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\(n=\frac{1}{1.5}+\frac{1}{5.10}+\frac{1}{10.15}+...+\frac{1}{2005.2010}=\frac{1}{5}\left(\frac{5}{1.5}+\frac{5}{5.10}+\frac{5}{10.15}+...+\frac{5}{2010.2015}\right)\)
\(=\frac{1}{5}\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+...+\frac{1}{2005}-\frac{1}{2010}\right)=\frac{1}{5}\left(1-\frac{1}{2010}\right)\)
\(=\frac{1}{5}.\frac{2009}{2010}=\frac{2009}{10050}\)
mik nghĩ đây là bài lớp 6
-->n=\(\frac{1}{5}\left(\frac{5}{1.5}+\frac{5}{5.10}+\frac{5}{10.15}+....+\frac{5}{2005.2010}\right)\)
-->n=\(\frac{1}{5}\left[\left(1-\frac{1}{5}\right)+\left(\frac{1}{5}-\frac{1}{10}\right)+..+\frac{1}{2005}-\frac{1}{2010}\right]\)
-->n=1/5(1-1/2010)
-->n=2009/2010.1/5
-->n=2009/10050
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li-kecho mk nhé bn
=[(-5)+10]+[(-15)+20]+[(-25)+30]+...+[(-1995)+2000]+[(-2005)+3000]
=5+5+5+...+5+5 ( Có 602 số 5)
=5.602
=3010
\(\left(27.700-45.20\right)\div\left(45-40+35-30+25-20+15-10+5\right)\)
\(=\)\(\left(27.100-45.20\right)\div25\)
\(=\)\(\left(27.35.20-45.20\right)\div25\)
\(=\)\(\left[\left(27.35-45\right).20\right]\div25\)
\(=\)\(18000\div25\)
\(=\)\(750\)
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a) x - (17 - 8) = 5 + (10 - 3x)
x - 17 + 8 = 5 + 10 - 3x
x + 3x = 5 + 10 + 17 - 8
4x = 24
x = 24 : 4
x = 6
b) 25 - (30 + x) = x - (27 - 8)
25 - 30 - x = x - 27 + 8
-x - x = -27 + 8 - 25 + 30
-2x = -14
x = (-14) : (-2)
x = 7
c) (x - 12) - 15 = (20 - 7) - (18 + x)
x - 12 - 15 = 20 - 7 -18 - x
x + x = 20 - 7 - 18 + 12 + 15
2x = 22
x = 22 : 2
x = 11
d) 9 - 25 = (7 - x) - (25 + 7)
9 - 25 = 7 - x - 25 - 7
x = 7 - 25 - 7 - 9 +25
x = -9
x = 1005 nha bạn .
10+20+30+...+2010 có số c/s là (2010-10):10+1=201
5+15+25+...+2005 có số c/s là (2005-5):10+=201
tc (10-5) +( 20-15)+(30-25)+......+(2010-2005)
5 +5+5....+5 có 201 c/s
5.201=1005