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{x2 - [62 - (64 -9 .7)3 -7.5]3 - 5.3}3=1
{x2 - [62 - (64 - 63)3 -7.5]3 - 5.3}3=1
{x2 - [62 - 13 -7.5]3 - 5.3}3=1
{x2 - [36 - 1 -7.5]3 - 5.3}3=1
{x2 - [36 - 1 - 35]3 - 5.3}3=1
{x2 - [35 - 35]3 - 5.3}3=1
{x2 - 03 - 5.3}3=1
{x2 - 0 -5.3}3=1
{x2 - 0 - 15}3=1
{x.x - 0 - 15}3=1
{x.x + 0+15}3=1
{x.x +15}3=1
nếu x bằng 1 thì:(1.1+15)3 không bằng 1
---------------2 thì:(2.2+15)3 ------------------1
-------------- 3 thì:(3.3+15)3-------------------1
-------------- 4 thì:(4.4+15)3 bằng 1
Vậy x bằng 4
a,\(\left(2x-1\right)^6=\left(2x-1\right)^8\)
\(\Leftrightarrow\left(2x-1\right)^6-\left(2x-1\right)^8=0\)
\(\Leftrightarrow\left(2x-1\right).\left[1-\left(2x-1\right)^2\right]=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x-1=0\\1-\left(2x-1\right)^2=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}2x=1\\\left(2x-1\right)^2=1\end{cases}}\Leftrightarrow\hept{\begin{cases}x=\frac{1}{2}\\2x-1=1\\2x-1=-1\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x=\frac{1}{2}\\2x=2\\2x=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=\frac{1}{2}\\x=1\\x=0\end{cases}}\)
\(b,5^x+5^{x+1}=650\)
\(\Leftrightarrow5^x+5^x.5^2=650\)
\(\Leftrightarrow5^x.\left(1+5^2\right)\)\(=650\)
\(\Leftrightarrow5^x.26=650\)
\(\Leftrightarrow5^x=650\div26\)
\(\Leftrightarrow5^x=25\)
\(\Leftrightarrow5^x=5^2\)
\(\Leftrightarrow x=2\)
\(c,3^{x-1}+5.3^{x-1}=162\)
\(\Leftrightarrow3^{x-1}.\left(1+5\right)=162\)
\(\Leftrightarrow3^{x-1}.6=162\)
\(\Leftrightarrow3^{x-1}=162\div6\)
\(\Leftrightarrow3^{x-1}=27\)
\(\Leftrightarrow3^{x-1}=3^3\)
\(\Leftrightarrow x-1=3\)
\(\Leftrightarrow x=3+1\)
\(\Leftrightarrow x=4\)
a: \(\Leftrightarrow4^x\left(\dfrac{3}{2}+\dfrac{5}{3}\cdot4^2\right)=4^8\left(\dfrac{3}{2}+\dfrac{5}{3}\cdot4^2\right)\)
=>4^x=4^8
=>x=8
b: \(\Leftrightarrow2^x\cdot\dfrac{1}{2}+2^x\cdot2=2^{10}\left(2^2+1\right)\)
=>2^x=2^11
=>x=11
c: =>1/6*6^x+6^x*36=6^15(1+6^3)
=>6^x=6*6^15
=>x=16
d: \(\Leftrightarrow8^x\left(\dfrac{5}{3}\cdot8^2-\dfrac{3}{5}\right)=8^9\left(\dfrac{5}{3}\cdot8^2-\dfrac{3}{5}\right)\)
=>x=9
a: (x-3)2=49
=>x-3=7 hoặc x-3=-7
=>x=10 hoặc x=-4
b: \(\left(x^4\right)^2=\dfrac{x^{12}}{x^5}\)
\(\Leftrightarrow x^8-x^7=0\)
\(\Leftrightarrow x^7\left(x-1\right)=0\)
=>x=0 hoặc x=1
c: \(\Leftrightarrow x^{10}-25x^8=0\)
\(\Leftrightarrow x^8\left(x^2-25\right)=0\)
\(\Leftrightarrow x^8\left(x-5\right)\left(x+5\right)=0\)
hay \(x\in\left\{0;5;-5\right\}\)
a) 3x+2 + 5.3x+1 = 648
=> 3x+1.3+ 5.3x+1= 648
=> 3x+1(3+ 5) = 648
=> 3x+1.8 = 648
=> 3x+1 = 81
=>3x+1= 34
=> x+1 = 4
=> x = 3
vậy x= 3
a,
5n + 5n + 2 = 650
=> 5n + 5n.52 = 650
=> 5n(1 + 52) = 650
=> 5n.26 = 650
=> 5n = 25
=> n = 2
a) 5n +5n+2 = 650
5n + 5n.52 = 650
5n.(1+25 ) = 650
5n.26= 650
5n = 25 = 52
=> n = 2
b) 3n+3 +5.3n = 864
3n.33 +5.3n = 864
3n.(33+5) = 864
3n.32 = 864
3n = 27 = 33
=> n = 3
các bài cn lại bn dựa vào mak lm nha!