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25.84=25.(23)4=25.212=217
256.1253=(52)6.(53)3=512.59=517
6255:257=(54)5:(52)7=520:214=56
a) \(25^6\cdot125^3=\left(5^2\right)^6\cdot\left(5^3\right)^3=5^{12}\cdot5^9=5^{21}\)
b) \(625^5:25^7=\left(5^4\right)^5:\left(5^2\right)^7=5^{20}:5^{14}=5^6\)
c) \(12^3\cdot3^3=\left(12\cdot3\right)^3=36^3\)
a)33 . 92
= 33 . 34
=33+4
=37
b) 512.7-511.10
= 512.7 - 512.2
= 512.(7-2)
= 512.5
=513
c) x1.x2.x3...x100
= x(100+1).100:2
= x5050
1) 75 . 76 . 1124 = 75 + 6 . 1 = 711
2) 34 . 37 . 32 . 30 = 34 + 7 + 2 . 1 = 313
3) 5 . 25 . 5 . 514 . 521 = ( 5 . 5 ) . 52 . 514 . 521 = 52 . 52 . 514 . 521 = 52 + 2 + 14 + 21 = 539
4) 26 . 16 . 42 . 213 = 26 . 24 . 24 . 213 = 26 + 4 + 4 + 13 = 227
\(2^5.4=2^5.2^2=2^7\);\(5^4.25=5^4.5^2=5^6\); \(16^3.2^3=\left(2^4\right)^3.2^3=2^{12}.2^3=2^{15}\)
\(625^5:25^7=\left(5^4\right)^5:\left(5^2\right)^7=5^{20}:5^{14}=5^6\); \(25^6:125^3=\left(5^2\right)^6:\left(5^3\right)^3=5^{12}:5^9=5^3\)
\(12^4.3^4=\left(2^2.3\right)^4.3^4=2^8.3^4.3^4=2^8.3^8=6^8\); \(9^6:3^2=\left(3^2\right)^6:3^2=3^{12}:3^2=3^{10}\)
\(2^3.2^4.2=2^8\)
a) = 53+4+1 = 58
b) = 65-4 = 6
c) = 32+3+4-7 = 32
d) = x4+2+1 = x7
e) = 812+10+3 = 825
1. \(5^3.5^4.5=5^{3+4+1}=5^8\)
2. \(6^5:\left(6^3.6\right)=6^5:\left(6^{3+1}\right)=6^5:6^4=6^{5-4}=6^1\)
3. \(\left(3^2.3^3.3^4\right):3^7=\left(3^{2+3+4}\right):3^7=3^9:3^7=3^{9-7}=3^2\)
4. \(x^4.x^2.x=x^{4+2+1}=x^7\)
5. \(\left(8^{12}.8^{10}\right).8^3=8^{12+10+3}=8^{25}\)
\(\left(\frac{3}{7}\right)^5.\left(\frac{7}{3}\right)^{-1}.\left(\frac{5}{6}\right)^6.\left(\frac{343}{625}\right)^{-2}\)
\(=\left(\frac{3}{7}\right)^5.\left(\frac{3}{7}\right).\left(\frac{5}{2.3}\right)^6.\left(\frac{5^4}{7^3}\right)^2\)
\(=\frac{3^5}{7^5}.\frac{3}{7}.\frac{5^6}{2^6.3^6}.\frac{5^8}{7^6}=\frac{1}{2^6}.\frac{3^6}{3^6}.\frac{5^{14}}{1}.\frac{1}{7^{12}}=\frac{5^{14}}{2^6.7^{12}}\)
Nó đâu có phải là số nguyên đâu
3/7 x 5/6 +5/6 x3/7
= (3/7x5/6) + (5/6x3/7)
= 15/42 + 15/42 = 30/42 = 5/7