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a) Ta có: 302^(2x-6) +45 = 46
=> 302^(2x-6) = 1 = 302^0
=> 2x-6 = 0
=> 2x = 6
=> x = 3
b) Ta có: (x+1)+(x+2)+(x+3)+....+(x+100)=5950
=> 100x+ (1+2+3+4+...+100) = 5950
=> 100x + 5050 = 5950
=> 100x = 900
=> x = 9
Nhấn đúng cho mk nha!!!!!!!!
26 + 8.x=6.x +46
8x = 6x + 46 -26
8x - 6x = 46 - 26
2x = 20
x = 20 : 2 = 10
a) \(\left(x+\frac{1}{4}-\frac{1}{3}\right):\left(2+\frac{1}{6}-\frac{1}{4}\right)=\frac{7}{46}\)
\(\left(x-\frac{1}{12}\right):\left(2-\frac{1}{12}\right)=\frac{7}{46}\)
\(\left(x-\frac{1}{12}\right):\frac{23}{12}=\frac{7}{46}\)
\(x-\frac{1}{12}=\frac{7}{46}.\frac{23}{12}\)
\(x-\frac{1}{12}=\frac{7}{24}\)
\(x=\frac{7}{24}+\frac{1}{12}\)
\(x=\frac{3}{8}\)
Vậy \(x=\frac{3}{8}\)
b) \(\frac{13}{15}-\left(\frac{13}{21}+x\right).\frac{7}{12}=\frac{7}{10}\)
\(\frac{13}{15}-\left(\frac{13}{21}+x\right)=\frac{7}{10}:\frac{7}{12}\)
\(\frac{13}{15}-\left(\frac{13}{21}+x\right)=\frac{7}{10}.\frac{12}{7}\)
\(\frac{13}{15}-\left(\frac{13}{21}+x\right)=\frac{6}{5}\)
\(\frac{13}{21}+x=\frac{13}{15}-\frac{6}{5}\)
\(\frac{13}{21}+x=\frac{-1}{3}\)
\(x=\frac{-1}{3}-\frac{13}{21}\)
\(x=\frac{-20}{21}\)
Vậy \(x=\frac{-20}{21}\)
=>x+x+x+...+x+1+6+..+46=6655
=>10x +235=6655
=>10x=6420
=>x=642
tickkkk nha