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`a,`
`31/23-(7/32+8/23)`
`=31/23-7/32-8/23`
`=(31/23-8/23)-7/32`
`=1-7/32=25/32`
`b,`
`38/45-(8/45-17/51-3/11)`
`=38/45-8/45+17/51+3/11`
`= (38/45-8/45)+17/51+3/11`
`=2/3+17/51+3/11`
`=1+3/11=14/11`
`c,`
`(1/3+12/67+13/41)-(79/67-28/41)`
`= 1/3+12/67+13/41-79/67+28/41`
`= 1/3+(12/67-79/67)+(13/41+28/41)`
`= 1/3+(-1)+1=1/3+(-1+1)=1/3+0=1/3`
`d,`
`1/5+(-1/6)+1/7+(-1/8)+1/9+1/8+(-1/7)+1/6+(-1/5)`
`= (1/5+ -1/5)+(-1/6+1/6)+(1/7+ -1/7)+(-1/8 +1/8)+1/9`
`= 0+0+0+0+1/9=1/9 .`
Bài 2:
a: =>x-35=-23
=>x=12
b: =>|x-8|=13
=>x-8=13 hoặc x-8=-13
=>x=21 hoặc x=-5
Bài 1:
a: =42-98-42+12-12=-98
b: =10x4x3x(-25)=40x(-25)x3=-1000x3=-3000
1:
a: \(=\dfrac{-4}{7}+\dfrac{4}{7}+\dfrac{3}{7}-\dfrac{23}{34}-\dfrac{4}{5}=\dfrac{3}{7}-\dfrac{23}{34}-\dfrac{4}{5}=-\dfrac{1247}{1190}\)
b:
Sửa đề: \(\dfrac{-5}{13}+\dfrac{4}{19}+\dfrac{-8}{13}+\dfrac{15}{19}+\dfrac{45}{6}\)
\(=\dfrac{-5}{13}-\dfrac{8}{13}+\dfrac{4}{19}+\dfrac{15}{19}+\dfrac{45}{6}=\dfrac{9}{2}\)
a: \(=\dfrac{9}{4}+\dfrac{11}{14}=\dfrac{63+22}{28}=\dfrac{85}{28}\)
b: \(=\dfrac{-7}{5}-\dfrac{11}{5}=-\dfrac{18}{5}\)
c: \(=\dfrac{-12}{13}-\dfrac{9}{13}=\dfrac{-21}{13}\)
d: \(=\dfrac{3-5}{4}=\dfrac{-2}{4}=-\dfrac{1}{2}\)
13/50+9/100+41/100+12/50
=(13/50+12/50)+(9/100+41/100)
=1/2+1/2
=1
11) Ta có:
\(\frac{120-0,5.40.5.0,2.20.0,25-20}{1+5+9+...+33+37}\)
\(=\frac{120-\left(0,5.40\right).\left(5.0,2\right).\left(20.0,25\right)-20}{1+5+9+...+33+37}\)
\(=\frac{120-20.1.5-20}{1+5+9+...+33+37}\)
\(=\frac{120-100-20}{1+5+9+...+33+37}\)
\(=\frac{0}{1+5+9+...+33+37}=0\)
B3:
a. =-1250000
b. =-20000
c. =0
d. =-24000
B4:
a. =-4100
b. =-2700
c. =400
d. =1007
Trả lời
a)4/5.9/7-4/5.3/14
=4/5(9/7-3/14)
=4/5(18/14-3/14)
=4/5.15/14
=6/7
b)13/50+9%+41/100+24%
=13/50+9/100+41/100+24/100
=26+9+41+24/100
=(26+24)+(9+41)/100
=100/100
=1
\(\frac{4}{5}\cdot\frac{9}{7}-\frac{4}{5}\cdot\frac{3}{14}\)
=\(\frac{4}{5}\cdot(\frac{9}{7}-\frac{3}{14})\)
=\(\frac{4}{5}\cdot\frac{15}{14}\)
=\(\frac{6}{7}\)
b,\(\frac{13}{50}\)+9%+\(\frac{41}{100}\)+24%
=26%+9%+41%+24%
=100%=1