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dễ mk bn cho mình hỏi nhé câu 4 là \(\frac{1}{2\cdot3}\)hay là\(\frac{1}{2}\cdot3\)
a) \(\dfrac{13}{20}+\dfrac{3}{5}+x=\dfrac{5}{6}\)
\(\Rightarrow\dfrac{5}{4}+x=\dfrac{5}{6}\)
\(\Rightarrow x=\dfrac{5}{6}-\dfrac{5}{4}\)
\(\Rightarrow x=\dfrac{-5}{12}\)
b) \(x+\dfrac{1}{3}=\dfrac{2}{5}-\dfrac{-1}{3}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{11}{15}\)
\(\Rightarrow x=\dfrac{11}{15}-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{2}{5}\)
c)\(\dfrac{-5}{8}-x=\dfrac{-3}{20}-\dfrac{-1}{6}\)
\(\dfrac{-5}{8}-x=\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-5}{8}-\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-77}{120}\)
d) \(\dfrac{3}{5}-x=\dfrac{1}{4}+\dfrac{7}{10}\)
\(\Rightarrow\dfrac{3}{5}-x=\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{3}{5}-\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{-7}{20}\)
e) \(\dfrac{-3}{7}-x=\dfrac{4}{5}+\dfrac{-2}{3}\)
\(\Rightarrow\dfrac{-3}{7}-x=\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-3}{7}-\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-59}{105}\)
g) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(\Rightarrow\dfrac{-5}{6}-x=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-5}{6}-\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-13}{12}\)
Câu 1:
a) \(\frac{3}{2}.\frac{4}{5}-x=\frac{2}{3}\)
\(\frac{6}{5}-x=\frac{2}{3}\)
\(x=\frac{8}{15}\)
b) \(\frac{6}{7}:\frac{1}{2}.\frac{3}{4}-\frac{5}{8}=\frac{37}{56}\)
Câu 2:
Gọi số có hai chữ số cần tìm là: ab
ta có: ab2 = ab + 92
=> a x 100 + b x 10 + 2 = a x 10 + b + 92
=> a x 90 + b x 9 = 90
9 x ( a x 10 + b) = 90
a x 10 + b = 90 : 9
a x 10 + b = 10 = 1 x 10 + 0
=> a = 1; b = 0
KL: ab = 10
Câu 1 :
a) \(\frac{3}{2}\times\frac{4}{5}-x=\frac{2}{3}\)
\(\Rightarrow\frac{6}{5}-x=\frac{2}{3}\)
\(\Rightarrow x=\frac{6}{5}-\frac{2}{3}\)
\(\Rightarrow x=\frac{8}{15}\)
b) Ko rõ đề :)
Câu 2 :
Gọi số cần tìm là \(\overline{ab}\), ta có :
\(\overline{ab2}-\overline{ab}=92\)
\(\Rightarrow\overline{ab}\times10+2-\overline{ab}=92\)
\(\Rightarrow\overline{ab}\times9+2=92\)
\(\Rightarrow\overline{ab}\times9=90\)
\(\Rightarrow\overline{ab}=90:9\)
\(\Rightarrow\overline{ab}=10\)
Học tốt # ^-<
\(a,\frac{62}{7}:x=\frac{29}{9}:\frac{3}{56}\)
\(\frac{62}{7}:x=\frac{1624}{27}\)
\(x=\frac{62}{7}:\frac{1624}{27}=\frac{837}{5684}\)
\(b,\frac{1}{5}:x=\frac{1}{5}-\frac{1}{7}\)
\(\frac{1}{5}:x=\frac{2}{35}\)
\(x=\frac{1}{5}:\frac{2}{35}=\frac{7}{2}\)
\(c,\frac{2}{3}.x-\frac{4}{7}=\frac{1}{7}\)
\(\frac{2}{3}.x=\frac{1}{7}+\frac{4}{7}=\frac{5}{7}\)
\(x=\frac{5}{7}:\frac{2}{3}=\frac{15}{14}\)
\(d,\frac{2}{7}-\frac{8}{9}.x=\frac{2}{3}\)
\(\frac{8}{9}.x=\frac{2}{7}-\frac{2}{3}=-\frac{8}{21}\)
\(x=-\frac{8}{21}:\frac{8}{9}=-\frac{3}{7}\)
\(e,\frac{4}{7}+\frac{5}{9}:x=\frac{1}{5}\)
\(\frac{5}{9}:x=\frac{1}{5}-\frac{4}{7}=-\frac{13}{35}\)
\(x=\frac{5}{9}:-\frac{13}{35}=\frac{175}{117}\)
\(i,\frac{2}{5}-\frac{2}{5}.x=\frac{2}{5}\)
\(\frac{2}{5}.\left(1-x\right)=\frac{2}{5}\)
\(1-x=\frac{2}{5}:\frac{2}{5}=1\)
\(x=1-1=0\)
\(g,\frac{2}{3}+\frac{1}{3}:x=-1\)
\(\frac{1}{3}:x=-1-\frac{2}{3}=-\frac{5}{3}\)
\(x=\frac{1}{3}:-\frac{5}{3}=-\frac{1}{5}\)
học tốt nha
\(-\frac{1}{10}< =x< =\frac{3}{5}\)
\(\frac{-4}{9}< x< =\frac{2}{3}\)
a) \(\frac{3}{7}-x=\frac{1}{4}-\left(-\frac{3}{-5}\right)\)
\(\Rightarrow\frac{3}{7}-x=\frac{1}{4}-\frac{3}{5}\)
\(\Rightarrow\frac{3}{7}-x=\frac{-7}{20}\)
\(\Rightarrow x=\frac{3}{7}-\left(\frac{-7}{20}\right)=\frac{3}{7}+\frac{7}{20}\)
\(\Rightarrow x=\frac{109}{140}\)
b) \(\frac{-21}{-13x}+\frac{1}{3}=\frac{-2}{-3}\)
\(\Rightarrow\frac{21}{13x}+\frac{1}{3}=\frac{2}{3}\)
\(\Rightarrow\frac{21}{13x}=\frac{2}{3}-\frac{1}{3}=\frac{1}{3}\)
\(\Rightarrow13x=\frac{3.21}{1}=63\Rightarrow x=\frac{63}{13}\)
`a) 3 / 5 x - 1 / 2 = 1 / 7`
`3 / 5 x = 1 / 7 + 1 / 2`
`3 / 5 x = 9 / 14`
`x = 9 / 14 : 3 / 5`
`x = 15 / 14`
______________________________
`b) 3 / 5 x + 2 / 7 = 4 / 5`
`3 / 5 x = 4 / 5 - 2 / 7`
`3 / 5 x = 18 / 35`
`x = 18 / 35 : 3 / 5`
`x = 6 / 7`
a) 3/5 x - 1/2 = 1/7
3/5 x = 1/7 + 1/2
3/5 x = 9/14
x = 9/14 : 3/5
x = 15/14
b) 3/5 x + 2/7 = 4/5
3/5x = 4/5 - 2/7
3/5x = 18/35
x = 18/35: 3/5
x = 6/7