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\(\frac{1}{2}2^x+2^{x+2}=2^8+2^5\)
\(\Leftrightarrow2^{x-1}+2^{x+2}=2^5\left(1+2^3\right)\)
\(\Leftrightarrow2^{x+1}\left(1+2^3\right)=2^5\left(1+2^3\right)\)
\(\Leftrightarrow2^{x-1}=2^5\)
\(\Leftrightarrow x-1=5\)
\(\Leftrightarrow x=5+1=6\)
Vậy x=6
Bạn ơi,cho mk hỏi tại sao từ chỗ \(2^{x-1}+2^{x+2}\)bạn lại suy ra được \(2^{x+1}\left(1+2^3\right)\)vậy bạn?
a) 1/7 - 3/5x = 3/5
3/5x= 1/7 - 3/5
3/5x = -16/35
x= -16/35 : 3/5 = -16/21
b) 3/7 - 1/2x = 5/3
1/2x = 3/7 - 5/3 = -26/21
x= -26/21 : 1/2 = -52/21
a )
Ta có :
\(\hept{\begin{cases}\frac{x}{5}=\frac{y}{6}\\\frac{y}{8}=\frac{z}{7}\end{cases}\Rightarrow\hept{\begin{cases}\frac{x}{20}=\frac{y}{24}\\\frac{y}{24}=\frac{z}{21}\end{cases}}}\)
và \(x+y-z=69\)
ADTCDTSBN , ta có :
\(\frac{x}{20}=\frac{y}{24}=\frac{z}{21}=\frac{x+y-z}{20+24-21}=\frac{69}{23}=3\)
\(\Rightarrow\hept{\begin{cases}\frac{x}{20}=3\\\frac{y}{24}=3\\\frac{z}{21}=3\end{cases}\Rightarrow\hept{\begin{cases}x=3.20=60\\y=3.24=72\\z=3.21=63\end{cases}}}\)
Vậy ...
b )
Ta có :
\(5y=72\Rightarrow y=\frac{72}{5}=14,4\)
\(\Rightarrow x=14,4.3:2=21,6\)
và \(3x+5y-7z=30\)
Thay vào làm tiếp :
c )
\(\frac{x-1}{2}=\frac{y+3}{4}=\frac{z-5}{6}\)
\(=\frac{3\left(x-1\right)}{6}=\frac{4\left(y+3\right)}{16}=\frac{5\left(z-5\right)}{30}\)
\(=\frac{3x-3}{6}=\frac{4y+12}{16}=\frac{5z-25}{30}\)
\(=\frac{5z-25-\left(3x-3\right)-\left(4y+12\right)}{30-6-16}\)( ADTCDTSBN )
\(=\frac{5z-25-3x+3-4y-12}{8}=\frac{5z-3x-4y-34}{8}\)
\(=\frac{50-34}{8}=\frac{16}{8}=2\)
\(\Rightarrow\hept{\begin{cases}\frac{x-1}{2}=2\\\frac{y+3}{4}=2\\\frac{z-5}{6}=2\end{cases}\Rightarrow\hept{\begin{cases}x-1=2.2=4\\y+3=2.4=8\\z-5=2.6=12\end{cases}\Rightarrow}\hept{\begin{cases}x=5\\y=5\\z=17\end{cases}}}\)
Vậy ...
Áp dụng tính chất dãy tỉ số bằng nhau
\(\frac{x}{5}=\frac{y}{7}=\frac{z}{9}=\frac{x-y+z}{5-7+9}=\frac{315}{7}=45\)
suy ra: x/5 = 45 => x = 225
y/7 = 45 => y = 315
z/9 = 45 => z = 405
\(\left(\frac{5}{x+3}-2\right).4=7-\left(\frac{9}{x+3}+\frac{1}{2}\right).2\)
\(\Leftrightarrow\frac{20}{x+3}-8=7-\frac{18}{x+3}+1\)
\(\Leftrightarrow\frac{20}{x+3}-8=8-\frac{18}{x+3}\)
\(\Leftrightarrow\frac{20}{x+3}+\frac{18}{x+3}=8+8\)
\(\Leftrightarrow\frac{38}{x+3}=16\)
\(\Leftrightarrow x+3=2,375\)
\(\Leftrightarrow x=-0,625\)
\(\left(\frac{5}{x+3}-2\right).4=7-\left(\frac{9}{x+3}+\frac{1}{2}\right).2\)
\(\Leftrightarrow\frac{20}{x+3}-8=7-\left(\frac{18}{x+3}+1\right)\)
\(\Leftrightarrow\frac{20}{x+3}-8=7-\frac{18}{x+3}-1\)
\(\Leftrightarrow\frac{20}{x+3}+\frac{18}{x+3}=7-1+8\)
\(\Leftrightarrow\frac{38}{x+3}=14\)
\(\Leftrightarrow\left(x+3\right)14=38\)
\(\Leftrightarrow14x+42=38\)
\(\Leftrightarrow14x=-4\Leftrightarrow x=-\frac{4}{14}=-\frac{2}{7}\)
Vậy \(x=-\frac{2}{7}\)
a) 23x+2 = 4x+5 = (22)x+5 = 22x+10
=> 3x + 2 = 2x + 10
=> 3x - 2x = 10 - 2
x = 8
b) 3-1.3x + 9.3x = 28
3x. ( 3-1 + 9) = 28
3x. 28/3 = 28
3x = 3 = 31
=> x = 1
\(2^{3x+2}=4^{x+5}\)
\(\Rightarrow2^{3x+2}=\left(2^2\right)^{x+5}\)
\(\Rightarrow3x+2=2\left(x+5\right)\)
\(\Rightarrow3x+2=2x+10\)
\(\Rightarrow3x-2x=10-2\Rightarrow x=8\)
\(3^{-1}.3^x+9.3^x=28\)
\(\Rightarrow\frac{1}{3}.3^x+9.3^x=28\)
\(\Rightarrow3^x.\left(9+\frac{1}{3}\right)=28\)
\(\Rightarrow3^x.\frac{28}{3}=28\)
\(\Rightarrow3^x=3\Rightarrow x=1\)
Chúc bạn học tốt.
\(5^{x+2}+5^{x+1}+5^x=3785.\)
\(\Leftrightarrow5^x\cdot5^2+5^x\cdot5+5^x=3785.\)
\(\Leftrightarrow5^x\left(5^2+5+1\right)=3785\)
\(\Leftrightarrow5^x\left(25+5+1\right)=3785\)
\(\Leftrightarrow5^x31=3785\)
\(\Leftrightarrow5^x=\frac{3785}{31}=125\)
\(\Leftrightarrow5^x=5^3\)
\(\Leftrightarrow x=3\)
vậy x\(=3\)
5x+2+5x+1+5x=3785
=> 5x.52+5x.5+5x=3785
=>31.5x=3875
=> 5x=125
=> 5x=53
=> x=3
Vậy x=3