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\(4x^3+15=47\)
\(4x^3=47-15\)
\(4x^3=32\)
\(x^3=32:4\)
\(x^3=8\)
\(x^3=2^3\)
\(\Rightarrow x=2\)
\(4.2^x-3=125\)
\(4.2^x=125+3\)
\(4.2^x=128\)
\(2^x=128:4\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
\(4x^3+15=47\)
\(4x^3=47-15\)
\(4x^3=32\)
\(x^3=32:4\)
\(x^3=8\)
\(x^3=2^3\)
\(\Rightarrow x=2\)
\(4.2^x-3=125\)
\(4.2^x=125+3\)
\(4.2^x=128\)
\(2^x=128:4\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
a) 4x3+15=47
=> 4x3=47-15
=> 4x3=32
=> x3=32:4
=> x3=23
=> x=2
b) 4.2x-3=125
=> 4.2x=125+3
=> 2x=128:4
=> 2x=32
=> 2x=25
=> x=5
4x3 + 15 = 47
4x3 = 47 - 15
4x3 = 32
x3 = 32 : 4
x3 = 8
x3 = 23
x = 2
b) 4 . 2x - 3 = 125
4 . 2x = 125 + 3
4 . 2x = 128
2x = 128 : 4
2x = 32
2x = 25
x = 5
a)4x3+15=47
4x3=47-15
4x3=32
x3=32:4
x3=8
x3=23
vậy x = 2
b)4.2x-3=125
4.2x=125+3
4.2x=128
2x=128:4
2x=32
2x=25
Vậy x=5
a) 4x3 + 15 = 47 b) 4.2x - 3 = 125
4x3 = 47 - 15 4.2x = 125 + 3
4x3 = 32 4.2x = 128
x3 = 32 : 4 2x = 128 : 4
x3 = 8 2x = 32
x3 = 23 2x = 25
=> x = 2 => x = 5
Giải:
a) \(70-5\left(x-3\right)=45\)
\(5\left(x-3\right)=70-45\)
\(5\left(x-3\right)=25\)
\(x-3=25:5\)
\(x-3=5\)
\(x=5+3\)
\(x=8\)
70 - 5 ( x - 3 ) = 45
5 ( x - 3 ) = 70 - 45
5 ( x - 3 ) = 25
x - 3 = 25 : 5
x - 3 = 5
=> x = 8
10 + 2 . x = 45 : 43
10 + 2 . x = 42
10 + 2 . x = 16
2 . x = 16 + 10
2 . x = 26
=> x = 13
231 - ( x - 6 ) = 1339 : 13
231 - ( x - 6 ) = 103
x - 6 = 231 - 103
x - 6 = 128
=> x = 134
2 . x - 138 = 23 . 32
2 . x - 138 = 72
2 . x = 72 + 138
2 . x = 210
=> x = 105
a) (3x - 1)2 = 100
(3x - 1)2 = 102
=>3x - 1 = 10
=> 3x = 10 + 1
3x = 11
x = 11/3
a/ => 2x = 32 => 2x = 25 => x = 5
b/ => x15 - x = 0
=> x (x14 - 1) = 0
=> x = 0
hoặc x14 - 1 = 0 => x14 = 1 => x14 = 114 => x =1
Vậy x = 0 ; x = 1
c/ => (2x + 1)3 = 53 => 2x + 1 = 5 => 2x = 4 => x = 2
d/ => (x - 5)4 - (x - 5)6 = 0
=> (x - 5)4 [1 - (x - 5)2 ] = 0
=> (x - 5)4 = 0 => x -5 = 0 => x = 5
hoặc 1 - (x - 5)2 = 0 => 1 - x2 + 10x - 25 = 0 => -x2 + 10x - 24 = 0 => (6 - x)(x - 4) = 0
=> 6 - x = 0 => x = 6
hoặc x - 4 = 0 => x = 4
Vậy x = 4; x = 5; x = 6
Ta có : x15 : 55 = 125
=> x15 : 55 = 53
=> x15 = 53 . 55
=> x15 = 58
Đề sai nhé !
a, \(4x^2+15=47\\ =>4x^2=47-15=32\\ =>x^2=32:4=8\\ =>x\ne N\)
b, \(4.2^x-3=125\\ =>4.2^x=125+3=128\\ =>2^x=128:4=32\\ Mà:2^5=32\\ =>x=5\)
a) 4\(x^2\)+ 15 = 47
=> 4\(x^2\) = 47 - 15
=> 4\(x^2\)= 32
=> \(x^2\)= 32 : 4
=> \(x^2\)= 8
=> \(x\) \(\ne\) N
b) 4. \(2^x\) - 3 = 125
=> 4.2\(^x\)= 125 + 3
=> 4. \(2^x\)= 128
=> \(2^x\)= 128 : 4
=> \(2^x\)= 32
Mà \(2^5\) = 32 nên \(x\) = 5