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\(a) C_6H_{12}O_6 \xrightarrow{t^o,xt} 2CO_2 + 2C_2H_5OH\\ C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O\\ CH_3COOH + C_2H_5OH \to CH_3COOC_2H_5 + H_2O\\ b) C_{12}H_{22}O_{11} + H_2O \xrightarrow{H^+}C_6H_{12}O_6 + C_6H_{12}O_6\\ C_6H_{12}O_6 \xrightarrow{t^o,xt} 2CO_2 + 2C_2H_5OH\\C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O\\ CH_3COOH + NaOH \to CH_3COONa + H_2O\\ c) CH_3COOC_2H_5 + NaOH \to CH_3COONa + C_2H_5OH\\ d) 2CH_3COOC_2H_5 + Ca(OH)_2 \to (CH_3COO)_2Ca + 2C_2H_5OH\)
\((CH_3COO)_2Ca + H_2SO_4 \to CaSO_4 + 2CH_3COOH\)
\(C_2H_4+H_2O\underrightarrow{^{170^0C,H_2SO_4}}C_2H_5OH\)
\(C_2H_5OH+O_2\underrightarrow{^{\text{men giấm}}}CH_3COOH+H_2O\)
\(CH_3COOH+C_2H_5OH⇌CH_3COOC_2H_5+H_2O\left(Đk:H_2SO_{4\left(đ\right)},t^0\right)\)
\(2CH_3COOC_2H_5+Ca\left(OH\right)_2\underrightarrow{^{t^0}}\left(CH_3COO\right)_2Ca+2C_2H_5OH\)
\(\left(CH_3COO\right)_2Ca+Na_2CO_3\rightarrow2CH_3COONa+CaCO_3\downarrow\)
\(C_2H_4 + H_2O \xrightarrow{t^o,xt} C_2H_5OH\\ C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O\\ CH_3COOH + C_2H_5 \rightleftharpoons CH_3COOC_2H_5 + H_2O\\ 2CH_3COOC_2H_5 + Ca(OH)_2 \to (CH_3COO)_2Ca + 2C_2H_5OH\\ (CH_3COO)_2Ca + Na_2CO_3 \to CaCO_3 + 2CH_3COONa\)
điều chế rượ etylic từ etyl axetat :
CH3COOC2H5 + NaOH - > CH3COONa + C2H5OH
điều chế etyl axetat từ axit axetic :
CH3COOH + C2H5OH \(\xrightarrow[to]{H2SO4,đặc}\) CH3COOC2H5 + H2O
điều chế axit axetic bằng rượu etylic:
\(C2H5OH+O2-^{men-giấm}->CH3COOH+H2O\)
điều chế etylic bằng glucozo :
\(C6H12O6\xrightarrow[30-33^{oC}]{men-rượu}2C2H5OH+2CO2\)
điều chế glucozo bằng tinh bột :
\(\left(-C6H10O5-\right)n+nH2O\xrightarrow[axit]{t0}nC6H12O6\)
a)
$C_2H_5OH + CH_3COOH \buildrel{{H_2SO_4,t^o}}\over\rightleftharpoons CH_3COOC_2H_5 + H_2O$
b)
n CH3COOC2H5 = n C2H5OH = 9,2/46 = 0,2(mol)
=> m este = 0,2.88 = 17,6 gam
c)
n este = 8,8/88 = 0,1(mol)
=> n C2H5OH = n CH3COOH = 0,1/60% = 1/6 mol
=> m C2H5OH = 46 . 1/6 = 7,67(gam) ; m CH3COOH = 60 . 1/6 = 10(gam)
\(a,C_2H_6O+3O_2\xrightarrow[]{t^o}2CO_2+3H_2O\\ CO_2+2NaOH\rightarrow Na_2CO_3+H_2O\\ Na_2CO_3+CO_2+H_2O\rightarrow2NaHCO_3\\ NaHCO_3+HCl\rightarrow NaCl+CO_2\uparrow+H_2O\)
\(b,C_2H_4+H_2O\xrightarrow[axit]{t^o}C_2H_5OH\\ C_2H_5OH+O_2\underrightarrow{\text{men giấm}}CH_3COOH+H_2O\\ CH_3COOH+C_2H_5OH\xrightarrow[t^o]{H_2SO_{4\left(đặc\right)}}CH_3COOC_2H_5+H_2O\\ 2CH_3COOH+BaO\rightarrow\left(CH_3COO\right)_2Ba+H_2O\\ \left(CH_3COO\right)_2Ba+Na_2SO_4\rightarrow2CH_3COONa+BaSO_4\downarrow\\ CH_3COONa+NaOH\rightarrow Na_2CO_3+CH_4\uparrow\)
\(\left(-C_6H_{10}O_5-\right)_n+nH_2O\xrightarrow[t^o]{axit}nC_6H_{12}O_6\)
\(C_6H_{12}O_6\xrightarrow[]{men}2C_2H_5OH+2CO_2\)
\(C_2H_5OH+O_2\xrightarrow[]{men}CH_3COOH+H_2O\)
\(C_2H_5OH+CH_3COOH\xrightarrow[H_2SO_4\left(đ\right)]{t^o}CH_3COOC_2H_5+H_2O\)
\(CH_3COOC_2H_5+H_2O\xrightarrow[t^o]{xt}CH_3COOH+C_2H_5OH\)
a) \(2CH_3COONa+H_2SO_4\rightarrow2CH_3COOH+Na_2SO_4\)
b) \(2C_2H_5OH+O_2\underrightarrow{t^o}CH_3COOH+CO_2\)
c) \(2C_4H_{10}+5O_2\rightarrow4CH_3COOH+2H_2O\)
a) 2CH3COONa + H2SO4 -> 2CH3COOH + Na2SO4
b) C2H5OH + O2 -men giấm -> CH3COOH + H2O
c) 2C4H10 + 5O2 -xt,to-> 4CH3COOH + 2H2O