Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(7^{2x}+7^{2x+2}=2450\)
\(7^{2x}.1+7^{2x}.7^2=2450\)
\(7^{2x}.\left(1+7^2\right)=2450\)
\(7^{2x}.\left(1+49\right)=2450\)
\(7^{2x}.50=2450\)
\(7^{2x}=2450:50\)
\(7^{2x}=49\)
\(7^{2x}=7^2\)
\(\Rightarrow2x=2\)
\(x=2:2\)
\(x=1\)
Vậy \(x=1\)
\(7^{2x}+7^{2x+2}=2450\)
\(\Leftrightarrow7^{2x}+7^{2x}.7^2=2450\)
\(\Leftrightarrow7^{2x}.\left(1+7^2\right)=2450\)
\(\Leftrightarrow7^{2x}.50=2450\)
\(\Leftrightarrow7^{2x}=2450:50\Leftrightarrow7^{2x}=49\)
\(\Leftrightarrow7^{2x}=7^2\Leftrightarrow2x=2\)
\(\Leftrightarrow x=1\)
\(7^{2x}+7^{2x+2}=2450\)
\(7^{2x}\left(1+7^2\right)=2450\)
\(7^{2x}=2450\div50\)
\(7^{2x}=49\)
\(\Rightarrow2x=2\)
\(\Leftrightarrow x=1\)
\(7^{2x}+7^{2x+2}=2450\)
\(\Leftrightarrow7^{2x}+7^{2x}.7^2=2450\)
\(\Leftrightarrow7^{2x}\left(1+7^2\right)=2450\)
\(\Leftrightarrow49^x\left(1+49\right)=2450\)
\(\Leftrightarrow49^x.50=2450\)
\(\Leftrightarrow49^x=2450:50\)
\(\Leftrightarrow49^x=49\)
\(\Rightarrow x=1\)
vậy x=1
72x + 72x+2 = 2450
1.72x + 72x.72 = 2450
72x.(1+72) = 2450
72x.(1+49) = 2450
72x.50 = 2450
72x = 2450 : 50
72x = 49
72x = 72
2x = 2
x = ... (Tự tính)
Vậy x = ...
\(7^{2x}+7^{2x+2}=2450\)
\(1\times7^{2x}+7^{2x}\times7^2=2450\)
\(7^{2x}\left(1+7^2\right)=2450\)
\(\frac{7^{2x}\left(1+7^2\right)}{1+7^2}=\frac{2450}{1+7^2}\)
\(7^{2x}=\frac{2450}{1+49}\)
\(7^{2x}=\frac{2450}{50}\)
\(7^{2x}=49\)
\(7^{2x}=7^2\)
\(2x=2\)
\(x=2\div2\)
\(x=1\)
Học tốt nha.
a) \(\left(2x+1\right)\left(x-\frac{1}{7}\right)=0\Leftrightarrow\orbr{\begin{cases}2x+1=0\\x-\frac{1}{7}=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-\frac{1}{2}\\x=\frac{1}{7}\end{cases}}.\)
Vậy.....
b) \(7^{2x}+7^{2x+2}=2450\Leftrightarrow7^{2x}\left(1+7^2\right)=2450\Leftrightarrow7^{2x}\cdot50=2450\Leftrightarrow7^{2x}=49\Leftrightarrow2x=2\Leftrightarrow x=1.\)
Vậy....
Học tốt nhé ^3^
\(2A\left(x\right)-B\left(x\right)=2\left(3x^3+2x^4-x^2+8x-7\right)-\left(-x^4-4x^2-2x^3-7+3x\right)\)
\(=4x^4+6x^3-2x^2+16x-14+x^4+2x^3+4x^2-3x+7\)
\(=5x^4+8x^3+x^2+13x-7\)
\(7^{2x}+7^{2x+2}=2450\)
\(7^{2x}+7^{2x}.7^2=2450\)
\(7^{2x}+7^{2x}.49=2450\)
\(7^{2x}\left(1+49\right)=2450\)
\(7^{2x}.50=2450\)
\(7^{2x}=2450:50\)
\(7^{2x}=49\)
\(7^{2x}=7^2\)
\(2x=2\)
=> \(x=1\)
Vậy \(x=1\)
7x.1+7x.72=2450
7x(1+49)=2450
7x.50=2450
7x=2450:50
7x=49=72
=>x=2.
Đây nhé
cảm ơn