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B = \(\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}.\left(13+65\right)}{2^8.104}=\frac{2^{10}.78}{2^8.104}\)
B = \(\frac{2^2.39}{52}=\frac{2^2.39}{2^2.13}\)
B = \(\frac{39}{13}\)
B = 3
B = \(\frac{2^{10}.13-2^{10}.65}{2^8.104}=\frac{2^{10}.\left(13+65\right)}{2^{8.104}}=\frac{2^{10}.78}{2^8.104}=\frac{2^2.39}{52}=\frac{2^2.39}{2^2.13}=\frac{39}{13}=3\)
a, 35.34 + 35.86 + 65.75 + 65.45
= 35.(34 + 86) + 65.(75 + 45)
= 35.120 + 65.120
= 120.(35+65)
= 120.100
= 12000
b, \(7.5^2-32:2^3+9\)
= 7.25 - 32:8 + 9
= 175 - 4 + 9
= 180
a) 35.34 + 35.86 + 65.75 + 65.45 =
( 35 + 65 ) x ( 34 + 86 ) + ( 75 + 45 )
100 x 120 x 120
100 x 14400
1440000
\(35\cdot34+35\cdot86+65\cdot75+65\cdot45\\ =35\cdot\left(34+86\right)+65\cdot\left(75+45\right)\\ =35\cdot120+65\cdot120\\ =120\cdot\left(35+65\right)\\ =120\cdot100\\ =12000\)
\(\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}.13+2^{10}.5.13}{2^8.2^3.13}=\frac{2^{10}.13\left(1+5\right)}{2^{11}.13}=\frac{2^{10}.13.2.3}{2^{11}.13}=\frac{2^{11}.3.13}{2^{11}.13}=3\)
a) \(=38\left(63+37\right)=38.100=3800\)
b) \(=53\left(12+172-84\right)=53.100=5300\)
c) \(=35\left(34+38\right)+65\left(75+45\right)=35.72+65.120=10422\)
d) \(=39.8+15.8+21.8=8\left(39+15+21\right)=8.75=600\)
e) \(=36\left(28+82\right)+64\left(69+41\right)=36.110+64.110=110\left(36+64\right)=110.100=11000\)
\(\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}.13+2^{10}.13.5}{2^8.2^3.13}\)
\(=\frac{2^{10}.13+2^{10}.13.5}{2^{11}.13}\)
\(=\frac{2^{10}.13\left(1+5\right)}{2^{11}.13}\)
\(=\frac{2^{10}.13.6}{2^{11}.13}\)
\(=\frac{2^{11}.13.3}{2^{11}.13}=3\)
T_i_c_k cho mình nha mơn bạn nhiều ^^
A,35*34+35*86+65*75+65*45
=35*[34+86]+65*[75+45]
=35*100+65*120
=35*100+65*100+65*20
=[35+65]*100+65*20
=10000+1300=11300
a. 8 x 17 x 125
= 8 x 125 x 17
= 1000 x 17
= 17000
b. 35 x 34 + 35 x 36 + 65 x 75 + 65 x 45
= 35 x (34 + 36 ) + 65 x ( 75 + 45 )
= 35 x 70 + 65 x 120
= 2450 + 7800
= 10250
c 4 x 72 + 16 x 22
= 4 x 49 + 16 x 4
= 4 x ( 49 + 16)
= 4 x 65
= 260
d. mk ko hỉu bạn ghi cái j