Question

[Hoàng Quỳnh Trang]

tính giá trị biểu thức khi đã bỏ dấu ngoặc :

A = ( 3,1 - 2,5 ) - ( - 2,5 + 3,1 )

B = ( 5,3 - 2,8 ) - ( 4 + 5,3 )

C = - ( 251 .3 + 281 ) + 3 . 215 - ( 1 -281 )

D = -\((\dfrac{3}{5}+\dfrac{3}{4})\) - \((-\dfrac{3}{4}+\dfrac{2}{5})\)

giúp mk nhé

Answer 1

[Phạm Tú Uyên]

\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)

\(=3,1-2,5+2,5-3,1=0\)

\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)

\(=5,3-2,8-4-5,3=-6,8\)

\(C=-\left(251.3+281\right)+3.215-\left(1-281\right)\)

\(=-753-281+645-1+281\)

\(=-753+654-1=-100\)

\(D=-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(\dfrac{-3}{4}+\dfrac{2}{5}\right)\)

\(=-\dfrac{3}{5}-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{2}{5}=\dfrac{-3}{5}-\dfrac{2}{5}=-1\)

Answer 2

[Hoàng Thị Ngọc Anh]

\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)

\(=3,1-2,5+2,5-3,1\)

\(=\left(3,1-3,1\right)-\left(2,5-2,5\right)\)

\(=0\)

Vậy \(A=0.\)

\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)

\(=5,3-2,8-4-5,3\)

\(=\left(5,3-5,3\right)-\left(2,8+4\right)\)

\(=-\dfrac{34}{5}\)

Vậy \(B=\dfrac{-34}{5}.\)

\(C=-\left(251.3+281\right)+3.215-\left(1-281\right)\)

\(=-251.3-281+3.215-1+281\)

\(=-753-\left(281-281\right)+645\)

\(=-753+645=-108\)

Vậy \(C=-108.\)

\(D=-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(-\dfrac{3}{4}+\dfrac{2}{5}\right)\)

\(=-\dfrac{3}{5}-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{2}{5}\)

\(=\left(\dfrac{-3}{5}-\dfrac{2}{5}\right)-\left(\dfrac{3}{4}-\dfrac{3}{4}\right)\)

\(=-1\)

Vậy D = -1.