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Đặt \(A=\frac{7.5^9.9^5}{15^{10}}\)
Hay \(A=\frac{7.5^9.3^{10}}{3^{10}.5^{10}}\)
=> \(A=\frac{7.1.1}{1.5}\)
Vậy \(A=\frac{7}{5}\)
\(=\dfrac{2^{19}\cdot3^9+2^{18}\cdot3^9\cdot5}{2^{19}\cdot3^9+2^{20}\cdot3^{10}}=\dfrac{2^{18}\cdot3^9\cdot\left(2+5\right)}{2^{19}\cdot3^9\cdot7}=\dfrac{1}{2}\)
gọn các phân số sau:
a) 7.59.95 / 1510
b) 3.7.8.13/ 14.15.26
/ là gạch ngang trong phân số
Giải chi tiết giúp mình
A= \(\dfrac{10.11.\left(1+5.5+7.7\right)}{11.12.\left(1+5.5+7.7\right)}=\dfrac{10}{12}=\dfrac{5}{6}\)
a)\(\dfrac{-3}{29}+\dfrac{16}{58}\)\(=\dfrac{-3}{29}+\dfrac{8}{29}=\dfrac{5}{29}\)
b) \(\dfrac{8}{40}+\dfrac{-36}{45}=\dfrac{1}{5}+\dfrac{-4}{5}=\dfrac{-3}{5}\)
c) \(\dfrac{-8}{18}+\dfrac{-15}{27}=\dfrac{-4}{9}+\dfrac{-5}{9}=\dfrac{-9}{9}=-1\)
a) \(\dfrac{-3}{29}+\dfrac{16}{58}=\dfrac{-3}{29}+\dfrac{8}{29}=\dfrac{-3+8}{29}=\dfrac{5}{29}\)
b) \(\dfrac{8}{40}+\dfrac{-36}{45}=\dfrac{1}{5}+\dfrac{-4}{5}=\dfrac{1+\left(-4\right)}{5}=\dfrac{-3}{5}\)
c) \(\dfrac{-8}{18}+\dfrac{-15}{27}=\dfrac{-4}{9}+\dfrac{-5}{9}=\dfrac{-4+\left(-5\right)}{9}=\dfrac{-9}{9}=-1\)
b) \(\dfrac{7.12^3+64.27}{4^6.3^4}\)
a) \(\dfrac{7.5^9.\left(3^2\right)^5}{15^{10}}\)=\(\dfrac{7.5^9.3^{10}}{15^{10}}\)=\(\dfrac{7.5^9.3^9.3}{15^{10}}\)=\(\dfrac{7.15^9.3}{15^{10}}\)\(\dfrac{7.3}{15}=\dfrac{7}{5}\)