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a, y + 30%y = -1,3
1.y + 30/100y = -13/10
1.y + 3/10y = -13/10
(1 + 3/10). y = -13/10
13/10 .y = -13/10
y = -13/10 : 13/10
y = -13/10 . 10/13
y = -1
b, y - 25%y = 1/2
1.y - 25/100.y = 1/2
1.y - 1/4.y = 1/2
(1 - 1/4) y = 1/2
3/4 .y = 1/2
y = 1/2 : 3/4
y = 1/2 . 4/3
y = 2/3
câu c mik chưa nghĩ ra
a) ( x - 3 )( y + 5 ) = 13
Ta lập bảng :
| x - 3 | - 1 | - 13 | 13 | 1 |
| y + 5 | - 13 | - 1 | 1 | 13 |
| x | 2 | - 10 | 16 | 4 |
| y | - 18 | - 6 | - 4 | 8 |
Vậy : x = 2 và y = - 18
Hoặc x = - 10 và y = - 6
Hoặc x = 16 và y= - 4
Hoặc x = 4 và y = 8
a) Có (x-3) (y+5)=13
=>x-3 và y+5 thuộc Ư(13)={1;13;-1;-13}
Ta có bảng sau
| x-3 | 1 | 11 | -1 | -11 |
| y+5 | 11 | 1 | -11 | -1 |
| x | 4 | 14 | 2 | -8 |
| y | 6 | -4 | -16 | -6 |
Các câu khác bn lm tương tự nha
a)\(y+30\%y=-1,3\Rightarrow y+\frac{3}{10}y=-1,3\Rightarrow y\left(1+\frac{3}{10}\right)=-1,3\Rightarrow y\times1,3\)\(=-1,3\Rightarrow y=-1\)
b)\(y-25\%y=\frac{1}{2}\Rightarrow y-\frac{1}{4}y=\frac{1}{2}\Rightarrow y\left(1-\frac{1}{4}\right)=\frac{1}{2}\Rightarrow y\times\frac{3}{4}=\frac{1}{2}\Rightarrow y=\frac{1}{2}:\frac{3}{4}\Rightarrow y=\frac{2}{3}\)
c)\(3\frac{1}{3}y+16\frac{3}{4}=13,25\Rightarrow\frac{10}{3}y+\frac{67}{4}=\frac{53}{4}\Rightarrow\frac{10}{3}y=\frac{53}{4}-\frac{67}{4}\Rightarrow\frac{10}{3}y=\frac{-7}{2}\Rightarrow y=\frac{-21}{20}\)
a) ta có : y + 30/100y = -1,3
hay y(1+ 3/10) = - 13/10
y.13/10 = -13/10
y= -13/10:13/10
y= -1
b) y - 25/100y=1/2
hay y(1-1/4)=1/2
y.3/4 = 1/2
y=2/3
c) 10/3y + 16,75 = -13,25
10/3y= -13,25 - 16,75
10/3y= -30
y= - 30:10/3
y= -9
Lời giải:
a. $y+30\text{%}y=-1,3$
$y+0,3y=-1,3$
$y(1+0,3)=-1,3$
$y.1,3=-1,3$
$y=(-1,3):1,3=-1$
b.
$y-25\text{%}y=\frac{1}{2}$
$y-0,25y=0,5$
$y(1-0,25)=0,5$
$y.0,75=0,5$
$y=0,5:0,75=\frac{2}{3}$
c.
\(3+\frac{1}{3}y+16+\frac{3}{4}=-13,25\)
$\frac{1}{3}y+19,75=-13,25$
$\frac{1}{3}y=-13,25-19,75=-33$
$y=-33:\frac{1}{3}=-99$
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