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\(\frac{16.29-32}{16.37+32}\)
\(=\frac{16.29-16.2}{16.37+16.2}\)
\(=\frac{16\left(29-2\right)}{16\left(37+2\right)}\)
\(=\frac{16.27}{16.39}\)
\(=\frac{27}{39}=\frac{9}{13}\)
\(y=\frac{16.29-32}{16.37+32}=\frac{9}{13}\)
vậy y = \(\frac{9}{13}\)
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\(=\dfrac{16\cdot30-30-16}{16\cdot37+16\cdot2}=\dfrac{30\left(16-1\right)-16}{16\cdot39}\)
\(=\dfrac{30\cdot15-16}{16\cdot39}=\dfrac{434}{16\cdot39}=\dfrac{217}{312}\)
\(a)\frac{x}{8}=\frac{-30}{y}=\frac{-48}{32}\)
Rút gọn : \(\frac{-48}{32}=\frac{(-48):16}{32:16}=\frac{-3}{2}\)
* Ta có : \(\frac{x}{8}=\frac{-3}{2}\)
\(\Rightarrow x\cdot2=-3\cdot8\)
\(\Rightarrow x=\frac{-3\cdot8}{2}=-12\)
* Ta có : \(\frac{-30}{y}=\frac{-3}{2}\)
\(\Rightarrow-30\cdot2=-3\cdot y\)
\(\Rightarrow y=\frac{-30\cdot2}{-3}=20\)
Mấy bài kia làm tương tự
\(\frac{6}{2}+\frac{9}{24}=3+\frac{3}{8}=\frac{24}{8}+\frac{3}{8}=\frac{27}{8}\)
\(\frac{29}{16}+\frac{16}{32}=\frac{29}{16}+\frac{1}{2}=\frac{29}{16}+\frac{8}{16}=\frac{29+8}{16}=\frac{37}{16}\)
\(\frac{6}{2}+\frac{9}{24}=3+\frac{3}{8}=3\frac{3}{8}\)
\(\frac{29}{16}+\frac{16}{32}=\frac{29}{16}+\frac{8}{16}=\frac{37}{16}\)
\(a)\frac{x}{4}=\frac{-15}{y}=\frac{z}{52}=\frac{-32}{64}\)
Rút gọn phân số : \(\frac{-32}{64}=\frac{-32:32}{64:32}=\frac{-1}{2}\)
* Ta có : \(\frac{x}{4}=\frac{-1}{2}\)
\(\Rightarrow2x=-4\)
\(\Rightarrow x=(-4):2=-2\)
* Ta có : \(\frac{-15}{y}=\frac{-1}{2}\)
\(\Rightarrow(-1)\cdot y=-30\)
\(\Rightarrow-y=-30\)
\(\Rightarrow y=30\)
* Ta có : \(\frac{z}{52}=\frac{-1}{2}\)
\(\Rightarrow2z=(-1)\cdot52\)
\(\Rightarrow2z=-52\)
\(\Rightarrow z=-26\)
b, Tương tự câu a
a, ta có \(\frac{x}{4}\)= \(\frac{-32}{64}\)=> \(\frac{x}{4}\)= \(\frac{-1}{2}\)=> x = -2
\(\frac{-15}{y}\) = \(\frac{-32}{64}\) => \(\frac{-15}{y}\) = \(\frac{-1}{2}\) => y = 30
\(\frac{z}{52}\) = \(\frac{-32}{64}\) => \(\frac{z}{52}\) = \(\frac{-1}{2}\) => z = -26
vậy x = -2 ; y = 30 ; z = -26
câu b làm tương tự câu a
Số đó là:
\(32:\frac{4}{32}\)
\(=\frac{4.5.32}{4}\)
\(=5.32=160\)