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Theo đề ta có:
\(5.3^{3x+2}-27^{x+1}=486\)
\(\Rightarrow5.27^x.9-27^x.27=486\)
\(\Rightarrow27^x\left(45-27\right)=486\)
\(\Rightarrow27^x.18=486\)
\(\Rightarrow27^x=\frac{486}{18}\)
\(\Rightarrow27^x=27\)
\(\Rightarrow27^x=27^1\)
\(\Rightarrow x=1\)
vậy \(x=1\)
Giang ho dai ca viet nham nhé:
\(5.3^x=8.3^9+7.27^3\)
<=> \(5.3^x=8.3^9+7.\left(3^3\right)^3\) <=> \(5.3^x=8.3^9+7.3^9\)
<=> \(5.3^x=15.3^9\) <=> \(3^x=3.3^9=3^{10}\) => x = 10
nhầm chỉnh lại :
\(5.3^x=8.3^9+7.27^3\Rightarrow5.3^x=8.3^9+7.3^9=15.3^9\Rightarrow15.3^{x-1}=15.3^9\Rightarrow3^{x-1}=3^9\Rightarrow x-1=9\Rightarrow x=10\)
\(\dfrac{81^4.3^{10}.27^5.3^{12}}{3^{18}.9^3.243^2}\)
=\(\dfrac{\left(3^4\right)^4.3^{10}.\left(3^3\right)^5.3^{12}}{3^{18}.\left(3^2\right)^3.\left(3^5\right)^2}\)
= \(\dfrac{3^{16}.3^{10}.3^{15}.3^{12}}{3^{18}.3^6.3^{10}}\)
\(=\dfrac{3^{53}}{3^{34}}\)
= \(3^{19}\)
\(\left(\frac{4}{9}\right)^x=\left(\frac{8}{27}\right)^{10}\)
\(\left(\frac{2^2}{3^2}\right)^x=\left(\frac{2^3}{3^3}\right)^{10}\)
\(\left(\frac{2}{3}\right)^{2x}=\left(\frac{2}{3}\right)^{30}\)
\(\Rightarrow2x=30\)
\(\Rightarrow x=15\)
vay \(x=15\)
5.3x+2 - 2.3x-2 = 3627
=> 3x-2 .( 5.34 - 2.1 ) = 3627
=> 3x-2 .( 5.81 - 2 ) = 3627
=> 3x-2 .( 405 - 2 ) = 3627
=> 3x-2 .403 = 3627
=> 3x-2 = 3627 : 403
=> 3x-2 = 9 = 32
=> x - 2 = 2
=> x = 2 + 2
x = 4
Vậy: x = 4
a: (x-3)2=49
=>x-3=7 hoặc x-3=-7
=>x=10 hoặc x=-4
b: \(\left(x^4\right)^2=\dfrac{x^{12}}{x^5}\)
\(\Leftrightarrow x^8-x^7=0\)
\(\Leftrightarrow x^7\left(x-1\right)=0\)
=>x=0 hoặc x=1
c: \(\Leftrightarrow x^{10}-25x^8=0\)
\(\Leftrightarrow x^8\left(x^2-25\right)=0\)
\(\Leftrightarrow x^8\left(x-5\right)\left(x+5\right)=0\)
hay \(x\in\left\{0;5;-5\right\}\)
\(\left(\frac{4}{9}\right)^x=\left(\frac{8}{27}\right)^{10}\)
\(\Leftrightarrow\left(\frac{2}{3}\right)^{2x}=\left(\frac{2}{3}\right)^{30}\)
\(\Leftrightarrow2x=30\Leftrightarrow x=15\)
Bài làm
Ta có: \(\left(\frac{4}{9}\right)^x=\left(\frac{2}{3}\right)^{2x}\)
\(\left(\frac{8}{27}\right)^{10}=\left(\frac{2}{3}\right)^{3.10}=\left(\frac{2}{3}\right)^{30}\)
\(\Rightarrow\left(\frac{2}{3}\right)^{2x}=\left(\frac{2}{3}\right)^{30}\)
\(\Rightarrow2x=30\)
\(\Rightarrow x=15\)
Vậy \(x=15\)
# Học tốt #
\(3^{15}.3^x=3^{20}\)
\(3^{15+x}=3^{20}\)
\(\Rightarrow15+x=20\)
\(x=5\)
275 . 3x = 910
=> 3x = 910 : 275
=> 3x = 92.5 : 275
=> 3x = ( 92)5 : 275
=> 3x = 815 : 275
=> 3x = 35
=> x = 5
Vậy x = 5