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a) ta có:99 - 97 + 95 - 93 + 91 - 89 + ... + 7 - 5 + 3 - 1
= (99 - 97) + (95 - 93) + ... + (7 - 5) + (3 - 1)
= 25.2=50
b)(125.37.32).4
=(125.4).(37.32)
=500.1184
=100.5.1184
=100.5920
=592000
c)A=5+8+11+14+...+302
Số số hạng của A là
(302-5):3+1=100(số)
Tổng A= (302+5).100:2=15350
b)(125.37.32):4
=125.37.32:4
=125.37.8
=125.8.37
=1000.37
=37000
Sorry bạn mk nhìn nhầm dấu
thực hiện phép tính sau một cách hợp lí:
C=(1+2+3)+(3+4+5)+(5+6+7)+..........+(97+98+99)+(99+100+101)
Ko ghi đề
C = (3.2)+(3.4)+(3.6)+...+(3.98)+(3.100)
C = 3 . (2+4+6+...+100)
C = 3 . 2550
C = 7650
Ko theo công thức nha @@
Nhớ k mk nha ^^
a,
A=1−3−5−7−9−...−97−99a)A=1−3−5−7−9−...−97−99
=1−(3+5+7+...+99)=1−(3+5+7+...+99)
=1−(99+3).[(99−3):2+1]2=1−(99+3).[(99−3):2+1]2
=1−2499=−2498=1−2499=−2498
b)B=1+3−5−7+9+...+97−99b)B=1+3−5−7+9+...+97−99
=(−8)+(−8)+(−8)+...+(−8)+97−99=(−8)+(−8)+(−8)+...+(−8)+97−99
=(−8).12+(−2)=−98=(−8).12+(−2)=−98
c)C=1−3−5+7+9−11−13+15+...+97−99c)C=1−3−5+7+9−11−13+15+...+97−99
=0+0+0+0+0+...+0−99=0+0+0+0+0+...+0−99
=−99
a. Ta có:
1+7=81+7=8
7+8=157+8=15
A=1+7+8+15+23+38+61+99+160A=1+7+8+15+23+38+61+99+160
=8+8+38+38+160+160=8+8+38+38+160+160
=(8+38+160).2=(8+38+160).2
=206.2=206.2
=412=412
b.Ta có
1+4=51+4=5
5+9=145+9=14
B=1+4+5+9+14+23+37+60+97B=1+4+5+9+14+23+37+60+97
=5+5+23+23+97+97=5+5+23+23+97+97
=(5+23+97).2=(5+23+97).2
=125.2=125.2
=250
c) Ta có: \(\dfrac{3}{5}+\dfrac{-5}{20}+\dfrac{30}{75}+\dfrac{-7}{4}\)
\(=\dfrac{3}{5}+\dfrac{2}{5}+\dfrac{-1}{4}+\dfrac{-7}{4}\)
\(=1-2=-1\)
Giải:
a)-1/12+4/3=-1/12+16/12=15/12=5/4
b)(-4/14-3/15)-(1/5-20/35-(-1)).7
=-17/35-22/35.7
=-17/35-22/5
=-171/35
c)3/5+-5/20+30/75+-7/4
=3/5+-1/4+2/5+-7/4
=(3/5+2/5)+(-1/4+-7/4)
=1+-2
=-1
d)5/6.-12/14+7/13
=-5/7+7/13
=-16/91
e)2/-9-5/-36-1/4
=-1/12-1/4
=-1/3
f)2/23+-5/12+7/18+21/23+-7/12
=(2/23+21/23)+(-5/12+-7/12)+7/18
=1+-1+7/18
=7/18
- \(\dfrac{3}{4}\).(-\(\dfrac{55}{9}\)).\(\dfrac{8}{11}\)
= \(\dfrac{3.5.11.4.2}{4.3.3.11}\)
= \(\dfrac{10}{3}\)
1\(\dfrac{4}{23}\) + (\(\dfrac{5}{21}\) - \(\dfrac{4}{23}\)) + \(\dfrac{16}{21}\) - \(\dfrac{1}{2}\)
= 1 + \(\dfrac{4}{23}\) + \(\dfrac{5}{21}\) - \(\dfrac{4}{23}\) + \(\dfrac{16}{21}\) - \(\dfrac{1}{2}\)
= 1 + (\(\dfrac{4}{23}\) - \(\dfrac{4}{23}\)) + (\(\dfrac{5}{21}\) + \(\dfrac{16}{21}\)) - \(\dfrac{1}{2}\)
= 1 + 0 + 1 - \(\dfrac{1}{2}\)
= 2 - \(\dfrac{1}{2}\)
= \(\dfrac{3}{2}\)
a) 1125 - (374 + 1125) + (-65 + 374)
= 1125 - 374 - 1125 + (-65) + 374
= (1125 - 1125) + (-374 + 374) + (-65)
= 0 + 0 + (-65)
= -65
b) -23. 63 + 23 . 21 - 58 . 23
= 23 .(-63) + 23 . 21 - 58 . 23
= 23 . [(-63) + 21 - 58]
= 23 . (-100)
= -2300
c) -2003 + (-21 + 75 + 2003)
= -2003 + (-21) + 75 + 2003
= (-2003 + 2003) + (-21) + 75
= 0 + 54
= 54
d) 942 - 2567 + 2563 - 1942
= (942 - 1942) + (-2567 + 2563)
= -1000 + (-4)
= -1004
e) 12 - 12 + 11 + 10 - 9 + 8 - 7 + 5 - 4 + 3 + 2 - 1
= 0 + 11 + 1 + 1 + 1 + 3 + 1
= 18
-7/23*75/97+75/97-11/23*75/97
=75/97*(-7/23+11/23)
=75/97*4/23
=300/2231
(3/8+ -1/4+5/12):2/3
=(9/24+ -6/24+10/24):2/3
=13/24/2/3
=13/16
ai h cho minh minh h lai cho