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Ta có A =1.2 + 2.3 + 3.4 + ...+ 98.99
B = 1^2 + 2^2 + 3^2 +...+98^2 = 1.1+2.2+3.3+...+98.98
Suy ra: A-B= (1.2 + 2.3 + 3.4 + ...+ 98.99) - (1.1+2.2+3.3+...+98.98)
= (1.2-1.1) + (2.3-2.2) + (3.4-3.3) +...+ (98.99-98.98)
= 1(2-1) + 2(3-2) + 3(4-3) +...+ 98(99-98)
= 1.1 + 2.1 + 3.1 +...+ 98.1
= 1+ 2+ 3+...+ 98 = [98.(98+1)]/2= 98.99/2 = 4851
đúng nha
A = 1.2 + 2.3 + 3.4 + ... + 98.99
= 1.(1 + 1) + 2.(2 + 1) + 3.(3 + 1) + ... + 98.(98 + 1)
= 12 + 1 + 22 + 2 + 32 + 3 + ... + 982 +98
= (12 + 22 + 32 + ... + 982) + (1 + 2 + 3 + ... + 98)
= B + (1 + 98).98 : 2
= B + 4851
Do đó A = B + 4851 suy ra A - B = 4851
Kết luận : A - B = 4851
C1 : B=\(\frac{1^2}{1.2}.\frac{2^2}{2.3}......\frac{98^2}{98.99}\)=\(\frac{1.1}{1.2}.\frac{2.2}{2.3}......\frac{98.98}{98.99}\)=\(\left(\frac{1.2......98}{1.2.....98}\right).\left(\frac{1.2......98}{2.3......99}\right)\)
\(1.\frac{1}{99}=\frac{1}{99}\)
C2:Đầu tiên cũng tách ra:\(1^2\)=1.1;\(2^2\)=2.2;...;\(98^2\)=98.98
Xong rút gọn ở tử và mẫu được:\(\frac{1}{2}.\frac{2}{3}.......\frac{98}{99}=\frac{1.2.....98}{2.3.....99}=\frac{1}{99}\)
Bạn thấy cách nào rễ hiểu hơn thì ghi nhé
Ta có A=1.2+2.3+3.4+...+98.99
B=1^2+2^2+3^2+...+98^2=1.1+2.2+3.3+...+98.98
=> A-B=(1.2+2.3+3.4+...98.99)-(1.1+2.2+3.3+...+98.98)
=(1.2-1.1)+(2.3-2.2)+(3.4-3.3)+...+(98.99-98.98)
=1.(2-1)+2.(3-2)+3.(4-3)+...+98.(99-98)
=1.1+2.1+3.1+...98.1
=1+2+3+...+98=[98.(98+1)]/2=98.99/2=4851
đúng nha
Ta có:a=1.2+2.3+3.4+...+98.99
a=1(1+1)+2(2+1)+3(3+1)+...+98(98+1)
a=12+1+22+2+33+3+...+982+98
a=b+(1+2+3+4+...+98)
a=b+(1+98).98:2
a=b+4851
Vậy a-b =4851
a) Ta có: A = 1.2 + 2.3 + 3.4 + 4.5 +....+ 98.99
\(\Rightarrow\) 3A = 1.2.3 + 2.3.3 + 3.4.3 + 4.5.3 +....+ 98.99.3
\(\Rightarrow\) 3A = 1.2.3 + 2.3(4-1) + 3.4(5-2) + 4.5(6-3) +.....+ 98.99(100-97)
\(\Rightarrow\) 3A = 1.2.3 + 2.3.4 - 2.3.1 + 3.4.5 - 3.4.2 + 4.5.6 - 4.5.3 + ....+ 98.99.100 - 98.99.97
\(\Rightarrow\) 3A = 98.99.100
\(\Rightarrow\) A = \(\frac{98.99.100}{3}\) = 323400
Vậy A = 323400
b) Ta có: B = 12 + 22 + 32 +......+ 982
\(\Rightarrow\) B = 1.1 + 2.2 + 3.3 + .....+ 98.98
\(\Rightarrow\) B = 1(2-1) + 2(3-1) + 3(4-1) + .......+ 98(99-1)
\(\Rightarrow\) B = 1.2 - 1 + 2.3 - 2 + 3.4 - 3 +......+ 98.99 -98
\(\Rightarrow\) B = (1.2 + 2.3 + 3.4 +........+ 98.99) - (1 + 2 + 3 +.....+ 98)
\(\Rightarrow\) B = (1.2.3 + 2.3.3 + 3.4.3 + 4.5.3 +....+ 98.99.3) : 3 - 4851
\(\Rightarrow\) B = [1.2.3 + 2.3(4-1) + 3.4(5-2) + 4.5(6-3) +.....+ 98.99(100-97)] : 3 - 4851
\(\Rightarrow\) B = (1.2.3 + 2.3.4 - 2.3.1 + 3.4.5 - 3.4.2 + 4.5.6 - 4.5.3 + ....+ 98.99.100 - 98.99.97) : 3 + 4851
\(\Rightarrow\) B = \(\frac{\text{ 98.99.100 }}{3}\) + 4851
\(\Rightarrow\) B = 323400 + 4851
\(\Rightarrow\) B = 328251
Vậy B = 328251
hahahahaha
xet A va B thi ta thay B la cac so binh phuong cong vao con A thi lai la cac so nhan nhau lien tiep neu de y ta thay neu lay 1*2-1=1....va tru thanh day so lien den 98
A-B=1+2+3+........................+98 co 98 so hang
A-B=(1+98)*98:2=4851
A = 1.2 + 2.3 + 3.4 + ... + 98.99
A = 1.(1 + 1) + 2.(2 + 1) + 3.(3 + 1) + ... + 98.(98 + 1)
A = 12 + 1 + 22 + 2 + 32 + 3 + ... + 982.98
A = (12 + 22 + 32 + ... + 982) + (1 + 2 + 3 + ... + 98)
A = (12 + 22 + 32 + ... + 982) + 4851 (1)
B = 12 + 22 + 32 + ... + 982 (2)
(1)(2) => A - B = 4851 ⋮ 4851
ta có: B = 12 + 22 + 32 +...+982 = 1.1 +2.2+3.3+...+98.98
=> A-B = (1.2+2.3+3.4+4.5+...+98.99) - (1.1+2.2+3.3+...+98.98)
A-B = (1.2-1.1) + (2.3-2.2) + (3.4-3.3) + (4.5-4.4) + ...+ (98.99-98.98)
A-B = 1.(2-1) + 2.(3-2) +3.(4-3) + 4.(5-4) + ...+ 98.(99-98)
A-B = 1 +2+3+4+...+98
A-B = (1+98).98:2
A -B = 4851 chia hết cho 4851
\(\text{a=1.2+2.3+3.4+......+98.99}\)
\(=1\left(1\text{+}1\right)\text{+}2\left(2\text{+}1\right)\text{+}3\left(3\text{+}1\right)\text{+}.........\text{+}98\left(98\text{+}1\right)\)
\(=1^2\text{+}1\text{+}1^2\text{+}2\text{+}3^2\text{+}3\text{+}...\text{+}98^2\text{+}98\)
\(=b\text{+}\left(1\text{+}2\text{+}3\text{+}...\text{+}98\right)\)
\(=b\text{+}\left(98\text{+}1\right).98:2\)
\(=b\text{+}4851\)
\(\Rightarrow a-b=4851\)
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