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Lê Quang Phúc
bài 1:Tính nhanh
b)58+42+32nhân 8+5 nhân 16
c)(42 nhân 43+46nhân 57+43)-360:4
bài 2:tìm x
a)890:x=35 dư 15
c)1482:x+23=80
a, [ 58+(-42)]-(58-42)
= 58 - 42 - 58 + 42
= ( 58 - 58 ) + ( 42 - 42)
= 0+0=0
b, ( 65 - 35 ) - ( 35 + 27 )
= 65 - 35 - 35 - 27
= 65 - 70 -27
= 65 - 97
= -32
c, 3 . 52 - 176 : 23
=3 .25 - 176 : 8
= 75 - 22
= 53
d, 22 . 3 - 5 . 23
= 4 . 3 - 5 . 8
= 12 - 40
= -28
g, 2020 - [ 39 - ( 5 - 1 )2 ] - 2019
= 2020 - [ 39 - 42 ] - 2019
= ( 2020 -2019 ) - [ 39 - 16 ]
= 1 - 23
= -22
k, 2018 : [ 38 - ( 7 - 1 )2 ] + 20180
= 2018 : [ 38 - 62 ] + 1
= 2018 : [ 38 - 36 ] + 1
= 2018 : 2 + 1
= 1009 + 1 =1010
a)\(\left[58+\left(-42\right)\right]-\left(58-42\right)\)
=\(58-42-58+42\)
=\(0\)
b)\(\left(65-35\right)-\left(35+27\right)\)
=\(65-35-35+27\)
=\(-32\)
c)\(3.5^2-176:2^3\)
=\(75-22\)
=\(53\)
d)\(2^2.3-5.2^3\)
=\(2^2\left(3-10\right)\)
=\(-28\)
g)\(2020-\left[39-\left(5-1\right)^2\right]-2019\)
=\(1-\left(39-16\right)\)
=\(-22\)
k)\(2018:\left[38-\left(7-1\right)^2\right]+2018^0\)
=\(2018:2+2018^0\)
=\(1010\)
a) \(74.42+74.58-400=74.\left(42+58\right)-400\)
\(=74.100-400\)
\(=7400-400\)
\(=7000\)
b) \(75-\left(3.5^2-4.2^3\right)=75-\left(3.25-4.8\right)\)
\(=75-\left(75-32\right)\)
\(=75-75+32\)
\(=32\)
c) \(x-15=-135\)
\(x=-135+15\)
\(x=-120\)
1
\(\left(x-2\right):2.3=6\)
\(\Leftrightarrow\left(x-2\right):2=2\)
\(\Leftrightarrow\left(x-2\right)=4\)
\(\Leftrightarrow x=4+2=6\)
c) ta có
\(\left[\left(2x+1\right)+1\right]m:2=625\)
\(\Leftrightarrow\left[\left(2x+1\right)+1\right]\left\{\left[\left(2x+1\right)-1\right]:2+1\right\}=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-1:2+1=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-2+1=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-2=1249\)
\(\Leftrightarrow\left(2x+1\right)^2+1=1251\)
\(\Leftrightarrow\left(2x+1\right)^2=1250\)
...
2
\(\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{7}{4}-\frac{1}{2}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{5}{4}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}:\frac{5}{3}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}.\frac{3}{5}\)
\(\Leftrightarrow x-\frac{1}{2}=\frac{3}{4}\)
\(\Leftrightarrow x=\frac{3}{4}+\frac{1}{2}=\frac{5}{4}\)
58 x 42 + 32 x 8 + 5 x 16
= 58 x 42 + 16 x 8 x 2 + 5 x 16
= 58 x 42 + 16 x 16 + 5 x 16
= 58 x 42 + (16 + 5) x 16
= 58 x 42 + 21 x 16
= 58 x 2 x 21 + 21 x 16
= 116 x 21 + 21 x 16
= (116 + 16) x 21
= 132 x 21 = 2772
58 x 42+32 x 8+5 x 16
=58 x 42+32 x 8+5 x 2 x 8
=58 x 42+32 x 8+10 x 8
=58 x 42+(32+10) x 8
=58 x 42+42 x 8
=(58+8) x 42
=66 x 41
=2706
a) Bạn xemm lại đề nhé.
b) \(5\left(x+35\right)=515\)
\(x+35=515\div5\)
\(x+35=103\)
\(x=103-35\)
\(x=68\)
Vậy \(x=68\).
c) \(90-3\left(x+1\right)=42\)
\(3\left(x+1\right)=90-42\)
\(3\left(x+1\right)=48\)
\(x+1=48\div3\)
\(x+1=16\)
\(x=16-1\)
\(x=15\)
Vậy \(x=15\).
d) \(12x-33=3^2.3^3\)
\(12x-33=3^5\)
\(12x-33=243\)
\(12x=243+33\)
\(12x=276\)
\(x=276\div12\)
\(x=23\)
Vậy \(x=23\).
e) \(100-7\left(x-5\right)=58\)
\(7\left(x-5\right)=100-58\)
\(7\left(x-5\right)=42\)
\(x-5=42\div7\)
\(x-5=6\)
\(\Rightarrow x=6+5=11\)
Vậy \(x=11\).
j) \(24+5x=7^5\div7^3\)
\(24+5x=7^2\)
\(24+5x=49\)
\(5x=49-24\)
\(5x=25\)
\(\Rightarrow x=25\div5=5\)
Vậy \(x=5\).
541+(218-x)=735
(218-x)=735-541
(218-x)=194
x=218-194
x=24
vậy x=24
5 (x+35)=515
(x+35)=515:5
(x+35=103
x=103-35
x=68
vậy x=68
90-3 (x+1)=42
3 (x+1)=90-42
3 (x+1)=48
(x+1)=48:3
(x+1)=16
x=16-1
x=15
vậy x=15
12x-33=3^2.3^3
12x-33=3^5
12x-33=243
12x=243-33
12x=210
x=210:12
x=17,5
vậy x=17,5
100- 7 (x-5)=58
7 (x-5)=100-58
7 (x-5)=42
(x-5)=42:7
(x-5)=6
x=6-5
x=1
vậy x=1
24+5x=7^5:7^3
24+5x=7^2
24+5x=49
5x=49-24
5x=25
x=25:5
x=5
vậy x=5
42 x 58 + 47 x 156 - 47 - 47 x 114
=42 x 58 + 47 x 156 - 47 x 1 - 47 x 114
=42 x 58 + 47 x (156 - 1 - 114)
=42 x 58 + 47 x 41
=2436 + 1927
=4363
42x58+47x156-47x114
= 42x58+47x(156-1-114)
= 42x58+47x41
= 41x58+47x41+58
= 41x(58+47)+58
= 41x105+58
= 4305+58
= 4363
3.x+(-42)=2.(x+1)+(-58)
=> 3x-42=2x+2-58
=> 3x-42=2x-56
=> 3x-2x=-56+42
=> x=-14