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\(a,\frac{12}{25}+\frac{3}{5}+\frac{13}{25}\)
\(=\left(\frac{12}{25}+\frac{13}{25}\right)+\frac{3}{5}\)
\(=\frac{25}{25}+\frac{3}{5}\)
\(=1+\frac{3}{5}\)
\(=\frac{8}{5}\)
\(b,\frac{3}{2}+\frac{2}{3}+\frac{4}{3}\)
\(=\frac{3}{2}+\left(\frac{2}{3}+\frac{4}{3}\right)\)
\(=\frac{3}{2}+2\)
\(=\frac{7}{2}\)
\(c,\frac{3}{5}+\frac{7}{5}+\frac{3}{4}\)
\(=\left(\frac{3}{5}+\frac{7}{5}\right)+\frac{3}{4}\)
\(=2+\frac{3}{4}\)
\(=\frac{11}{4}\)
a) 145 + 86 + 14 + 55 = ( 145 + 55 ) + (86 + 14 )
= 200 + 100
= 300
b) 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = ( 1+9 +2 + 8) + ( 3 + 7 + 4 + 6 ) + 5
= 20 + 20 + 5
= 45
bài 7.
a. 5x2x123= 10 x 123 = 1230
b.2x5 x 34= 10 x 34 = 340
c. 2x5x3x4= 10x 12= 120
d. 20x5x6x7= 100 x 42= 4200
a) \(\frac{12}{25}+\frac{3}{5}+\frac{134}{25}=\left(\frac{12}{25}+\frac{134}{25}\right)+\frac{3}{5}=\frac{146}{25}+\frac{3}{5}=\frac{146}{25}+\frac{15}{25}=\frac{161}{25}\)
b) \(\frac{3}{2}+\frac{2}{3}+\frac{4}{3}=\frac{3}{2}+\left(\frac{2}{3}+\frac{4}{3}\right)=\frac{3}{2}+\frac{6}{3}=\frac{9}{6}+\frac{12}{6}=\frac{21}{6}=\frac{7}{2}\)
c) \(\frac{3}{5}+\frac{7}{5}+\frac{3}{4}=\left(\frac{3}{5}+\frac{7}{5}\right)+\frac{3}{4}=\frac{10}{5}+\frac{3}{4}=2+\frac{3}{4}=\frac{8}{4}+\frac{3}{4}=\frac{11}{4}\)
a,\(\frac{12}{25}+\frac{3}{5}+\frac{134}{25}=\frac{12}{25}+\frac{15}{25}+\frac{134}{25}=\frac{161}{25}\)
b, \(\frac{3}{2}+\frac{2}{3}+\frac{4}{3}=\frac{3}{2}+\left(\frac{2}{3}+\frac{4}{3}\right)=\frac{3}{2}+\frac{6}{3}=\frac{3}{2}+2=\frac{7}{2}\)
c, \(\left(\frac{3}{5}+\frac{7}{5}\right)+\frac{3}{4}=\frac{10}{5}+\frac{3}{4}=2+\frac{3}{4}=\frac{11}{4}\)
\(\frac{3}{4}+\frac{2}{5}+\frac{1}{4}+\frac{3}{5}\)
\(\Leftrightarrow\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{2}{5}+\frac{3}{5}\right)\)
\(=1+1\)
\(=2\)
\(\frac{3}{4}+\frac{2}{5}+\frac{1}{4}+\frac{3}{5}.\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{2}{5}+\frac{3}{5}\right)\)
\(=\frac{4}{4}+\frac{5}{5}\)
\(=1+1\)
\(=2\)
a) = (360 + 126 + 123) : 3 = 203
b) = (436 + 164 - 200) : 4 = 100
c) = (525 + 120 - 145) : 5 = 100