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A)\(1-2x+x^2\)
\(=\left(1-x\right)^2\)
B)\(4y+4+y^2\)
\(=2^2+4y+y^2\)
\(=\left(2+y\right)^2\)
C)\(\frac{1}{16}+\frac{1}{2}x+x^2\)
\(=\left(\frac{1}{4}\right)^2+\frac{1}{2}x+x^2\)
\(=\left(\frac{1}{4}+x\right)\)
D)\(36x^2+12xy+y^2\)
\(=\left(6x+y\right)^2\)
a) x^3-3x^2+3x-1
=x3-3x2.1+3x.12-13
=(x-1)3
b)16+8x+x^2
=42+2.4.x+x2
=(4+x)2
c) 3x^2+3x+1+x^3
=x3+3x2.1+3x.12+13
=(x+1)3
d)1-2y+y^2
=1-2.1.y+y2
=(1-y)2
\(a.x^2+x+\frac{1}{4}=x^2+2.x.\frac{1}{4}+\left(\frac{1}{4}\right)^2\)
\(=\left(x+\frac{1}{4}\right)^2\)
b) \(x^2+12xy+36xy^2=x^2+2.x.y+y^2\)
\(a.x^2+x+\frac{1}{4}=x^2+2.x.\frac{1}{4}+\left(\frac{1}{4}\right)^2\)
\(=\left(x+\frac{1}{4}\right)^2\)
b) \(x^2+12xy+36xy^2=x^2+2.x.y+y^2\)
\(a.x^2+x+\frac{1}{4}=x^2+2.x.\frac{1}{4}+\left(\frac{1}{4}\right)^2\)
\(=\left(x+\frac{1}{4}\right)^2\)
b) \(x^2+12xy+36xy^2=x^2+2.x.y+y^2\)
\(a.x^2+x+\frac{1}{4}=x^2+2.x.\frac{1}{4}+\left(\frac{1}{4}\right)^2\)
\(=\left(x+\frac{1}{4}\right)^2\)
b) \(x^2+12xy+36xy^2=x^2+2.x.y+y^2\)
d) \(x^2-2x+4=x^2-2.x.4+4^2\)
\(=\left(x-4\right)^2\)
e) \(25x^2+4y^2-20xy=\left(5x\right)^2-2.5x.2y+\left(2y\right)^2\)
\(=\left(5x-2y\right)^2\)
^...^ 
^_^ Bài làm có gì ko hiểu bạn cứ hỏi nhé ^_^
mạng của mk bị lỗi bạn xem cái phần cuối cùng nhé xl bạn nhiều vì mạng của mk bị lỗi 
a, \(25x^2+5xy+\frac{1}{4}y^2=\left(5x\right)^2+2.5x.\frac{1}{2}y+\left(\frac{1}{2}y\right)^2\)
\(=\left(5x+\frac{1}{2}y\right)^2\)
b, \(9x^2+12x+4=\left(3x\right)^2+2.3x.2+2^2=\left(3x+2\right)^2\)
c, \(x^2-6x+5-y^2-4y=\left(x^2-6x+9\right)-\left(y^2+4y+4\right)\)
\(=\left(x-3\right)^2-\left(y+2\right)^2=\left(x-y-5\right)\left(x+y-1\right)\)
d, \(\left(2x-y\right)^2+4\left(x+y\right)^2-4\left(2x-y\right)\left(x+y\right)\)
\(=\left(2x-y\right)^2-2\left(2x-y\right)\left(2x+2y\right)+\left(2x+2y\right)^2\)
\(=\left(2x-y+2x+2y\right)^2=\left(4x+y\right)^2\)
a)\(x^2+2x+1=x^2+2x1+1^2=\left(x+1\right)^2\)
b)\(9x^2+y^2+6xy=3^2x^2+y^2+2.3x.y=\left(3x\right)^2+2.3x.y+y^2=\left(3x+y\right)^2\)
c)\(25a^2+4b^2-20ab=5^2a^2+2^2b^2-2.5a.2b=\left(5a\right)^2-2.5a.2b+\left(2b\right)^2=\left(5a-2b\right)^2\)
d)\(x^2-x+\frac{1}{4}=x^2-2.x.\frac{1}{2}+\left(\frac{1}{2}\right)^2=\left(x-\frac{1}{2}\right)^2\)
a) \(x^2+2x+1=\left(x+1\right)^2\)
b) \(9x^2+y^2+6xy=\left(3x+y\right)^2\)
c) \(25a^2+4b^2-20ab=\left(5a-2b\right)^2\)
Câu d thì biểu thức là \(\frac{x^2-1}{2x+\frac{1}{10}}\) hay là \(\frac{x^2-1}{\frac{2x+1}{10}}\) z bạn???
a, 1-2x+x^2 = x^2 - 2x.1 + 1^2= (x-1)^2
b, 4y+4+y^2 = y^2 + 2y.2+ 2^2 = (y+2)^2
c, 1/16+1/2x+x^2 = x^2 + 2.x.\(\frac{1}{4}\)+ (1/4)^2 = (x+1/4)^2
d, 36x^2+12xy+y^2 = (6x)^2 + 2.6x.y + y^2 = (6x+y)^2
a) \(1-2x+x^2=\left(1-x\right)^2=\left(x-1\right)^2\)
b) \(4y+4+y^2=y^2+4y+4=\left(y+2\right)^2\)
c) \(\frac{1}{16}+\frac{1}{2}x+x^2=\left(x+\frac{1}{4}\right)^2\)
d) \(36x^2+12xy+y^2=\left(6x+y\right)^2\)