Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Bài 4
d. 450 : [ 41 - (2x - 5) ] = 32 . 5
450 : [ 41 - (2x - 5) ] = 9 . 5
450 : [ 41 - (2x - 5) ] = 45
[ 41 - (2x - 5) ] = 450 : 45
41 - (2x - 5) = 10
(2x - 5) = 41 - 10
2x - 5 = 31
2x = 31 + 5
2x = 36
x = 36 : 2
x = 1
e. 30 : (x - 7) = 1519 : 158
30 : (x - 7) = 15
x - 7 = 30 : 15
x - 7 = 2
x = 2 + 7
x = 9
f. (2x - 3)3 = 125
2x - 3 = 5
2x = 5 + 3
2x = 8
x = 8 : 2
x = 4
tk cho cj nha
a)x2=4 d)6x3-8=40 g)(x-1)3=27 b)x2=25 c)3x5-1=2
\(\Rightarrow\)x=2 6x3 =40+8=48 (x-1)3=\(\pm\)(3)3 \(\Rightarrow\)x=5 3x5 =2+1=3
x3 =48:6=8 Vậy x-1=3 hoặc x-1=-3 x5 3:3=1
\(\Rightarrow\)x=2 x =3+1 x =(-3)+1 \(\Rightarrow\)x=1
x =4 x =-2
\(\Rightarrow\)x\(\in\)+{4;(-2)}
e)(x-2)2=4 f)(x+1)2=25 h)(x+1)3=64
(x-2)2=\(\pm\)(2)2 (x+1)2=\(\pm\)(5)2 (x+1)3=\(\pm\)(4)3
Vậy x-2=2 hoặc x-2=(-2) Vậy x+1=5 hoặc x+1=-5 Vậy x+1=4 hoặc x+1=-4
x =2+2 x =(-2)+2 x =5+1 x =(-5)+1 x =4+1 x =(-4)+1
x =4 x =0 x =6 x =-4 x =5 x =-3
\(\Rightarrow\)x\(\in\){4;0} \(\Rightarrow\)x\(\in\){6;(-4)} \(\Rightarrow\)x\(\in\){5;(-3)}
Hok tốt!
Trả lời:
\(\frac{5}{1.6}+\frac{5}{6.11}+...+\frac{5}{\left(5x+1\right)\left(5x+6\right)}=\frac{2005}{2006}\)
\(\Rightarrow1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+...+\frac{1}{5x+1}-\frac{1}{5x+6}=\frac{2005}{2006}\)
\(\Rightarrow1-\frac{1}{5x+6}=\frac{2005}{2006}\)
\(\Rightarrow\frac{1}{5x+6}=1-\frac{2005}{2006}\)
\(\Rightarrow\frac{1}{5x+6}=\frac{1}{2006}\)
\(\Rightarrow5x+6=2006\)
\(\Rightarrow5x=2000\)
\(\Rightarrow x=400\)
Vậy x = 400
Trả lời:
\(\frac{x}{2008}-\frac{1}{10}-\frac{1}{15}-\frac{1}{21}-...-\frac{1}{120}=\frac{5}{8}\)
\(\Rightarrow\frac{x}{2008}-\left(\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+...+\frac{1}{120}\right)=\frac{5}{8}\)\(\frac{5}{8}\)
Đặt \(A=\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+...+\frac{1}{120}\), ta được : \(\frac{x}{2008}-A=\frac{5}{8}\) (*)
\(\Rightarrow A=\frac{2}{20}+\frac{2}{30}+\frac{2}{42}+...+\frac{2}{240}\)
\(\Rightarrow A=2\left(\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+...+\frac{1}{240}\right)\)
\(\Rightarrow A=2\left(\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{15.16}\right)\)
\(\Rightarrow A=2\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{15}-\frac{1}{16}\right)\)
\(\Rightarrow A=2\left(\frac{1}{4}-\frac{1}{16}\right)=2.\frac{3}{16}=\frac{3}{8}\)
Thay A vào (*) , ta có:
\(\frac{x}{2008}-\frac{3}{8}=\frac{5}{8}\)
\(\Rightarrow\frac{x}{2008}=1\)
\(\Rightarrow x=2008\)
Vậy x = 2008
Bài 48:
1/ 17(-84) + 17(-16) = 17 \(\left[\left(-84\right)+\left(-16\right)\right]\) = 17. (-100) = -1700
2/ 15.58 - 15.48 = 15.(58 - 48) = 15 . 10 = 150
3/ -37.86 + 37.76 = 37 .(-86 + 76) = 37. (-10) = -370
4/ 1975 .(-115) + 1975.15 = 1975. (-115 + 15) = 1975 . (-100) = -197500
5/ 79.89 - 79.(-11) = 79. (89 + 11) = 79 . 100 = 7900
6/ 48.195 - 48 . 95 = 48. (195 - 95) = 48 . 100 = 4800
7/ 157.17 - 157.7 = 157. (17 - 7) = 157 . 10 = 1570
8/ 15(-176) + 15.76 = 15. (-176 + 6) = 15 . 100 = 1500
9/ 47.(-147) - 47 .(-47)= 47 (-147 + 47) = 47. (-100) = -4700
10/ 153.177 - 153.77 = 153. (177 - 77) = 153. 100 = 15300
11/ 15. (4 - 7) - 15. (5 - 3)
= 15. (-3) - 15. 2
= 15. (-3 - 2)
= 15. (-5)
= -75
12/ 73. (8 - 59) - 59. (8 - 73)
= 73. 8 - 73. 59 - 59. 8 + 73. 59
= 8. (73 - 59) + 73. (59 - 59)
= 8. (73 - 59) + 0
= 8. 14
= 112
13/ 159. (18 - 59) - 59. (18 - 159)
= 159. 18 - 159. 59 - 59. 18 + 59. 159
= 18.(159 - 59) - 59. (159 - 159)
= 18.(159 - 59) - 0
= 18. 100
= 1800
14/ -145. (13 - 57) + 57. (10 - 145)
= -145. 13 + 145. 57 + 57. 10 - 57. 145
= -145. 13 + 57. 10
= -1885 + 570
= 2455
Những câu còn lại tương tự