Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) a3.a5 = a3+5 = a8
b) x7.x.x4 = x7+1+4 = x12
c) 35.45 = (3.4)5 = 125
d) 85.23 = 25.25.25.23 = 25+5+5+3 = 218
a/a\(^3\).a\(^5\)=a\(^8\)
b/x\(^7\).x.x\(^4\)=x\(^{12}\)
c/3\(^5\).4\(^5\)=2\(^{10}\).3\(^5\)
d/8\(^5\).2\(^3\)=2\(^{18}\)
a, \(3^{15}:3^5=3^{15-5}=3^{10}\)
b, \(4^6:4^6=4^{6-6}=4^0\)
c, \(9^8:3^2=9^8:9=9^{8-1}=9^7\)
Bài 6:
a: \(x=-\dfrac{2}{3}-\dfrac{1}{7}=\dfrac{-14-3}{21}=\dfrac{-17}{21}\)
d: \(x=\dfrac{9}{10}\cdot\dfrac{-5}{9}=\dfrac{-1}{2}\)
e: \(\Leftrightarrow x\cdot\dfrac{1}{3}=\dfrac{14}{21}-\dfrac{3}{21}=\dfrac{11}{21}\)
=>x=11/7
a;\(\dfrac{-6}{11}\) : \(\dfrac{12}{55}\) = \(\dfrac{-5}{2}\)
b;\(\dfrac{7}{12}\) + \(\dfrac{5}{72}\) - \(\dfrac{11}{36}\) = \(\dfrac{47}{72}\) - \(\dfrac{11}{36}\) = \(\dfrac{25}{72}\)
c;\(\dfrac{13}{10}\) : \(\dfrac{-5}{13}\) = \(\dfrac{-169}{50}\)
d; {\(\dfrac{5}{12}\) + \(\dfrac{5}{11}\) } : { \(\dfrac{5}{3}\) -\(\dfrac{7}{11}\) } = \(\dfrac{115}{132}\) : \(\dfrac{34}{33}\) = \(\dfrac{115}{136}\)
lưu ý mk ko chép đầu bài
mình cần gấp lắm đến chiều mai là phải nộp rùi
giúp mình nha thanks cá bạn trước 
ko có tâm trạng mà cười nữa
a) \(a^3.a^5=a^{3+5}=a^8\)
b) \(x^7.x.x^4=x^{7+1+4}=x^{12}\)
c) \(3^5.4^5=\left(3.4\right)^5=12^5=248831\)
d) \(8^5.2^3=8^2.\left(8.2\right)^3=64.16^3=262144\)
a)a3*a5=a8
b)x7*x*x4=x12
c)35*45=(3*4)5=125
d)85*23=215*23=218
Theo quy tắc nhân hai lũy thừa cùng cơ số: am.an = am + n ta có:
a) 33.34 = 37 b) 52.57 = 59; c) 75.7 = 76.
a: \(=\dfrac{-28}{36}+\dfrac{15}{36}-\dfrac{26}{36}=\dfrac{-39}{36}=\dfrac{-13}{12}\)
b: \(=\dfrac{11}{9}\left(\dfrac{15}{4}-\dfrac{7}{4}-\dfrac{5}{4}\right)=\dfrac{11}{9}\cdot\dfrac{3}{4}=\dfrac{11}{12}\)
c: \(=15+\dfrac{9}{7}+6+\dfrac{2}{3}-5-\dfrac{5}{9}\)
\(=16+\dfrac{88}{63}=\dfrac{1096}{63}\)
d: \(=\dfrac{5}{6}-\dfrac{1}{3}+\dfrac{2}{18}\)
\(=\dfrac{15-6+2}{18}=\dfrac{11}{18}\)
a) 6 9 : 6 7 = 6 9 - 7 = 6 2
b) 7 5 : 7 2 = 7 5 - 2 = 7 3
c) 11 8 : 11 3 : 11 2 = 11 8 - 3 - 2 = 11 3
d) x 8 - 7 - 1 = x 0 = 1