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18 tháng 8 2017

a) 7x3 - 5x2 

= x2( 7x - 5 )

b) x- 10x + 25

= x- 2.5.x + 52

= ( x - 5 )2

18 tháng 8 2017

a, 7x3-5x2

=x2(7x-5)

b, x2-10x+25

=x2-2.x.5+52

=(x-5)2

18 tháng 8 2017

Ta có:\(7x^3-5x^2=x^2\left(7x-5\right)\)

          \(x^2-10x+25=\left(x-5\right)^2\)

13 tháng 10 2016

\(x^2-10x+16=x^2-8x-2x+16=x\left(x-8\right)-2\left(x-8\right)=\left(x-8\right)\left(x-2\right)\)

\(x^2-2x-15=x^2-5x+3x-15=x\left(x-5\right)+3\left(x-5\right)=\left(x-5\right)\left(x+3\right)\)

\(2x^2+7x+3=2x^2+x+6x+3=x\left(2x+1\right)+3\left(2x+1\right)=\left(x+3\right)\left(2x+1\right)\)

13 tháng 10 2016

a) \(x^2-10x+16=x^2-8x-2x+16=\left(x^2-8x\right)-\left(2x-16\right)=x\left(x-8\right)-2\left(x-8\right)=\left(x-8\right)\left(x-2\right)\)b) \(x^2-2x-15=x^2+3x-5x-15=\left(x^2+3x\right)-\left(5x+15\right)=x\left(x+3\right)-5\left(x+3\right)=\left(x+3\right)\left(x-5\right)\)c) \(2x^2+7x+3=2x^2+x+6x+3=\left(2x^2+x\right)+\left(6x+3\right)=x\left(2x+1\right)+3\left(2x+1\right)=\left(2x+1\right)\left(x+3\right)\)

 

25 tháng 11 2018

5x2 - 5x - 3x2 + 3x

= 5x( x - 1 ) - 3x( x - 1 )

= ( x - 1 )( 5x - 3x )

4x2 - 8xy + 4y2 - 16z2

= ( 2x - 2y )2 - (4z)2

= ( 2x - 2y - 4z )( 2x - 2y + 4z )

3x2 + 7x + 2

= 3x+ 6x + x + 2

= 3x( x + 2 ) + ( x + 2 )

= ( x+ 2 )( 3x + 1 )

HỌC TỐT !

17 tháng 7 2019

\(a,\left(a^3-b^3\right)+\left(a-b\right)^2\)

\(=\left(a-b\right)\left(a^2+ab+b^2\right)+\left(a-b\right)^2\)

\(=\left(a-b\right)\left(a^2+ab+b^2+a-b\right)\)

\(b,\left(x^2+1\right)^2-4x^2\)

\(=x^4+2x^2+1-4x^2\)

\(=x^4-2x^2+1\)

\(\left(x^2-1\right)^2\)

\(c\left(y^3+8\right)+\left(y^2-4\right)\)

\(=\left(y+2\right)\left(y^2-8y+4\right)+\left(y-2\right)\left(y+2\right)\)

\(=\left(y+2\right)\left(y^2-8y+4+y-2\right)\)

\(=\left(y+2\right)\left(y^2-7y+2\right)\)

17 tháng 7 2019

a) ( a3 - b3) + ( a - b)2

= (a-b) (a2 + ab + b) + (a-b)2

= (a-b) (a2 + ab + b2 +a -b ) 

hok tốt

1 tháng 10 2016

1) \(6x^2-15x+6\) 

\(=6x^2-3x-12x+6\)

\(=3x\left(2x-1\right)-6\left(2x-1\right)\)

\(=\left(3x-6\right)\left(2x-1\right)\)

\(=3\left(x-2\right)\left(2x-1\right)\)

b) \(6x^2-20x+6\) 

\(=6x^2-2x-18x+6\)

\(=2x\left(3x-1\right)-6\left(3x-1\right)\)

\(=\left(2x-6\right)\left(3x-1\right)\)

\(=2\left(x-3\right)\left(3x-1\right)\)

c) \(-10x^2-7x+6\)

\(=5x-10x^2+6-12x\)

\(=5x\left(1-2x\right)+6\left(1-2x\right)\)

\(=\left(5x+6\right)\left(1-2x\right)\)

d) \(10x^2-7x-12\)

\(=10x^2-15x+8x-12\)

\(=5x\left(2x-3\right)+4\left(2x-3\right)\)

\(=\left(5x+4\right)\left(2x-3\right)\)

1 tháng 10 2016

1) 6x^2 - 15x + 6

= 6x^2 - 12x - 3x +6

= 6x (x - 2) - 3 (x - 2)

= (x - 2) (6x - 3)

= 3 (x - 2) (x - 1)

2) 6x^2 - 20x + 6

= 6x^2 - 18x - 2x + 6

= 6x (x - 3) - 2 (x - 3)

= (x - 3) (6x - 2)

= 2 (x - 3) (3x - 1)

3) -10x^2 - 7x + 6

= -10x^2 + 5x - 12x + 6

= 5x (1 - 2x) + 6 (1 - 2x)

= (1 - 2x) (5x + 6)

4) 10x^2 - 7x - 12

= 10x^2 - 15x + 8x - 12

= 5x (2x - 3) + 4 (2x - 3)

= (2x - 3) (5x + 4)

good luck !

24 tháng 7 2016

1 ) 

=x3-2x2+6x2-12x+5x-10

=x2(x-2)+6x(x-2)+5(x-2)

=(x-2)(x2+6x+5)

=(x-2)(x2+x+5x+5)

=(x-2)[x(x+1)+5(x+1)]

=(x-2)(x+1)(x+5)

toàn mũ lớn hơn 3 khó làm quá!!!! >.<

653645645645645676746784734746856876897684737547

30 tháng 10 2018

Bài 1 :

a) \(A=x^2-6x+11\)

\(A=x^2-2\cdot x\cdot3+3^2+2\)

\(A=\left(x-3\right)^2+2\ge2\forall x\)

Dấu "=' xảy ra \(\Leftrightarrow x-3=0\Leftrightarrow x=3\)

b) \(B=2x^2+10x-1\)

\(B=2\left(x^2+5x-\frac{1}{2}\right)\)

\(B=2\left[x^2+2\cdot x\cdot\frac{5}{2}+\left(\frac{5}{2}\right)^2-\frac{27}{4}\right]\)

\(B=2\left[\left(x+\frac{5}{2}\right)^2-\frac{27}{4}\right]\)

\(B=2\left(x+\frac{5}{2}\right)^2-\frac{27}{2}\ge\frac{-27}{2}\forall x\)

Dấu "=" xảy ra \(\Leftrightarrow x+\frac{5}{2}=0\Leftrightarrow x=\frac{-5}{2}\)

c) \(C=5x-x^2\)

\(C=-\left(x^2-5x\right)\)

\(C=-\left[x^2-2\cdot x\cdot\frac{5}{2}+\left(\frac{5}{2}\right)^2-\left(\frac{5}{2}\right)^2\right]\)

\(C=-\left[\left(x-\frac{5}{2}\right)^2-\frac{25}{4}\right]\)

\(C=\frac{25}{4}-\left(x-\frac{5}{2}\right)^2\le\frac{25}{4}\forall x\)

Dấu "=" xảy ra \(\Leftrightarrow x-\frac{5}{2}=0\Leftrightarrow x=\frac{5}{2}\)

Bài 2 :

\(\left(x+y+z\right)^3-x^3-y^3-z^3\)

\(=\left[x+\left(y+z\right)\right]^3-x^3-y^3-z^3\)

\(=x^3+3x^2\left(y+z\right)+3x\left(y+z\right)^2+\left(y+z\right)^3-x^3-y^3-z^3\)

\(=3x^2\left(y+z\right)+3x\left(y+z\right)^2+y^3+3y^2z+3yz^2+z^3-y^3-z^3\)

\(=3x^2\left(y+z\right)+3x\left(y+z\right)^2+3yz\left(y+z\right)\)

\(=3\left(y+z\right)\left[x^2+x\left(y+z\right)+yz\right]\)

\(=3\left(y+z\right)\left(x^2+xy+xz+yz\right)\)

\(=3\left(y+z\right)\left[x\left(x+y\right)+z\left(x+y\right)\right]\)

\(=3\left(y+z\right)\left(x+y\right)\left(x+z\right)\)

30 tháng 10 2018

a) A=x2-6x+11

=(x2-6x+9)+2

=(x-3)2+2

Ta có  \(\left(x-3\right)^2\le0vớim\text{ọi}x\)

=>\(\left(x-3\right)^2+2\le2v\text{ới}m\text{ọi}x\)

Dấu "="xảy ra khi : x-3=0

=>x=3

Vậy x có GTNN là 2 tại x=3

25 tháng 8 2017

1)x(x2 - 19 - 30)

2)x(x2 - 7 - 6)

3)x(x2 + 4x - 7 - 10)

( 4 tích mình làm tiếp 3 câu cuối)