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4x3 - 13x2 + 9x - 18
= 4x3 - 12x2 - x2 + 3x + 6x - 18
= 4x2(x - 3) - x(x - 3) + 6(x - 3)
= (x - 3)(4x2 - x + 6)
x2 + 5x - 6
= x2 + 2x + 3x - 6
= x(x + 2) - 3(x + 2)
= (x + 2)(x - 3)
x3 + 8x2 + 17x + 10
= x3 + x2 + 7x2 + 7x + 10x + 10
= x2(x + 1) + 7x(x + 1) + 10(x + 1)
= (x + 1)(x2 + 7x + 10)
= (x + 1)(x2 + 5x + 2x + 10)
= (x + 1)[ x(x + 5) + 2(x + 5)]
= (x + 1)(x + 5)(x + 2)
x3 + 3x2 + 6x + 4
= x3 + 3x2 + 3x + 1 + 3x + 3
= (x + 1)3 + 3(x + 1)
= (x + 1)[(x + 1)2 + 3]
= (x + 1)(x2 + 2x + 1 + 3)
= (x + 1)(x2 + 2x + 4)
2x3 - 12x2 + 17x - 2
= 2x3 - 8x2 - 4x2 + x + 16x - 2
= (2x3 - 8x2 + x) - (4x2 - 16x + 2)
= x(2x2 - 8x + 1) - 2(2x2 - 8x + 1)
= (2x2 - 8x + 1)(x - 2)
\(3x^3-7x^2+17x-5=3x^3-x^2-6x^2+2x+15x-5\)
\(=x^2\left(3x-1\right)-2x\left(3x-1\right)+5\left(3x-1\right)\)
\(=\left(3x-1\right)\left(x^2-2x+5\right)\)
\(x^3-x^2-4=x^3+x^2+2x-2x^2-2x-4\)
\(=x\left(x^2+x+2\right)=2\left(x^2+x+2\right)=\left(x-2\right)\left(x^2+x+2\right)\)
a) Ta có: \(x^4+4\)
\(=\left(x^2\right)^2+2\cdot x^2\cdot2+4-4x^2\)
\(=\left(x^2+2\right)^2-\left(2x\right)^2\)
\(=\left(x^2-2x+2\right)\left(x^2+2x+2\right)\)
b) Ta có: \(x^4+64\)
\(=\left(x^2\right)^2+8^2+16x^2-16x^2\)
\(=\left(x^2+8\right)^2-\left(4x\right)^2\)
\(=\left(x^2-4x+8\right)\left(x^2+4x+8\right)\)
c) Ta có: \(64x^4+y^4\)
\(=\left(8x^2\right)^2+\left(y^2\right)^2+16x^2y^2-16x^2y^2\)
\(=\left(8x^2+y^2\right)^2-\left(4xy\right)^2\)
\(=\left(8x^2-4xy+y^2\right)\left(8x^2+4xy+y^2\right)\)
d) Ta có: \(x^3-x^2-4\)
\(=x^3+x^2+2x-2x^2-2x-4\)
\(=x\left(x^2+x+2\right)-2\left(x^2+x+2\right)\)
\(=\left(x^2+x+2\right)\left(x-2\right)\)
e) Ta có: \(x^3-7x-6\)
\(=x^3-x-6x-6\)
\(=x\left(x^2-1\right)-6\left(x+1\right)\)
\(=x\left(x+1\right)\left(x-1\right)-6\left(x+1\right)\)
\(=\left(x+1\right)\left(x^2-x-6\right)\)
\(=\left(x+1\right)\left(x^2-3x+2x-6\right)\)
\(=\left(x+1\right)\left(x-3\right)\left(x+2\right)\)
f) Ta có: \(x^4+x^2+1\)
\(=x^4+2x^2+1-x^2\)
\(=\left(x^2+1\right)^2-x^2\)
\(=\left(x^2-x+1\right)\left(x^2+x+1\right)\)
d)
$(x^2+x)^2+4x^2+4x-12$
$=(x^2+x)^2+4(x^2+x)-12$
$=(x^2+x)^2-2(x^2+x)+6(x^2+x)-12$
$=(x^2+x)(x^2+x-2)+6(x^2+x-2)$
$=(x^2+x+6)(x^2+x-2)=(x^2+x+6)(x+2)(x-1)$
e)
$(x^2+2x)^2+9x^2+18x+20$
$=(x^2+2x)^2+9(x^2+2x)+20$
$=(x^2+2x)^2+4(x^2+2x)+5(x^2+2x)+20$
$=(x^2+2x)(x^2+2x+4)+5(x^2+2x+4)$
$=(x^2+2x+4)(x^2+2x+5)$
a)
$(x^2+x)^2+3(x^2+x)+2$
$=(x^2+x)^2+(x^2+x)+2(x^2+x)+2$
$=(x^2+x)(x^2+x+1)+2(x^2+x+1)=(x^2+x+1)(x^2+x+2)$
b)
$(x^2+x)^2-2(x^2+x)-15$
$=(x^2+x)^2+3(x^2+x)-5(x^2+x)-15$
$=(x^2+x)(x^2+x+3)-5(x^2+x+3)$
$=(x^2+x+3)(x^2+x-5)$
c)
$(x^2+x+1)(x^2+x+2)-12=(x^2+x+1)^2+(x^2+x+1)-12$
$=(x^2+x+1)^2-3(x^2+x+1)+4(x^2+x+1)-12$
$=(x^2+x+1)(x^2+x+1-3)+4(x^2+x+1-3)$
$=(x^2+x+1-3)(x^2+x+1+4)=(x^2+x-2)(x^2+x+5)$
$=[x(x-1)+2(x-1)](x^2+x+5)=(x+2)(x-1)(x^2+x+5)$
x2 - 10xy + 9y
= x2 - xy - 9xy + 9y2
= x(x - y) - 9y(x - y)
= (x - y)(x - 9y)
x3 - x2 - 4
= x3 + x2 + 2x - 2x2 - 2x - 4
= x(x2 + x + 2) - 2(x2 + x + 2)
= (x2 + x + 2)(x - 2)
x3 - 5x2 + 8x - 4
= x3 - x2 - 4x2 + 4x + 4x - 4
= x2(x - 1) - 4x(x - 1) + 4(x - 1)
= (x - 1)(x2 - 4x + 4)
= (x - 1)(x - 2)2
x3 + 2x - 3
= x3 - x2 + x2 - x + 3x - 3
= x2(x - 1) + x(x - 1) + 3(x - 1)
= (x - 1)(x2 + x + 3)
x3 + 5x2 + 8x + 4
= x3 + x2 + 4x2 + 4x + 4x + 4
= x2(x + 1) + 4x(x + 1) + 4(x + 1)
= (x + 1)(x2 + 4x + 4)
= (x + 1)(x + 2)2
vậy có cần phải làm lại hong hi`? :b