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a) \(x+\dfrac{4}{5}=\dfrac{45}{5}-\left(\dfrac{3}{7}+\dfrac{3}{5}\right)\)
\(x+\dfrac{4}{5}=\dfrac{45}{5}-\dfrac{36}{35}\)
\(x+\dfrac{4}{5}=\dfrac{279}{35}\)
\(x=\dfrac{279}{35}-\dfrac{4}{5}\)
\(x=\dfrac{251}{35}\)
b) \(\dfrac{5}{8}\times x=\dfrac{4}{5}\)
\(x=\dfrac{4}{5}\div\dfrac{5}{8}\)
\(x=\dfrac{32}{25}\)
Câu 1: D
Câu 2: Các phân số tối giản là \(\dfrac{1}{9};\dfrac{2}{11}\)
Câu 3: Phân số lớn nhất là \(\dfrac{17}{3}\)
Câu 4:
\(76m^28cm^2=760008cm^2\)
Câu 5:
Gọi số cần tìm là x
Theo đề, ta có: \(\dfrac{4}{7}=\dfrac{x}{21}\)
=>\(x=4\cdot\dfrac{21}{7}=4\cdot3=12\)
a) =\(\dfrac{21}{35}+\dfrac{10}{35}+\dfrac{4}{35}=\dfrac{21+10+4}{35}=\dfrac{35}{35}=1\)
b) =\(\dfrac{16}{24}+\dfrac{15}{24}-\dfrac{12}{24}=\dfrac{19}{24}\)
c) =\(\dfrac{35}{40}+\dfrac{80}{40}-\dfrac{24}{40}+\dfrac{120}{40}=\dfrac{35+80-24+120}{40}=\dfrac{211}{40}\)
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Bài 1:
a: =2/3+7/5=10/15+21/15=31/15
b: =3/4+1/8=6/8+1/8=7/8
c: =225/25+7/25=232/25
d: =5/8+8=64/8+5/8=69/8
a)
5/6+3/6= 8/6 = 4/3
b)
6/36= 1/6
LÀ SAO