Question

[Phạm Anh Tuấn bk]

Tìm các số nguyên x,y,z biết rằng:

X+y=2

Y+z=2

Z+x=-5

Answer 1

[Ngyễn Thái Thên Khánh]

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Answer 2

[Phùng Minh Quân]

Ta có x + y + y + z + z + x = 2 + 2 - 5 = -1

\(\Rightarrow\)2x + 2y + 2z = -1

\(\Rightarrow\)x + y + z = \(\frac{-1}{2}\)

Vậy

x = ( x + y + z ) - ( y + z ) = \(\frac{-1}{2}\)- 2 = -2,5

y = ( x + y + z ) - ( z + x ) = \(\frac{-1}{2}\)- (-5) = 4,5

z = ( x + y + z ) - ( x + y ) = \(\frac{-1}{2}\)- 2 = -2,5