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A. -14 - 7 - 12 - 24
= - 21 - 12 - 24
= - 33 - 24
= - 57
B. -10 - 14 - 16 + 43
= - 24 - 16 + 43
= - 40 + 43
= - 83
C. 32 + |-23| - 57 - (-23)
= 32 + 23 - 57 +23
= 55 - 57 + 23
= - 2 + 23
= 21
D. |-8| + |-4| - (-12) + 5
= 8 + 4 + 12 + 5
= 12 + 12 + 5
= 24 + 5
= 29
E. |-13| - |-17| + (-20) - (-18)
= 13 - 17 - 20 + 18
= - 4 - 17 - 20 + 18
= - 21 - 20 + 18
= - 41 + 18
= 23
A. -14-7-12-24=-21-36=-57
B. -10-14-16+43=-24+27=3
C.32+\(^{|-23|}\)-57-(-23)=32+23-57+23=55-80=-25
D.\(|-8|+|-4|\)-(-12)+5=8+4+12+5=12+17=29
E.\(|-13|-|-17|\)+(-20)-(-18)=13-17-20+18=-4-2=-6
Giải:
a) \(11\dfrac{3}{4}.\left(6\dfrac{5}{6}-4\dfrac{1}{2}+1\dfrac{2}{3}\right)\)
\(=\dfrac{47}{4}.\left(\dfrac{41}{6}-\dfrac{9}{2}+\dfrac{5}{3}\right)\)
\(=\dfrac{47}{4}.4\)
\(=47\)
b) \(\left(5\dfrac{7}{8}-2\dfrac{1}{4}-0,5\right):2\dfrac{23}{26}\)
\(=\left(\dfrac{47}{8}-\dfrac{9}{4}-\dfrac{1}{2}\right):\dfrac{75}{26}\)
\(=\dfrac{25}{8}:\dfrac{75}{26}\)
\(=\dfrac{13}{12}\)
c) \(\left(17\dfrac{13}{15}-3\dfrac{3}{7}\right)-\left(2\dfrac{12}{15}-4\right)\)
\(=\dfrac{268}{15}-\dfrac{24}{7}-\dfrac{14}{5}+4\)
\(=\left(\dfrac{268}{15}-\dfrac{14}{5}\right)+\left(\dfrac{-24}{7}+4\right)\)
\(=\dfrac{226}{15}+\dfrac{4}{7}\)
\(=\dfrac{1642}{105}\)
d) \(2\dfrac{2}{3}.\left(\dfrac{-4}{5}.0,375.-10.\dfrac{-15}{24}\right)\)
\(=\dfrac{8}{3}.\left(\dfrac{-4}{5}.\dfrac{3}{8}.-10.\dfrac{-5}{8}\right)\)
\(=\left(\dfrac{8}{3}.\dfrac{3}{8}\right).\left(\dfrac{-4}{5}.\dfrac{-5}{8}.-10\right)\)
\(=1.-5\)
\(=-5\)
Chúc bạn học tốt!
1/ -7264 + (1543 + 7264)
=-7264 + 1543 + 7264=1543
2/ (144 – 97) – 144
=144-97-144=-97
3/ (-145) – (18 – 145)(Vì có dấu trừ ở trước ngoặc nên p đổi dấu)
=-145-18+145=-18
4/ 111 + (-11 + 27)
=111-11+27=137
a. \(\begin{matrix}24=2^3.3\\10=2.5\end{matrix}\Rightarrow BCNN_{\left(24;10\right)}=2^3.3.5=120\)
Vậy...........
b. \(\begin{matrix}9=3^2\\24=2^3.3\end{matrix}\Rightarrow BCNN_{\left(9;24\right)}=2^3.3^2=72\)
Vậy...........
c, \(\begin{matrix}14=2.7\\21=3.7\\56=2^3.7\end{matrix}\Rightarrow BCNN_{\left(14;21;56\right)}=2^3.3.7=168\)
Vậy.........
d. \(\begin{matrix}8=2^3\\12=2^2.3\\15=3.5\end{matrix}\Rightarrow BCNN_{\left(8;12;15\right)}=2^3.3.5=120\)
Vậy........
e. \(\begin{matrix}12=2^2.3\\52=2^2.13\end{matrix}\Rightarrow BCNN_{\left(12;52\right)}=2^2.3.13=156\)
Vậy......
g. \(\begin{matrix}6=2.3\\8=2^3\\10=2.5\end{matrix}\Rightarrow BCNN_{\left(6;8;10\right)}=2^3.3.5=120\)
Vậy.........
h. \(\begin{matrix}9=3^2\\24=2^3.3\\35=5.7\end{matrix}\Rightarrow BCNN_{\left(9;24;35\right)}=2^3.3^2.5.7=2520\)
Vậy...........
C
C