M
1
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Các câu hỏi dưới đây có thể giống với câu hỏi trên
MD
8
24 tháng 7 2015
\(\frac{5+55+555+5555}{9+99+999+9999}=\frac{5.\left(1+11+111+1111\right)}{9.\left(1+11+111+1111\right)}=\frac{5}{9}\)
NT
5
30 tháng 7 2017
\(\frac{5+55+555+5555}{9+99+999+9999}=\frac{5.\left(1+11+111+1111\right)}{9.\left(1+11+111+1111\right)}=\frac{5}{9}\)\(\frac{5}{9}\)
dấu chấm bạn cứ hiểu là nhân nhé !
30 tháng 7 2017
\(\frac{5+55+555+5555}{9+99+999+9999}=\frac{5+11x5+111x5+1111x5}{9+11x9+111x9+1111x9}\)\(=\frac{5x5x5x5}{9x9x9x9}=\frac{625}{6561}\)
LH
24 tháng 7 2017
\(A=\frac{8\cdot4\cdot125\cdot25+96524+2476}{10\cdot125\cdot4\cdot25\cdot8}\)
\(A=\frac{1+96524+2476}{10}\)
\(A=\frac{99001}{10}\)
\(B=\frac{5+55+555+5555}{9+99+999+9999}\)
\(B=\frac{9}{5}\)
ML
26 tháng 7 2015
\(A=\left(10^2-1\right)+\left(10^3-1\right)+...+\left(10^{51}-1\right)\)
\(=-50+\left(10^2+10^3+...+10^{51}\right)\)
\(=-50+\frac{10^{52}-10^2}{10-1}=\frac{10^{52}-10^2}{9}-50\)
16 tháng 8 2017
999 + 3 + 98 + 998 + 3 + 9
= ( 999 + 1 ) + ( 98 + 2 ) + ( 998 + 2 ) + ( 99 + 1 ) + ( 9 + 1 )
= 1000 + 100 + 1000 + 100 + 10
= 2110
636 - 576 - 99 + 367
= ( 636 + 364 ) + 3 - ( 575 + 100 )
= 900 - ( 675 - 3 )
= 228
5034 - 997 - 998 - 999
= 5034 + 6 - ( 1000 + 1000 + 1000 )
= 5040 - 3000
= 2040
Mỏi tay quá k giúp mình nhé !!!!!!
23 tháng 7 2020
1)
\(\left(a\right)37+397+3997+39997\)
\(=40-3+400-3+4000-3+40000-3\)
\(=\left(40+400+4000+40000\right)-\left(3+3+3+3\right)\)
\(=44440-12=44428\)
\(\left(b\right)298+2998+29998+299998\)
\(=300-2+3000-2+30000-2+300000-2\)
\(=\left(300+3000+30000+300000\right)-\left(2+2+2+2\right)\)
\(=333300-8=333296\)
\(\left(c\right)9+99+999+9999+99999\)
\(=10-1+100-1+1000-1+10000-1+100000-1\)
\(=\left(10+100+1000+10000+100000\right)-\left(1+1+1+1+1\right)\)
\(=111110-5=111105\)
2)
\(\left(a\right)\left(2+4+6+...+2002+2004+2006\right)-\left(1+3+5+...+2001+2003+2005\right)\)
\(=\left(2-1\right)+\left(4-3\right)+\left(6-5\right)+...+\left(2002-2001\right)+\left(2004-2003\right)+\left(2006-2005\right)\)
\(=1+1+1+...+1+1+1\)( 1003 số 1 )
\(=1003\)
\(\left(b\right)88-87+86-85+84-83+...+6-5+4-3+2-1\)
\(=\left(88-87\right)+\left(86-85\right)+\left(84-83\right)+...+\left(6-5\right)+\left(4-3\right)+\left(2-1\right)\)
\(=1+1+1+...+1+1+1\)( 44 số 1 )
\(=44\)
\(\left(c\right)100-98+96-94+92-90+...+12-10+8-6+4-2\)
\(=\left(100-98\right)+\left(96-94\right)+\left(92-90\right)+...+\left(12-10\right)+\left(8-6\right)+\left(4-2\right)\)
\(=2+2+2+...+2+2+2\) ( 25 số 2 )
\(=50\)
3)
\(\left(a\right)360-357+354-351+348-345+...+312-309+306-303+300-297\)
\(=\left(360-357\right)+\left(354-351\right)+\left(348-345\right)+...+\left(312-309\right)+\left(306-303\right)+\)\(\left(300-297\right)\)
\(=3+3+3+3+3+3+3+3+3+3+3=33\)
\(\left(b\right)2006-1-2-3-4-...-47-48-49-50\)
\(=2006-\left(1+2+3+4+...+47+48+49+50\right)\)
\(=2006-\frac{\left(50+1\right)\left[\left(50-1\right)+1\right]}{2}\)
\(=2006-1275=731\)
\(\left(c\right)280-276+272-268+264-260+...+216-212+208-204+200-196\)
\(=\left(280-276\right)+\left(272-268\right)+\left(264-260\right)+...+\left(216-212\right)+\left(208-204\right)+\)\(\left(200-196\right)\)
\(=4+4+4+4+4+4+4+4+4+4+4=44\)
\(\frac{5+55+555+5555}{9+99+999+9999}=\)
\(=\frac{5x\left(1+11+111+1111\right)}{9x\left(1+11+111+1111\right)}=\frac{5}{9}\)