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\(\frac{x+9}{13-x}=\frac{6}{5}\)
\(\Rightarrow\orbr{\begin{cases}x+9=6\\13-x=5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-3\\x=8\end{cases}}\)
\(\frac{120-x}{30}=3\frac{1}{2}\)
\(\Rightarrow\frac{120-x}{30}=\frac{7}{2}\)
\(\Rightarrow\frac{120-x}{30}=\frac{105}{30}\)
\(\Rightarrow120-x=105\)
\(\Rightarrow x=120-105\)
\(\Rightarrow x=15\)
a) x + 5,84 = 9,16
=> x = 9,16 - 5,84
x = 3,32
b) \(x=\frac{1}{5}-\frac{3}{7}\)
=> x = \(\frac{-8}{35}\)
c) \(\frac{x}{5}=\frac{5}{6}-\frac{13}{30}\)
=> \(\frac{x}{5}=\frac{2}{5}\)
=> \(x=5\)
d) \(x+\frac{3}{4}=\frac{4}{5}\)
=> x = \(\frac{4}{5}-\frac{3}{4}\)
x = \(\frac{1}{20}\)
e) \(\frac{x}{7}=\frac{7}{8}-\frac{25}{56}\)
=> \(\frac{x}{7}=\frac{3}{7}\)
=> x = 3
t i c k nhé!! 426356457467568768467356457568578769578956
Câu a,x=9,16-5,84=3,32
Câu b, d bạn làm tương tự như câu a
Câu c,e bạn làm thế này, mik chỉ làm mẫu 1 câu thôi
c, x/5 = 25/30 - 13/30
x/5 = 12/30
x/5 = 2/5
x = 2/5 : 5
x = 2/5 X 1/5
x = 2/25
Vậy x=2/25
Câu e làm tương tự như vậy nhé.Bạn tính phần hiệu bên phải rồi lấy nó nhân với mẫu số của x là ra thôi.
Ủng hộ nhé
a) \(\frac{24}{x}=\frac{3}{5}.\frac{8}{3}\)
\(\frac{24}{x}=\frac{8}{5}\)
\(x=\frac{24.5}{8}\)
\(x=15\)
b) \(2.x=24\frac{1}{4}-3\frac{1}{2}\)
\(2.x=\frac{83}{4}\)
\(x=\frac{83}{8}\)
Câu c, d làm tương tự, đơn giản
a) (1,5 . 1,9 - x - 0,5) : 0,25 = 7,5 : 0,125
=> (2,85 - x - 0,5) : 0,25 = 60
=> (2,85 - 0,5) - x = 60 . 0,25
=> 2,35 - x = 15
=> x = 2,35 - 15
=> x = -12,65
Vậy x = -12,65
b) \(1-\left(5\frac{2}{9}+x-7\frac{7}{18}\right)\div2\frac{1}{6}=0\)
\(\Rightarrow\left(5\frac{2}{9}-7\frac{7}{18}+x\right)\div2\frac{1}{6}=1-0\)
\(\Rightarrow\left(\frac{47}{9}-\frac{133}{18}+x\right)\div2\frac{1}{6}=1\)
\(\Rightarrow\frac{-13}{6}+x=2\frac{1}{6}\)
\(\Rightarrow x=2\frac{1}{6}-\frac{-13}{6}\)
\(\Rightarrow x=\frac{13}{6}+\frac{13}{6}\)
\(\Rightarrow x=\frac{26}{6}\)
\(\Rightarrow x=\frac{13}{3}\)
Vậy \(x=\frac{13}{3}\)
c) \(35\left(2\frac{1}{5}-x\right)=32\)
\(\Rightarrow2\frac{1}{5}-x=32\div35\)
\(\Rightarrow\frac{11}{5}-x=\frac{32}{35}\)
\(\Rightarrow x=\frac{11}{5}-\frac{32}{35}\)
\(\Rightarrow x=\frac{9}{7}\)
Vậy \(x=\frac{9}{7}\)
d) \(\frac{4}{3}+\left(x\div2\frac{2}{3}-0,5\right).1\frac{35}{55}=0,6\)
\(\Rightarrow\left(x\div\frac{8}{3}-\frac{1}{2}\right).\frac{18}{11}=\frac{3}{5}-\frac{4}{3}\)
\(\Rightarrow\left(x\div\frac{8}{3}-\frac{1}{2}\right).\frac{18}{11}=\frac{-11}{15}\)
\(\Rightarrow x\div\frac{8}{3}-\frac{1}{2}=\frac{-11}{15}\div\frac{18}{11}\)
\(\Rightarrow x\div\frac{8}{3}-\frac{1}{2}=\frac{-121}{270}\)
\(\Rightarrow x\div\frac{8}{3}=\frac{-121}{270}+\frac{1}{2}\)
\(\Rightarrow x\div\frac{8}{3}=\frac{7}{135}\)
\(\Rightarrow x=\frac{7}{135}.\frac{8}{3}\)
\(\Rightarrow x=\frac{56}{405}\)
Vậy \(x=\frac{56}{405}\)
e) \(1\frac{1}{3}.2\frac{2}{4}\div\frac{5}{6}.1\frac{1}{11}=11-5\div x\)
\(\Rightarrow\frac{4}{3}.\frac{5}{2}\div\frac{5}{6}.\frac{12}{11}=11-5\div x\)
\(\Rightarrow\frac{10}{3}\div\frac{5}{6}.\frac{12}{11}=11-5\div x\)
\(\Rightarrow4.\frac{12}{11}=11-5\div x\)
\(\Rightarrow11-5\div x=\frac{48}{11}\)
\(\Rightarrow5\div x=11-\frac{48}{11}\)
\(\Rightarrow5\div x=\frac{73}{11}\)
\(\Rightarrow x=5\div\frac{73}{11}\)
\(\Rightarrow x=\frac{55}{73}\)
Vậy \(x=\frac{55}{73}\)
a) (1,5 * 1,9 - x - 0,5) : 0,25 = 7,5 : 0,125
(2,85 - x - 0,5) : 0,25 = 60
(2,85 - x - 0,5) = 60 x 0,25
(2,85 - x - 0,5) = 15
2,35 - x = 15
x = 2,35 - 15
x = -12,65
Ta có : x . x/5 . 7,5 + x/2 . 9 = 315
=> x . ( x/5 . 7,5 ) + 9x/2 = 315
=> x . ( 7,5x / 5 ) + 4,5 . x = 315
=> x . 1 , 5 . x + 4,5 . x = 315
=> 1 , 5 . x ( x + 3 ) = 315
=> x.( x + 3 ) = 315 : 1,5
=> x . ( x + 3 ) = 210
=> x = 13 ( dư 2 )
\(\dfrac{3}{4}\times\dfrac{8}{5}:1\dfrac{1}{6}\)
=\(\dfrac{6}{5}:\) \(\dfrac{7}{6}\)
=\(\dfrac{6}{5}\times\dfrac{6}{7}=\dfrac{36}{35}\)
2\(\dfrac{1}{3}\) x 1\(\dfrac{1}{4}\) -\(\dfrac{7}{5}\)
\(\dfrac{7}{3}\times\dfrac{5}{4}-\) \(\dfrac{7}{5}\)
\(\dfrac{35}{12}-\dfrac{7}{5}\)
\(\dfrac{175}{60}-\dfrac{84}{60}=\dfrac{91}{60}\)
4\(\dfrac{2}{3}+1\dfrac{1}{4} +2\dfrac{1}{3}+2\dfrac{3}{7}\)
(4 +2) + \(\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\) +1\(\dfrac{1}{4}\) + \(2\dfrac{3}{7}\)
6 + 1 + \(\dfrac{5}{4}\) + \(\dfrac{17}{7}\)
7 + \(\dfrac{103}{28}\)
\(\dfrac{299}{28}\)
tổng không đổi,tổng lúc đầu là:13+9=22
9+x là:22:(5+6)x5=10
vậy x=1
ta có
\(\frac{9+X}{13-X}\)=\(\frac{5}{6}\)\(\Leftrightarrow\)6(9+X)=5(13-x)\(\Leftrightarrow\)54+6x=65-5x\(\Leftrightarrow\)11x=11\(\Leftrightarrow\)x=1
a) Ta có : \(\frac{35}{91}\)= \(\frac{5}{13}=\frac{x}{13}\Rightarrow x=5\)
b, ta có
<=>6 (9+x)=5 (13-x)
<=>54+6x=65-5x
<=>6x+5x=65-54
<=>11x=11
<=>x=1