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a) \(\frac{81}{504}=\frac{81:9}{504:9}=\frac{9}{56}\)
b) \(\frac{-10101}{101010}=\frac{-10101:10101}{101010:10101}=\frac{-1}{10}\)
a)\(\frac{81}{504}\) = \(\frac{9}{56}\)
b)\(\frac{-10101}{101010}\) = \(\frac{-1}{10}\)
A=\(\frac{1.2.3.....20.\left(21.22.23.....39\right)}{\left(21.22.23.....39\right).40}\)
A=\(\frac{1.2.3.....20}{40}\)
A=\(1.3.4.5.....18.19\)
+2.20/40.
A=1.3.4.5.....18.19+1.
A= tự bấm máy là ra.
tk mk nha các bn.
-chúc ai tk mk học giỏi-
tA CÓ :
\(\frac{5.6+5.7}{5.8+20}=\frac{5\left(6+7\right)}{5.\left(8+4\right)}=\frac{5.13}{5.12}=\frac{13}{12}\)
\(\frac{8.9-4.15}{12.7-180}=\frac{3.4\left(2.3-5\right)}{12\left(7-15\right)}=\frac{12\left(6-5\right)}{12\left(7-15\right)}=\frac{6-5}{7-15}=\frac{1}{-8}\)
A = \(\frac{3^4\left(5.79-1\right)}{2^2.3^2\left(5.79-1\right)}=\frac{9}{4}\); B = \(\frac{3.7.13.37\left(5.11-1\right)}{4.3.7.13.37\left(3.5-1\right)}=\frac{54}{4.14}=\frac{2.9}{4.2.7}=\frac{9}{28}\)
Bài 1: Rút gọn phân số:
A=\(\frac{11}{21.10^2+10^2}\)
B=\(\frac{3.5.7.11.13.37-10101}{1313130+20202}\)
\(A=\frac{11}{21.10^2+10^2}=\frac{11}{10^2.\left(21+1\right)}=\frac{11}{10^2.22}=\frac{11}{10^2.11.2}=\frac{1}{10^2.2}\)
\(B=\frac{3.5.7.11.13.37-10101}{1313130+20202}=\frac{\left(3.5.7.11.13.37\right).5-10101.1}{130.10101+10101.2}=\frac{10101.\left(5-1\right)}{10101.\left(130+2\right)}=\frac{4}{132}=\frac{1}{33}\)
\(\frac{-1997\cdot1996+1}{-1995\cdot\left(-1997\right)+1996}\)
\(=\frac{-1997\cdot\left(1995+1\right)+1}{1995\cdot1997+1996}\)
\(=\frac{-1997\cdot1995+\left(-1997\right)+1}{1995\cdot1997+1996}\)
\(=\frac{-1997\cdot1995+\left(-1996\right)}{1995\cdot1997+1996}\)
\(=-1\)
\(\frac{-1997.1996+1}{-1995.\left(-1997\right)+1996}\)
\(=\frac{-1997.1996+1}{1995.1997+1996}\)
\(=\frac{-1997.\left(1995+1\right)+1}{1995.1997+1996}\)
\(=\frac{-1997.1995+-1997+1}{1995.1997+1996}\)
\(=\frac{1995.-1997+-1996}{1995.1997+1996}\)
\(=\frac{-\left(1995.1997+1996\right)}{1995.1997+1996}\)
\(=-1\)
a/ \(-\frac{81}{504}=-\frac{9}{56};-\frac{10101}{101010}=\frac{-1}{10}\)
b/ \(\frac{72\cdot5+72\cdot3}{144\cdot2+144\cdot6}=\frac{72\left(5+3\right)}{144\left(2+6\right)}=\frac{8}{2\cdot8}=\frac{1}{2}\)
\(\frac{-81}{504}=-\frac{81:9}{504:9}=-\frac{9}{56}\)
\(\frac{-10101}{101010}=\frac{-10101:10101}{101010:10101}=\frac{-1}{10}\)
\(\frac{72.5+72.3}{144.2+144.6}=\frac{72.\left(5+3\right)}{144\left(2+6\right)}=\frac{72.8}{144.8}=\frac{72.8}{72.2.8}=\frac{1}{2}\)