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Đặt A=1/2+1/6+1/18+1/54+1/162+1/486 A*3=3/2+1/2+1/6+1/18+1/54+1/162 A*3-A={3/2+1/2+1/6+1/18+1/54+1/162}-{1/2+1/6+1/18+1/54+1/162+1/486} A*2=3/2-1/486 A*2={kết quả} =kết quả :2=A Vậy 1/2+1/6+/18+1/54+1/162+1/486=A
\(\dfrac{5}{2}+\dfrac{5}{6}+\dfrac{5}{18}+\dfrac{5}{54}+\dfrac{5}{162}+\dfrac{5}{486}\)
\(=\dfrac{5.243}{486}+\dfrac{5.81}{486}+\dfrac{5.27}{486}+\dfrac{5.9}{486}+\dfrac{5.3}{486}+\dfrac{5}{486}\)
\(=\dfrac{1215+405+135+45+15+5}{486}\)
\(=\dfrac{1820}{486}=\dfrac{910}{243}\)
C=5/2+5/6+5/18+5/54+5/162+5/486
C=1215/486+405/486+135/486+45/486+15/486+5/486
C=1215+405+135+45+15+5/486
C=1820/486=910/243
\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{98.99}+\frac{1}{99.100}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}=\frac{99}{100}\)
\(B=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{97.99}+\frac{2}{99.101}\)
\(=1-\frac{1}{3}+\frac{!}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{99}-\frac{1}{101}\)
\(=1-\frac{1}{101}=\frac{100}{101}\)
\(C=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+....+\frac{1}{1024}+\frac{1}{2048}\)
\(\Rightarrow\)\(2C=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+....+\frac{1}{512}+\frac{1}{1024}\)
\(\Rightarrow\)\(2C-C=\left(1+\frac{1}{2}+\frac{1}{4}+...+\frac{1}{1024}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{2048}\right)\)
\(\Leftrightarrow\)\(C=1-\frac{1}{2048}=\frac{2047}{2048}\)
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