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Ta có :
\(C=\frac{3^2}{8.11}+\frac{3^2}{11.14}+\frac{3^2}{14.17}+...+\frac{3^2}{197.200}\)
\(C=3\left(\frac{3}{8.11}+\frac{3}{11.14}+\frac{3}{14.17}+...+\frac{3}{197.200}\right)\)
\(C=3\left(\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{17}+...+\frac{1}{197}-\frac{1}{200}\right)\)
\(C=3\left(\frac{1}{8}-\frac{1}{200}\right)\)
\(C=3.\frac{3}{25}\)
\(C=\frac{9}{25}\)
Chúc bạn học tốt ~
N=3(3/8.11 +3 /11.14 + 3/14.17 +...+3/197.200)
N=3( 1/8-1/11+1/11-1/14+1/14-1/17+...+1/197-1/200)
N=3(1/8-1/200)
N=3. 3/25=9/25
Ủng hộ mk nha
\(\Rightarrow N=\frac{9}{8.11}+\frac{9}{11.14}+\frac{9}{14.17}+....+\frac{9}{197.200}\)
\(\Rightarrow N=\frac{9}{3}\left(\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+...+\frac{1}{197}-\frac{1}{200}\right)\)
\(\Rightarrow N=3\left(\frac{1}{8}-\frac{1}{200}\right)=\frac{3}{8}-\frac{3}{200}=\frac{75}{200}-\frac{3}{200}=\frac{72}{200}=\frac{9}{25}\)
\(\frac{3^2}{8\cdot11}+\frac{3^2}{11\cdot14}+\frac{3^2}{14\cdot17}+...+\frac{3^2}{197\cdot200}\)
\(=3(\frac{1}{8}-\frac{1}{11}+...+\frac{1}{197}-\frac{1}{200})\)
\(=3(\frac{1}{8}-\frac{1}{200})\)
\(=3\cdot\frac{3}{25}=\frac{9}{25}\)
=3(1\(= 3(3/8.11+3/11.14+...+3/197.200) = 3(1/8-1/11+1/11-1/14+...+1/197-1/200) =3(1/8-1/200) =3/8-3/200 đề bạn ghi có chỗ nhầm nha \)
=3(\(\frac{3}{8.11}\)+\(\frac{3}{11.14}\)+...+\(\frac{3}{1997.2000}\))
=3(\(\frac{1}{8}\)-\(\frac{1}{11}\)+\(\frac{1}{11}\)-\(\frac{1}{14}\)+...+\(\frac{1}{1997}\)-\(\frac{1}{2000}\))
=3(\(\frac{1}{8}\)-\(\frac{1}{2000}\))=3.\(\frac{249}{2000}\)=\(\frac{747}{2000}\)
\(A=3.\left(\frac{3}{8.11}+\frac{3}{11.14}+...+\frac{3}{1997.2000}\right)\)
\(=3.\left(\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+...+\frac{1}{1997}-\frac{1}{2000}\right)\)
\(=3.\left(\frac{1}{8}-\frac{1}{2000}\right)\)
\(=3.\frac{249}{2000}\)
\(\frac{747}{2000}\)
=1,798