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\(7,5x:\left(9-6\dfrac{13}{21}\right)=7.\left(\dfrac{3}{5}\right)^2\\ 7,5x:\left(9-\dfrac{139}{21}\right)=7.\dfrac{9}{25}\\ 7,5x:\left(\dfrac{189}{21}-\dfrac{139}{21}\right)=\dfrac{63}{25}\\ 7,5x:\dfrac{50}{21}=\dfrac{63}{25}\\ 7,5x=\dfrac{63}{25}.\dfrac{50}{21}\\ 7,5x=\dfrac{3150}{525}\\ 7,5x=\dfrac{207}{35}\\ \dfrac{15}{2}x=\dfrac{207}{35}\\ x=\dfrac{207}{35}:\dfrac{15}{2}\\ x=\dfrac{207}{35}.\dfrac{2}{15}\\ x=\dfrac{414}{525}\\ x=\dfrac{138}{175}\)
\(7,5x:\left(9-\frac{139}{21}\right)=\frac{63}{25}\)
\(7,5x:\left(\frac{189}{21}-\frac{139}{21}\right)=\frac{63}{25}\)
\(7,5x:\left(\frac{50}{21}\right)=\frac{63}{25}\)
\(7,5x=\frac{63}{25}.\frac{50}{21}\)
\(7,5x=6\)
\(x=6:7,5\)
\(x=\frac{4}{5}\)
vậy \(x=\frac{4}{5}\)
k mk nha vì mk đang âm điểm
7,5x:\(\frac{50}{21}\)=\(\frac{64}{25}\)
7,5x = \(\frac{64}{25}.\frac{50}{21}\)
7,5x = \(\frac{128}{21}\)
x = \(\frac{128}{21}:7,5\)
x = \(\frac{256}{315}\)
\(7,5x:\left[9-6\frac{13}{21}\right]=2\frac{13}{25}\)
\(\Leftrightarrow7,5x:\left[9-\frac{139}{21}\right]=\frac{63}{25}\)
\(\Leftrightarrow7,5x:\frac{50}{21}=\frac{63}{25}\)
\(\Leftrightarrow7,5x=\frac{63}{25}.\frac{50}{21}\)
\(\Leftrightarrow7,5x=6\)
\(\Leftrightarrow x=6:7,5\)
\(\Leftrightarrow x=\frac{4}{5}=0,8\)
(Chúc bạn học tốt và tíck cho mìk vs nha!)
a: =35/11-13/11-7/13-6/13
=2-1=1
b: =2+1/7+6/7+7/9-25/9
=2+1-2=1
c: \(=\dfrac{132}{321}\left(-\dfrac{103}{13}-\dfrac{27}{13}\right)=\dfrac{-132}{321}\cdot10=-\dfrac{440}{107}\)
\(a,2\frac{x}{7}=\frac{75}{35}\)
\(\frac{75}{35}=2\frac{5}{35}=2\frac{1}{7}\)
\(\Rightarrow x=1\)
\(b,47:4=...\left(+3\right)\)
\(\Rightarrow\left(47-3\right):4=11\)
\(\Rightarrow x=11\)
\(c,\frac{112}{5}=\frac{336}{15}=22\left(+6\right)\)
\(\Rightarrow x=22\frac{x=6}{15}\)
\(d,7,5x=\frac{75x}{100}:\left(9-6\frac{13}{21}\right)=2\frac{13}{25}\)
\(\frac{75x}{100}:\left(9-\frac{139}{21}\right)=\frac{63}{25}\)
\(\frac{75x}{100}:\frac{50}{21}=\frac{63}{25}\)
\(\Rightarrow\frac{63^3}{25^{\left(1\right)}}\cdot\frac{50^{\left(2\right)}}{21^1}=6=\frac{6}{1}\)
\(\Rightarrow\frac{6}{1}=\frac{600}{100}\)
Con d sai đề
\(x:(3\frac{1}{2}-5\frac{1}{6})=4\frac{1}{5}-6\frac{2}{3}\) b,\((2\frac{1}{3}+3\frac{1}{2})\cdot x=-4\frac{1}{4}+3\frac{1}{7}\)
\(x:\frac{-5}{3}\)=\(\frac{-37}{15}\) \(\frac{35}{6}\cdot x=\)\(\frac{-31}{28}\)
\(x=\frac{-37}{15}\cdot\frac{-5}{3}\) \(x=\frac{-31}{28}:\)\(\frac{35}{6}\)
\(x=\frac{37}{9}\) \(x=\frac{-93}{490}\)
Vậy x=\(\frac{37}{9}\) Vậy x=\(\frac{-93}{490}\)
7,5x:\((9-6\frac{13}{21})=2\frac{13}{25}\)
7,5x:\(\frac{50}{21}\)=\(\frac{63}{25}\)
7,5x=\(\frac{63}{25}:\frac{50}{21}=\frac{1323}{1250}\)
x=\(\frac{1323}{1250}:7,5\)
x=\(\frac{441}{3125}\)
Vậy x=\(\frac{441}{3125}\)
a) 22 + (2x -13) = 83 => 2x -13 = 61 => x = 37.
b) 51 - (-12 + 3x) = 27 => 63 - 3x = 27 => x = 12.
c) - (2x + 2) + 21 = - 23 => 2x + 2 = 44 => x = 21.
d) 25 - (25 - x) = 0 => 25 - 25 + x = 0 => x = 0.