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LT
1
K
12 tháng 11 2018
\(\frac{x-3}{53}+\frac{x+14}{36}=\frac{x+15}{35}-\frac{x}{50}\)
\(\left(1+\frac{x-3}{53}\right)+\left(1+\frac{x+14}{36}\right)=\left(\frac{x+15}{35}+1\right)-\left(1+\frac{x}{50}\right)\)
\(\frac{x+50}{53}+\frac{x+50}{36}-\frac{x+15}{35}+\frac{x+50}{50}=0\)
\(\left(x+50\right).\left(\frac{1}{53}+\frac{1}{36}-\frac{1}{35}+\frac{1}{50}\right)=0\)
\(\left(\frac{1}{53}+\frac{1}{36}-\frac{1}{35}+\frac{1}{50}\right)\ne0\)
\(\Rightarrow\left(x+50\right)=0\Rightarrow x=-50\)
Vậy x=-50
p/s: bn viết sai đề nên mk sửa lại
13 tháng 8 2019
\(\frac{-2}{7}\div\frac{15}{14}=\frac{-21}{20}\div\left(5\times x\right)\)
\(\Rightarrow\frac{-4}{15}=\frac{-21}{20}\div\left(5\times x\right)\)
\(\Rightarrow5\times x=\frac{-21}{20}\div\frac{-4}{15}\)
\(\Rightarrow5\times x=\frac{63}{16}\)
\(\Rightarrow x=\frac{63}{16}\div5\)
\(\Rightarrow x=\frac{63}{80}\)
~ học tốt nha ~
13 tháng 8 2019
\(\frac{-2}{7}:\frac{15}{14}=\frac{-21}{20}:(5\cdot x)\)
\(\Leftrightarrow\frac{-21}{20}:(5\cdot x)=\frac{-2}{7}:\frac{15}{14}\)
\(\Leftrightarrow\frac{-21}{20}:(5\cdot x)=\frac{-2}{7}\cdot\frac{14}{15}\)
\(\Leftrightarrow\frac{-21}{20}:(5\cdot x)=\frac{-2}{1}\cdot\frac{2}{15}\)
\(\Leftrightarrow\frac{-21}{20}:(5\cdot x)=\frac{4}{15}\)
\(\Leftrightarrow5\cdot x=\frac{-21}{20}:\frac{4}{15}\)
\(\Leftrightarrow5\cdot x=\frac{-21}{20}\cdot\frac{15}{4}\)
\(\Leftrightarrow5\cdot x=\frac{-21}{4}\cdot\frac{3}{4}\)
\(\Leftrightarrow5\cdot x=\frac{-63}{16}\)
\(\Leftrightarrow x=\frac{-63}{16}:5\)
\(\Leftrightarrow x=\frac{-63}{16}\cdot\frac{1}{5}=\frac{-63}{80}\)
C
7 tháng 7 2018
{ x2 - [ 62 - ( 82 - 9.7)3 - 7.5]3 - 5.3 }3 = 1
{ x2 + [ 36 - (64 - 63)3 - 35]3 - 15}3 = 1
[ x2 - ( 36 - 13 - 35 ) - 15 ]3 = 1
[ x2 - ( 36 - 1 - 35 ) - 15]3 = 1
[ x2 - ( 35 - 35 ) - 15]3 = 1
[ x2 - 0 - 15]3 = 1
( x2 - 15 )3 = 1
<=> ( x2 - 15)3 = 13
=> x2 - 15 = 1
<=> x2 = 16
=> x = 4
19 tháng 7 2018
\(\frac{x-90}{10}+\frac{x-76}{12}+\frac{x-58}{14}+\frac{x-36}{16}+\frac{x-15}{17}=0\)
\(\Rightarrow\left(\frac{x-90}{10}-1\right)+\left(\frac{x-76}{12}-2\right)+\left(\frac{x-58}{14}-3\right)+\left(\frac{x-36}{16}-4\right)+\left(\frac{x-15}{17}-5\right)=0\)
\(\Rightarrow\frac{x-100}{10}+\frac{x-100}{12}+\frac{x-100}{14}+\frac{x-100}{16}+\frac{x-100}{17}=0\)
\(\Rightarrow\left(x-100\right).\left(\frac{1}{10}+\frac{1}{12}+\frac{1}{14}+\frac{1}{16}+\frac{1}{17}\right)=0\)
\(\Rightarrow x-100=0\left(Vì\frac{1}{10}+\frac{1}{12}+\frac{1}{14}+\frac{1}{16}+\frac{1}{17}\ne0\right)\)
\(\Rightarrow x=100\)
LY
0
HK
2
25 tháng 12 2021
\(1.\dfrac{27^4.4^3}{9^5.8^2}=\dfrac{3^{12}.2^6}{3^{10}.2^6}=3^2=9\)
\(2.\dfrac{8^5.3^{15}}{2^{14}.81^4}=\dfrac{2^{15}.3^{15}}{2^{14}.3^{16}}=\dfrac{2}{3}\)
GN
GV Nguyễn Trần Thành Đạt
Giáo viên
25 tháng 12 2021
Ý 1:
\(\dfrac{27^4.4^3}{9^5.8^2}=\dfrac{\left(3^3\right)^4.\left(2^2\right)^3}{\left(3^2\right)^5.\left(2^3\right)^2}=\dfrac{3^{12}.2^6}{3^{10}.2^6}=3^2=9\)
Ý 2:
\(\dfrac{8^5.3^{15}}{2^{14}.81^4}=\dfrac{\left(2^3\right)^5.3^{15}}{2^{14}.\left(3^4\right)^4}=\dfrac{2^{15}.3^{15}}{2^{14}.3^{16}}=\dfrac{2^{14}.2.3^{15}}{2^{14}.3^{15}.3}=\dfrac{2}{3}\)
UN
1