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a, cách 1 : 7/11 : 3/5 + 4/11 : 3/5 b, cách 1 : [ 6,24 + 1,26 ] : 0,75
=[ 7/11 + 4/11 ] : 3/5 = 7,5 : 0,75
= 1 : 3/5 = 10
= 5/3 cách 2 : [ 6,24 + 1,26 ] : 0,75
cách 2 :7/11 : 3/5 + 4/11 : 3/5 = 6,24 : 0,75 + 1,26 : 0,75
=35/33 + 20/33 = 8,32 + 1,68
=55/33 = 10
=5/3
\(\frac{7}{11}:\frac{3}{5}+\frac{4}{11}:\frac{3}{5}\)
= ( \(\frac{7}{11}+\frac{4}{11}\)) : \(\frac{3}{5}\)
= 1 : \(\frac{3}{5}\)
= \(\frac{5}{3}\)
C1 : \(\frac{7}{11}:\frac{3}{5}+\frac{4}{11}:\frac{3}{5}=\frac{35}{33}+\frac{20}{33}=\frac{55}{33}=\frac{5}{3}\)
C2: \(\frac{7}{11}:\frac{3}{5}+\frac{4}{11}:\frac{3}{5}=\left(\frac{7}{11}+\frac{4}{11}\right):\frac{3}{5}=1:\frac{3}{5}=\frac{5}{3}\)
Ta có ; \(\frac{3}{7}\times\frac{4}{11}+\frac{3}{7}\times\frac{5}{11}+\frac{1}{2}\)
\(=\frac{3}{7}\times\left(\frac{4}{11}+\frac{5}{11}\right)+\frac{1}{2}\)
\(=\frac{3}{7}\times\frac{9}{11}+\frac{1}{2}\)
\(=\frac{27}{77}+\frac{1}{2}\)
\(=\frac{131}{154}\)
a)=384:(25*4)=384:100=3,84.
b)37/25:5/4:74/25=37/25*4/5*25/74=37*4*25/5*25*74=2/5.
c)380:(38*2)=(380:38):2=10:2=5.
d)6/11:4/3:5/11:4/3=6/11*3/4*11/5*3/4=6*3*11*3/11*4*5*4=27/40.
k nha
a= (\(\frac{2}{5}\)+\(\frac{2}{9}\)+\(\frac{2}{11}\)\(\times\)\(\frac{5}{7}\)\(+\frac{7}{9}\)\(+\frac{7}{11}\)\()\)
C1 : \(\frac{7}{11}\):\(\frac{3}{5}\)+\(\frac{4}{11}\):\(\frac{3}{5}\)
=\(\frac{7}{11}\)x\(\frac{5}{3}\)+\(\frac{4}{11}\)x\(\frac{5}{3}\)
=\(\frac{35}{33}\)+\(\frac{20}{33}\)
=\(\frac{55}{33}\)=\(\frac{5}{3}\)
C2: \(\frac{7}{11}\):\(\frac{3}{5}\)+\(\frac{4}{11}\):\(\frac{3}{5}\)
= \(\frac{3}{5}\)x (\(\frac{7}{11}\)+\(\frac{4}{11}\))
=\(\frac{3}{5}\)x 1= \(\frac{3}{5}\)
\(C1:\frac{7}{11}:\frac{3}{5}+\frac{4}{11}:\frac{3}{5}\)
\(=\frac{7}{11}x\frac{5}{3}+\frac{4}{11}x\frac{5}{3}\)
\(=\frac{35}{33}+\frac{20}{33}\)
\(=\frac{55}{33}=\frac{5}{3}\)
\(C2:\frac{7}{11}:\frac{3}{5}+\frac{4}{11}:\frac{3}{5}\)
\(=\frac{7}{11}x\frac{5}{3}+\frac{4}{11}x\frac{5}{3}\)
\(=\frac{5}{3}x\left(\frac{7}{11}+\frac{4}{11}\right)\)
\(=\frac{5}{3}x1=\frac{5}{3}\)