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\(=\left(\dfrac{5}{3}-\dfrac{1}{4}\right).\left(\dfrac{1}{20}\right)^2\)
\(=\dfrac{17}{12}.\dfrac{1}{400}=\dfrac{17}{4800}\)
\(2:\left(\dfrac{-1}{6}\right)^3\)
\(=2:\dfrac{-1}{216}=2.\left(-216\right)=-432\)
Ta có : \(\left(\dfrac{-10}{3}\right)^5.\left(\dfrac{-6}{5}\right)^4=\dfrac{\left(-10\right)^5.\left(-6\right)^4}{3^5.5^4}=\dfrac{\left(-2\right)^5.\left(-2\right)^4.5^5.3^4}{3^5.5^4}=\dfrac{\left(-2\right)^9.5}{3}\)
a) \(\dfrac{16}{2^n}=2\Rightarrow2^n=\dfrac{16}{2}=8=2^3\)
\(\Rightarrow n=3\)
b) \(\dfrac{\left(-3\right)^n}{81}=-27\)
\(\Leftrightarrow\dfrac{\left(-3\right)^n}{3^4}=\left(-3\right)^3\)
\(\Leftrightarrow\left(-3\right)^n=-\left(3^4\cdot3^3\right)=\left(-3\right)^7\)
\(\Rightarrow n=7\)
c) \(8^n:2^n=4\)
\(\Leftrightarrow2^{3n}:2^n=2^2\)
\(\Leftrightarrow3n-n=2\)
\(\Leftrightarrow2n=2\Rightarrow n=1\)
a, \(\dfrac{16}{2^n}=2\Rightarrow2^n.2=16\Rightarrow2^{n+1}=2^4\Rightarrow n+1=4\Rightarrow n=3\). Vậy n=3.
b, \(\dfrac{\left(-3\right)^n}{81}=-27\Rightarrow\left(-3\right)^n=81.\left(-27\right)\Rightarrow\left(-3\right)^n=-2187\)
\(\Rightarrow\left(-3\right)^n=\left(-3\right)^7\Rightarrow n=7\)
Vậy n=7
c, \(8^n:2^n=4\Rightarrow\left(2^3\right)^n:2^n=2^2\Rightarrow2^{3n}:2^n=2^2\Rightarrow2^{2n}=2^2\Rightarrow2n=2\Rightarrow n=1\)
Vậy n=1.
a) \(\frac{16}{2^n}=2\)
\(\Rightarrow16=2\cdot2^n\)
\(\Rightarrow16=2^{n+1}\)
\(\Rightarrow2^4=2^{n+1}\)
\(\Rightarrow n+1=4\)
\(\Rightarrow n=4-1\)
\(\Rightarrow n=3\)
Vậy n=3
b) \(\frac{\left(-3\right)^n}{81}=-27\)
\(\Rightarrow\left(-3\right)^n=-27\cdot81\)
\(\Rightarrow\left(-3\right)^n=\left(-3\right)^3.\left(-3\right)^4\)
\(\Rightarrow\left(-3\right)^n=\left(-3\right)^7\)
\(\Rightarrow n=7\)
Vậy n=7
c ) \(8^n:2^n=4\)
\(\Rightarrow2^{3n}:2^n=2^2\)
\(\Rightarrow2^{2n}=2^2\)
\(\Rightarrow2n=2\)
\(\Rightarrow n=2:2\)
\(\Rightarrow n=1\)
Vậy n=1
d) \(\dfrac{2}{3}-\left[\left(\dfrac{-7}{4}\right)-\left(\dfrac{1}{2}+\dfrac{3}{8}\right)\right]\)
\(=\dfrac{2}{3}-\left[\left(\dfrac{-7}{4}\right)-\left(\dfrac{4}{8}+\dfrac{3}{8}\right)\right]\)
\(=\dfrac{2}{3}-\left[\left(\dfrac{-14}{8}-\dfrac{7}{8}\right)\right]=\dfrac{2}{3}-\left(\dfrac{-21}{8}\right)\)
\(=\dfrac{16}{24}+\dfrac{63}{24}=\dfrac{79}{24}\)
Hok tốt
\(8^n:2^n=4\)
\(\Rightarrow\left(8:2\right)^n=4\)
\(\Rightarrow4^n=4\)
\(\Rightarrow n=1\)
Vậy n = 1
Hình a)
Áp dụng định lí Pytago, Ta có:
x2 =122+5 = 144+25=169
=> 132=x2 => x=13.
Hình b) ta có:
x2= 12 + 22 = 1+4=5
x= √5
Hình c)
Theo định lí pytago:
292=212+x2
nên x2=292-212
= 841-441=400=202
=>x=20
Hình d)
x2=( √7)2+32=7+9=16=42
=>x=4.
(-10/3)5.(-6/5)4=-100000/243.1296/625=-853,(3)
K CHO MÌNH NHA CẢM ƠN
\(\left(\frac{-10}{3}\right)^5x\left(\frac{-6}{5}\right)^4\)
\(=\frac{-100000}{243}x\frac{1296}{625}\)
\(=\frac{-2560}{3}\)
Cố lên!!!