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a: \(2,5:4x=0,5:0,2\)
=>\(2,5:4x=0,5\cdot5=2,5\)
=>4x=1
=>\(x=\dfrac{1}{4}\)
b: \(3,8:2x=\dfrac{1}{4}:2\dfrac{2}{3}\)
=>\(3,8:2x=\dfrac{1}{4}:\dfrac{8}{3}=\dfrac{1}{4}\cdot\dfrac{3}{8}=\dfrac{3}{32}\)
=>\(2x=3,8:\dfrac{3}{32}=\dfrac{19}{5}\cdot\dfrac{32}{3}=\dfrac{608}{15}\)
=>\(x=\dfrac{608}{15}:2=\dfrac{304}{15}\)
c: \(5,25:7x=3,6:2,4\)
=>\(5,25:7x=1,5\)
=>\(7x=5,25:1,5=3,5\)
=>\(x=\dfrac{3.5}{7}=0,5\)
d: \(1,8:1,3=-2,7:5x\)
=>\(5x=-2,7:\dfrac{18}{13}=-2,7\cdot\dfrac{13}{18}=-1,95\)
=>\(x=-1,95:5=-0,39\)
a) Ta được: x . 1,25 = 5. (-2) nên \(x = \frac{{5.( - 2)}}{{1,25}} = - 8\)
Vậy x = -8
b) Vì 18 : x = 2,4 : 3,6 nên \(\frac{{18}}{x} = \frac{{2,4}}{{3,6}} \Rightarrow 18.3,6 = x.2,4 \Leftrightarrow x = \frac{{18.3,6}}{{2,4}} = 27\)
Vậy x = 27
c) Vì (x+1) : 0,4 = 0,5 : 0,2 nên \(\frac{{x + 1}}{{0,4}} = \frac{{0,5}}{{0,2}} \Rightarrow (x + 1).0,2 = 0,4.0,5 \Leftrightarrow x + 1 = \frac{{0,4.0,5}}{{0,2}} = 1 \Leftrightarrow x = 0\)
Vậy x = 0
a, x= (-2). 5 :1,25 = -8
b, x= 18 : (2,4:3,6)= 18: 2/3 = 18 x 3/2 = 27
c, x+1= (0,5:0,2) x 0,4= 2,5 x 0,4= 1
=> x=1-1=0
a) 9x-1/4=3/2
=>9x=3/2+1/4
=>9x=7/4
=>x=7/4:9
=>x=7/36
Vậy x=7/36
b)(4x+2):2,5=3,2:0,5
=>(4x+2):2,5=6,4
=>4x+2=6,4.2,5
=>4x+2=16
=>4x=16-2
=>4x=14
=>x=14:4
=>x=7/2
Vậy x=7/2
c) 5,4/x-2=6/7
=>5,4/x=6/7+2
=>5,4/x=20/7
=>x=5,4 :20/7
=>x=1,89
Vậy x= 1,89
d) 0,5:2=3:(2x+7)
=>3:(2x+7)=0,25
=>2x+7=3:0,25
=>2x+7=12
=>2x=12-7
=>2x=5
=>x=5/2
Vậy x=5/2
a) 9x-1/4=3/2
=>9x=3/2+1/4
=>9x=7/4
=>x=7/4:9
=>x=7/36
Vậy x=7/36
b)(4x+2):2,5=3,2:0,5
=>(4x+2):2,5=6,4
=>4x+2=6,4.2,5
=>4x+2=16
=>4x=16-2
=>4x=14
=>x=14:4
=>x=7/2
Vậy x=7/2
c) 5,4/x-2=6/7
=>5,4/x=6/7+2
=>5,4/x=20/7
=>x=5,4 :20/7
=>x=1,89
Vậy x= 1,89
d) 0,5:2=3:(2x+7)
=>3:(2x+7)=0,25
=>2x+7=3:0,25
=>2x+7=12
=>2x=12-7
=>2x=5
=>x=5/2
Vậy x=5/2
a)2,5:7,5=x:3/5
0,(3)=x:3/5
\(\Rightarrow\)x= 1/5
b)x:2,5=0,003;0,75
x:2,5=1/250
\(\Rightarrow\)x=1/100
a, Ta có: x = 2,5 . 3/5 : 7,5 = 1/5
b, Ta có: x = 3 . 5 : 7 = 15/7
c, Ta có: x = -2 . 37 : 3,6 = -185/9
a) \(2.5\div7.5=x\div\frac{3}{5}\)
\(x\div\frac{3}{5}=\frac{1}{3}\)
\(x=\frac{1}{3}×\frac{3}{5}\)
\(x=\frac{3}{15}=\frac{1}{5}\)
Vậy, \(x=\frac{1}{5}\)
b) \(x\div5=3\div7\)
\(x\div5=\frac{3}{7}\)
\(x=\frac{3}{7}×5\)
\(x=\frac{15}{7}\)
Vậy, \(x=\frac{15}{7}\)
c) \(x\div37=\frac{-2}{3×6}\)
\(x\div37=\frac{-5}{9}\)
\(x=\frac{-5}{9}×37\)
\(x=\frac{-185}{9}\)
Vậy, \(x=\frac{-185}{9}\)
Cbht
a)\(\dfrac{2,5}{7,5}=\dfrac{x}{\dfrac{3}{5}}\)
<=>\(x=\dfrac{2,5.\dfrac{3}{5}}{7,5}\)
<=>\(x=\dfrac{1,5}{7,5}=\dfrac{1}{5}=0,2\)
b)\(\dfrac{2\dfrac{2}{3}}{x}=\dfrac{1\dfrac{17}{9}}{2}\)
<=>\(\dfrac{\dfrac{8}{3}}{x}=\)\(\dfrac{\dfrac{26}{9}}{2}\)
<=>\(\dfrac{\dfrac{8}{3}.2}{\dfrac{26}{9}}=\dfrac{24}{13}\)
c)\(\dfrac{x-1}{1,5}=\dfrac{2,8}{0,5}\)
<=>\(x-1=\dfrac{1,5.2,8}{0,5}\)
<=>\(x-1=\dfrac{42}{5}=8,4\)
d)\(\dfrac{0,6}{x}=\dfrac{x}{2,4}\)
<=>\(x^2=0,6.2,4 \)
<=>\(x^2=\dfrac{36}{25}\)
<=>\(x=\sqrt{\dfrac{36}{25}}=\dfrac{6}{5}=1,2\)