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\(\frac{16.29-32}{16.37+32}\)
\(=\frac{16.29-16.2}{16.37+16.2}\)
\(=\frac{16\left(29-2\right)}{16\left(37+2\right)}\)
\(=\frac{16.27}{16.39}\)
\(=\frac{27}{39}=\frac{9}{13}\)
\(=\dfrac{16\cdot30-30-16}{16\cdot37+16\cdot2}=\dfrac{30\left(16-1\right)-16}{16\cdot39}\)
\(=\dfrac{30\cdot15-16}{16\cdot39}=\dfrac{434}{16\cdot39}=\dfrac{217}{312}\)
a) \(\frac{3^2.2^4}{8.3^2}=\frac{3^2.2^4}{2^3.3^2}=2\)
b)\(\frac{84.45}{49.54}=\frac{2^2.7.3^3.5}{7^2.2.3^3}=\frac{10}{7}\)
c) \(\frac{36.10.21}{2^3.63.35}=\frac{2^3.3^3.5.7}{2^3.3^2.5.7^2}=\frac{3}{7}\)
d) \(\frac{16.29-32}{16.37+32}=\frac{16.29-16.2}{16.37+2.16}=\frac{16.\left(29-2\right)}{16.\left(37+2\right)}=\frac{27}{39}=\frac{9}{13}\)
\(\frac{48}{168}\cdot\frac{132}{32}=\frac{2^4\cdot3}{2^3\cdot3\cdot7}\cdot\frac{2^2\cdot3\cdot11}{2^5}=\frac{2\cdot1}{1\cdot1\cdot7}\cdot\frac{1\cdot3\cdot11}{2^3}=\frac{33}{28}\)
+) \(\frac{-180}{270}=\frac{-2}{3}\) +) \(\frac{22}{-165}=\frac{-2}{15}\)
+) \(\frac{-39}{261}=\frac{-13}{87}\) +) \(\frac{4.26}{52.20}=\frac{4.13.2}{4.13.2.10}=\frac{1}{10}\)
+) \(\frac{7.\left(-32\right)}{16.35}=\frac{7.\left(-2\right).16}{16.7.5}=\frac{-2}{5}\)
Học tốt
Vì nếu rút gọn \(\frac{a}{b}\)thì được phân số \(\frac{9}{13}\)=> \(\frac{a}{b}=\frac{9k}{13k}\left(k\in Z;k\ne0\right)\)
Ta có: \(\frac{9k}{13k-35}=\frac{27}{32}\)
=> \(9.k.32=27.\left(13.k-35\right)\)
=> \(288.k=351.k-945\)
=> \(351.k-288.k=945\)
=> \(63.k=945\)
=> \(k=945:63=15\)
=> \(\frac{a}{b}=\frac{9.15}{13.15}=\frac{135}{195}\)
\(y=\frac{16.29-32}{16.37+32}=\frac{9}{13}\)
vậy y = \(\frac{9}{13}\)
t i ck nha!! 6546576876876976
= 29/37