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15 tháng 9 2017
Cộng 1 vào mỗi ps
\(\frac{x+5}{2015}+1+\frac{x+6}{2014}+1+\frac{x+7}{2013}+1=0\)
\(\Rightarrow\frac{x+2020}{2015}+\frac{x+2020}{2014}+\frac{x+2020}{2013}=0\)
\(\Rightarrow\left[x+2020\right]\left[\frac{1}{2015}+\frac{1}{2014}+\frac{1}{2013}\right]=0\)
Mà \(\frac{1}{2015}+\frac{1}{2014}+\frac{1}{2013}\ne0\Rightarrow x+2020=0\)
=> x = -2020
20 tháng 5 2022
a: Sửa đề: \(\dfrac{2x-1}{11}+\dfrac{2x-2}{12}+\dfrac{2x-3}{13}=\dfrac{2x+5}{5}+\dfrac{2x+7}{3}+\dfrac{2x+4}{6}\)
\(\Leftrightarrow\dfrac{2x-1}{11}+1+\dfrac{2x-2}{12}+1+\dfrac{2x-3}{13}+1=\dfrac{2x+5}{5}+1+\dfrac{2x+7}{3}+1+\dfrac{2x+4}{6}+1\)
=>2x+10=0
hay x=-5
b: \(\dfrac{x-1}{2016}+\dfrac{x-2}{2015}+\dfrac{x-3}{2014}+\dfrac{x-4}{2013}+\dfrac{x-5}{2012}-5=0\)
\(\Leftrightarrow\left(\dfrac{x-1}{2016}-1\right)+\left(\dfrac{x-2}{2015}-1\right)+\left(\dfrac{x-3}{2014}-1\right)+\left(\dfrac{x-4}{2013}-1\right)+\left(\dfrac{x-5}{2012}-1\right)=0\)
=>x-2017=0
hay x=2017
20 tháng 5 2022
a: Sửa đề: \(\dfrac{2x-1}{11}+\dfrac{2x-2}{12}+\dfrac{2x-3}{13}=\dfrac{2x+5}{5}+\dfrac{2x+7}{3}+\dfrac{2x+4}{6}\)
\(\Leftrightarrow\dfrac{2x-1}{11}+1+\dfrac{2x-2}{12}+1+\dfrac{2x-3}{13}+1=\dfrac{2x+5}{5}+1+\dfrac{2x+7}{3}+1+\dfrac{2x+4}{6}+1\)
=>2x+10=0
hay x=-5
b: \(\dfrac{x-1}{2016}+\dfrac{x-2}{2015}+\dfrac{x-3}{2014}+\dfrac{x-4}{2013}+\dfrac{x-5}{2012}-5=0\)
\(\Leftrightarrow\left(\dfrac{x-1}{2016}-1\right)+\left(\dfrac{x-2}{2015}-1\right)+\left(\dfrac{x-3}{2014}-1\right)+\left(\dfrac{x-4}{2013}-1\right)+\left(\dfrac{x-5}{2012}-1\right)=0\)
=>x-2017=0
hay x=2017
2 tháng 9 2019
=> (x+2020)/5=(x+2020)/6=(x+2020)/3+(x+2020)/2
=>(x+2020)(1/5+1/6)=(x+2020)(1/3+1/2)
Với x+2020=0=>x=-2020
Với x+2020 khác 0=>1/5+1/6=1/3+1/2 ,vô lí
Vậy x=-2020
AH
14 tháng 10 2016
a, ( 44 - x ) / 3 = ( x - 12 ) / 5
=> 5 ( 44 - x ) = 3 ( x - 12 )
220 - 5x = 3x - 36
- 5x - 3x = - 36 - 220
- 8 x = - 256
x = 32
b , ( 3 - x ) / 4 = ( 2x + 7 ) / 5
=> 5 ( 3 - x ) = 4 ( 2x + 7 )
15 - 5x = 8 x + 28
- 5 x - 8 x = 28 - 15
- 13 x = 13
x = -1
KH
14 tháng 10 2016
a, \(\frac{\left(44-x\right)}{3}=\frac{\left(x-12\right)}{5}\)
=> (44 - x) . 5 = (x - 12) . 3
=> 44 - x . 5 = x - 12 .3
=> 44 - x . 5 = x - 36
=> x5 + x = - 36 - 44
=> x5 + x = - 80
=> x . (5 + 1) = - 80
=> x . 6 = - 80
=> x = - 80 : 6
=> x = - 13,3
b, \(\frac{\left(3-x\right)}{4}=\frac{\left(2x+7\right)}{5}\)
=> (3 - x) . 5 = (2x + 7) . 4
=> 3 - x . 5 = 2x + 7 . 4
=> 3 - x . 5 = 2x + 28
=> -x . 5 + 2x = 28 - 3
=> -x . 5 + 2x = 25
=> x . 5 + 2x = 25
=> x . (5 + 2) = 25
=> x . 7 = 25
=> x = 25 : 7
=> x = 3,57
\(x+\frac{5}{2015}+x+\frac{6}{2014}+x+\frac{3}{2017}=-3\)
\(\Rightarrow3x+\left(\frac{1}{403}+\frac{3}{1007}+\frac{3}{2017}\right)=-3\)
\(\Rightarrow\frac{1}{403}+\frac{3}{1007}+\frac{3}{2017}=-3-3x=-3.\left(1-x\right)\)
\(\Rightarrow\frac{\frac{1}{403}+\frac{3}{1007}+\frac{3}{2017}}{-3}-1=-x\)
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