+3\right)=105\)
\(\Leftrightarrow9x+15=105\)
\(\Leftrightarrow9x=90\)
\(\Rightarrow x=10\)
5) \(5\cdot\left(x-2\right)+10\left(x+3\right)=170\)
\(\Leftrightarrow5\left[x-2+2\left(x+3\right)\right]=170\)
\(\Leftrightarrow3x+4=34\)
\(\Leftrightarrow3x=30\)
\(\Rightarrow x=10\)
12 + ( 5 + x ) = 20 5.22 + ( x + 3 ) = 52 23 + ( x + 3 ) = 52 43 - ( x - 2 ) = 52
17 + x = 20 5.4 + x + 3 = 25 8 + x + 3 = 25 64 - x + 2 = 25
x = 20 - 17 20 + 3 + x = 25 11 + x = 25 66 - x = 25
x = 3 23 + x = 25 x = 25 - 11 x = 66 - 25
x = 25 - 23 x = 14 x = 41
x = 2
Đăng nhìu v bn :) Đáng quan ngại đây :)
\(a,5^{14}.x=5^{17}\\ x=\dfrac{5^{17}}{5^{14}}=5^{17-14}=5^3=125\\ ----\\ b,5^x+5^{x+2}+5^{x+4}=16275\\ 5^x.\left(1+5^2+5^4\right)=16275\\ 5^x.651=16275\\ 5^x=\dfrac{16275}{651}=25=5^2\\ Vậy:x=2\\ -----\\ c,2^7.x-100=1948\\ 128.x=1948+100=2048\\ x=\dfrac{2048}{128}=16\)
a, 514 \(\times\) \(x\) = 517
\(x\) = 517 : 514
\(x\) = 53
b, 5\(^x\) + 5\(^{x+2}\) + 5\(^{x+4}\) = 1948
5\(^x\) .( 1 + 52 + 54) = 1948
5\(^x\). ( 1 + 25 + 625) = 1948
5\(^x\) . 651 = 1948
5\(^x\) = 1948 : 651 ( xem lại đề bài )
c, 27 \(\times\) \(x\) - 100 = 1948
27 \(\times\) \(x\) = 1948 + 100
27 \(\times\) \(x\) = 2048
\(x\) = 2048 : 27
\(x\) = \(\dfrac{2048}{27}\)
Bài 1 :
\(11.x+5=60\)
\(\Leftrightarrow\)\(11.x=60-5\)
\(\Leftrightarrow11.x=55\)
\(\Leftrightarrow x=55:11\)
\(\Rightarrow x=5\)
Vậy x=5
\(11.x+5=60\)
\(11x=55\)
\(x=5\)
\(2|x+5|=32-13\)
\(2|x+5|=19\)
\(|x+5|=\frac{19}{2}\)
\(\Rightarrow\orbr{\begin{cases}x+5=\frac{19}{2}\\x+5=-\frac{19}{2}\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{9}{2}\\x=-\frac{29}{2}\end{cases}}}\)
a. -12 (x-5) +7(3-x) = -12x+60+21-7x=-19x+81=15
=> -19x=15-81=-66
=> x=66/19
b. 30(x+2) - 5 (x-5) - 24x = 30x+60-5x+25-24x =(30x-5x-24x)+(60+25)=x+85=100
=> x=100-85=15
=>x^2+60x=100*(-7/5)=-140
=>x^2+60x+140=0
=>\(x=-30\pm2\sqrt{190}\)