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Grey.nnvd (07) · Accepted Answer

`#3107.101107`a)$\dfrac{-22}{25}+\left(\dfrac{3}{7}-0,12\right)\
=\dfrac{-22}{25}+\dfrac{3}{7}-0,12\
=-\dfrac{79}{175}-0,12\
=-\dfrac{4}{7}$b)$\dfrac{3}{8}-\left(1,2-\dfrac{5}{8}\right)\
=\dfrac{3}{8}-1,2+\dfrac{5}{8}\
=\dfrac{8}{8}-1,2\
=1-1,2\
=-0,2$c)$\dfrac{4}{15}-\left(2,9-\dfrac{11}{15}\right)\
=\dfrac{4}{15}-2,9+\dfrac{11}{15}\=\dfrac{15}{15}-2,9\
=1-2,9\
=-1,9$d)$\dfrac{17}{11}-\left(\dfrac{6}{5}-\dfrac{16}{11}\right)+\dfrac{26}{5}\
=\dfrac{17}{11}-\dfrac{6}{5}+\dfrac{16}{11}+\dfrac{26}{5}\
=\left(\dfrac{17}{11}+\dfrac{16}{11}\right)+\left(-\dfrac{6}{5}+\dfrac{26}{5}\right)\
=\dfrac{33}{11}+\dfrac{20}{5}\
=3+4\
=7$e)$\dfrac{39}{5}+\left(\dfrac{9}{4}-\dfrac{9}{5}\right)-\left(\dfrac{5}{4}+\dfrac{6}{7}\right)\
=\dfrac{39}{5}+\dfrac{9}{4}-\dfrac{9}{5}-\dfrac{5}{4}-\dfrac{6}{7}\
=\left(\dfrac{39}{5}-\dfrac{9}{5}\right)+\left(\dfrac{9}{4}-\dfrac{5}{4}\right)-\dfrac{6}{7}\
=\dfrac{30}{5}+\dfrac{4}{4}-\dfrac{6}{7}\
=6+1-\dfrac{6}{7}\=\dfrac{43}{7}$Câu trả lời: `#3107.101107`a)$\dfrac{-22}{25}+\left(\dfrac{3}{7}-0,12\right)\
=\dfrac{-22}{25}+\dfrac{3}{7}-0,12\
=-\dfrac{79}{175}-0,12\
=-\dfrac{4}{7}$b)$\dfrac{3}{8}-\left(1,2-\dfrac{5}{8}\right)\
=\dfrac{3}{8}-1,2+\dfrac{5}{8}\
=\dfrac{8}{8}-1,2\
=1-1,2\
=-0,2$c)$\dfrac{4}{15}-\left(2,9-\dfrac{11}{15}\right)\
=\dfrac{4}{15}-2,9+\dfrac{11}{15}\=\dfrac{15}{15}-2,9\
=1-2,9\
=-1,9$d)$\dfrac{17}{11}-\left(\dfrac{6}{5}-\dfrac{16}{11}\right)+\dfrac{26}{5}\
=\dfrac{17}{11}-\dfrac{6}{5}+\dfrac{16}{11}+\dfrac{26}{5}\
=\left(\dfrac{17}{11}+\dfrac{16}{11}\right)+\left(-\dfrac{6}{5}+\dfrac{26}{5}\right)\
=\dfrac{33}{11}+\dfrac{20}{5}\
=3+4\
=7$e)$\dfrac{39}{5}+\left(\dfrac{9}{4}-\dfrac{9}{5}\right)-\left(\dfrac{5}{4}+\dfrac{6}{7}\right)\
=\dfrac{39}{5}+\dfrac{9}{4}-\dfrac{9}{5}-\dfrac{5}{4}-\dfrac{6}{7}\
=\left(\dfrac{39}{5}-\dfrac{9}{5}\right)+\left(\dfrac{9}{4}-\dfrac{5}{4}\right)-\dfrac{6}{7}\
=\dfrac{30}{5}+\dfrac{4}{4}-\dfrac{6}{7}\
=6+1-\dfrac{6}{7}\=\dfrac{43}{7}$

Grey.nnvd (07) · Answer

Sửa lại giúp mình câu a) một chút:$\dfrac{-22}{25}+\left(\dfrac{3}{7}-0,12\right)\
=\dfrac{-22}{25}+\dfrac{3}{7}-0,12\
=\dfrac{-22}{25}+\dfrac{3}{7}-\dfrac{3}{25}\
=\dfrac{-25}{25}+\dfrac{3}{7}\
=-1+\dfrac{3}{7}\
=-\dfrac{4}{7}$Câu trả lời: Sửa lại giúp mình câu a) một chút:$\dfrac{-22}{25}+\left(\dfrac{3}{7}-0,12\right)\
=\dfrac{-22}{25}+\dfrac{3}{7}-0,12\
=\dfrac{-22}{25}+\dfrac{3}{7}-\dfrac{3}{25}\
=\dfrac{-25}{25}+\dfrac{3}{7}\
=-1+\dfrac{3}{7}\
=-\dfrac{4}{7}$

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