Question

[pham nhu nguyen]

 Tính giá trị biểu thức

\(\frac{9^{10}.27^7}{81^7.3^{15}}\)            \(\frac{2^{10}.3^{13}.16^3}{4^{10}.9^6}\)

Giúp em với

Answer 1

[Phạm Cao Sơn]

\(\frac{9^{10}\cdot27^7}{81^7\cdot3^{15}}=\frac{3^{20}\cdot3^{21}}{3^{28}\cdot3^{15}}=\frac{3^{41}}{3^{43}}=\frac{1}{9}\)

\(\frac{2^{10}\cdot3^{13}\cdot16^3}{4^{10}\cdot9^6}=\frac{2^{10}\cdot3^{13}\cdot2^{12}}{2^{20}\cdot3^{12}}=\frac{2^{22}\cdot3^{13}}{2^{20}\cdot3^{12}}=2^2\cdot3=12\)